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If an input field is != null display a integer in the output

New Here ,
Dec 05, 2018 Dec 05, 2018

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Hi Everyone

I want my program to detect if a field has an entry and if it has an entry set the output field to a value. Currently the program gets stuck on the if statement.

The following code is in custom calculation script. Running on Adobe Acrobat Pro 2017. Also if there is a easier way to do this please let me know, thanks in advance.

var nameOne = this.getField("Name1").valueAsString;

var nameTwo = this.getField("Name2").valueAsString;

var nameThree = this.getField("Name3").valueAsString;

var nameFour = this.getField("Name4").valueAsString;

var nameFive = this.getField("Name5").valueAsString;

if( nameOne != "null"){

    event.value=1;

}

else if(nameOne && nameTwo != "null"){

event.value= 2;

}

else if(nameOne && nameTwo && nameThree != "null"){

event.value= 3;

}

else if(nameOne && nameTwo && nameThree && nameFour != "null"){

event.value= 4;

}

else if(nameOne && nameTwo && nameThree && nameFour && nameFive != "null"){

event.value= 5;

}

TOPICS
Acrobat SDK and JavaScript , Windows

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correct answers 1 Correct answer

Community Expert , Dec 05, 2018 Dec 05, 2018

You should add something like this at the end of the code:

else event.value = "";

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Community Expert ,
Dec 05, 2018 Dec 05, 2018

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The valueAsString property can't return null, only strings. Replace all instances of "null" in your code with "", therefore.

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New Here ,
Dec 05, 2018 Dec 05, 2018

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Thanks for the reply. I have changed the code to as shown; however, is still returns 1

if( nameOne != ""){

    event.value=1;

}

else if(nameOne && nameTwo != ""){

event.value= 2;

}

else if(nameOne && nameTwo && nameThree != ""){

event.value= 3;

}

else if(nameOne && nameTwo && nameThree && nameFour.value != ""){

event.value= 4;

}

else if(nameOne && nameTwo && nameThree && nameFour && nameFive != ""){

event.value= 5;

}

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Community Expert ,
Dec 05, 2018 Dec 05, 2018

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You should add something like this at the end of the code:

else event.value = "";

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New Here ,
Dec 05, 2018 Dec 05, 2018

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I changed my logic around  because it was getting stuck on the if because the if was always true because the form always has the name1 entered then name2 ect,.

var nameOne = this.getField("Name1").valueAsString;

var nameTwo = this.getField("Name2").valueAsString;

var nameThree = this.getField("Name3").valueAsString;

var nameFour = this.getField("Name4").valueAsString;

var nameFive = this.getField("Name5").valueAsString;

if( nameOne && nameTwo && nameThree && nameFour && nameFive != ""){

    event.value=5;

}

else if(nameOne && nameTwo && nameThree && nameFour != ""){

event.value= 4;

}

else if(nameOne && nameTwo && nameThree){

event.value= 3;

}

else if(nameOne && nameTwo != ""){

event.value= 2;

}

else if(nameOne!= ""){

event.value= 1;

}

else(event.value = " ");

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Community Expert ,
Dec 06, 2018 Dec 06, 2018

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You must use:

if( nameOne != "" && nameTwo != "" && nameThree != "" && nameFour != "" && nameFive != ""){

    event.value=5;

...

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New Here ,
Dec 06, 2018 Dec 06, 2018

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Thanks Bernd, I could reverse the change i made

var nameOne = this.getField("Name1").valueAsString;

var nameTwo = this.getField("Name2").valueAsString;

var nameThree = this.getField("Name3").valueAsString;

var nameFour = this.getField("Name4").valueAsString;

var nameFive = this.getField("Name5").valueAsString;

// determine if a string has been entered

if( nameOne!= "" && nameTwo!= "" && nameThree!= "" && nameFour!= "" && nameFive != ""){

    event.value=5;

}

else if(nameOne!= "" && nameTwo!= "" && nameThree!= "" && nameFour != ""){

event.value= 4;

}

else if(nameOne!= "" && nameTwo!= "" && nameThree!= ""){

event.value= 3;

}

else if(nameOne!= "" && nameTwo != ""){

event.value= 2;

}

else if(nameOne!= ""){

event.value= 1;

}

else(event.value = " ");

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