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Fields not hidden upon return/change of answer on Java Window.

New Here ,
Aug 08, 2018 Aug 08, 2018

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I have created a Javascript Window attached to a Radio button where upon selecting Yes, some text fields populate and upon selecting No, the fields are hidden. I realize that if yes was selected by mistake, the fields still remain visible when you return to the window and click no. What can I do to make the script work where you can return to change selection and it remove and hide the fields consistently?

Here this my script,

//Message for the popup window//

cMsg = "Do you want to deactivate the incumbent's previous position for this Job Change?\n"

var nRtn = app.alert(cMsg,2,2,"Deactivate Previous Position");

// field that populate upon selecting the option Yes//

if(nRtn == 4)

this.getField("LayerButton7").display = display.visible;

if(nRtn == 4)

this.getField("Text16").display = display.visible;

//Fields are hidden upon selecting No//

elseif(nRtn == 3)

this.getField("LayerButton7").display = display.hidden;

elseif(nRtn == 3)

this.getField("Text16").display = display.hidden;

TOPICS
Acrobat SDK and JavaScript

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correct answers 1 Correct answer

Community Expert , Aug 08, 2018 Aug 08, 2018

Your code is incorrect, both in syntax and in logic.

You need to do it like this:

var cMsg = "Do you want to deactivate the incumbent's previous position for this Job Change?\n"

var nRtn = app.alert(cMsg,2,2,"Deactivate Previous Position");

if (nRtn == 4) {

    this.getField("LayerButton7").display = display.visible;

    this.getField("Text16").display = display.visible;

} else if (nRtn == 3) {

    this.getField("LayerButton7").display = display.hidden;

    this.getField("Text16").display = display.hidde

...

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Community Expert ,
Aug 08, 2018 Aug 08, 2018

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Your code is incorrect, both in syntax and in logic.

You need to do it like this:

var cMsg = "Do you want to deactivate the incumbent's previous position for this Job Change?\n"

var nRtn = app.alert(cMsg,2,2,"Deactivate Previous Position");

if (nRtn == 4) {

    this.getField("LayerButton7").display = display.visible;

    this.getField("Text16").display = display.visible;

} else if (nRtn == 3) {

    this.getField("LayerButton7").display = display.hidden;

    this.getField("Text16").display = display.hidden;

}

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New Here ,
Aug 08, 2018 Aug 08, 2018

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Oh I see. The code I provided is working at it should except for the return. But this Worked Like Magic!!!!!

Thank you! I need to learn more about how to properly code.

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Community Expert ,
Aug 08, 2018 Aug 08, 2018

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LATEST

The code you submitted should throw an exception when you enter it, as "elseif" is invalid.

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