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• Date calculation

Date calculation

Community Beginner ,
Jul 14, 2021 Jul 14, 2021

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I have a form in acrobat where the user can input a start and an end date which should result in a third text field displaying the days between those two dates.

My question is if there is a way to calculate the amount days between minus weekends and holidays or other specific dates.

Also is there a method outside of using the javascript validation as it seems impractical for this.

Any and all help is appreciated 🙂

TOPICS
How to, JavaScript, PDF forms

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2 Replies 2
Jul 14, 2021 Jul 14, 2021

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It's possible, but only with JavaScript.

In fact, I created a (paid-for) tool that does exactly that, if you don't want to write the code yourself:

https://www.try67.com/tool/acrobat-apply-automatic-date-calculation

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Community Beginner ,
Jul 15, 2021 Jul 15, 2021

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LATEST

I already have a working JavaScript method which only works outside of acrobat.

I also tried changing the input values to acrobat form fields and it still doesn't work.

If you have any advice on this lmk.

``````var StartDate = window.prompt("Start Date: ");
StartDate = parseInt(StartDate);
var EndDate = window.prompt("End Date: ");
EndDate = parseInt(EndDate);
//User input for Start & End Date as integer
//Day 1 representing the first day of the year

var DaysBetween = [];
for (var i = StartDate; i <= EndDate; i++) {
DaysBetween.push(i);
}
//Puts all days between, including start and end day into array

var Saturday = 6;
var Sunday = 7;
//Change value to the first weekend of the year

var Holiday = [
14,
15,
16
];
//Contains the date of every holiday

var Holidays = 0;
Holiday.forEach((entry) => {
if (entry >= StartDate & entry <= EndDate) {
Holidays++;
}
});
//Checks each holiday if its between start and end date

console.log(Holidays);

var Saturdays = 0;
DaysBetween.forEach((entry) => {
if (entry % Saturday == 0) {
Saturdays++;
}
});
console.log(Saturdays);

var Sundays = 0;
DaysBetween.forEach((entry) => {
if (entry % Sunday == 0) {
Sundays++;
}
});
console.log(Sundays);

var DaysAbsent = 0;
DaysAbsent = DaysBetween.length - Holidays - Saturdays - Sundays;

console.log(DaysAbsent);``````

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