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- After effects Sum Numbers & expressions

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/t5/after-effects-discussions/after-effects-sum-numbers-expressions/td-p/8806239
Feb 05, 2017
Feb 05, 2017

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Goodmorning guys and to all forum!

I would like to ask a question...I would like to build a project which I will change two numbers and all of the following take place automatically! Explain...

Part 1:

I have to layers, Number 1 and Number 2. Suppose I put to the No1 the value 15 and to the No2 the value 5. Automatically i want to a new layer sum this numbers (20) like the photo.

Part 2:

Next, I would like to built a chart below take the prices automatically according to the numbers that I gave. Explain...

From the above sum, i want the layer with the value 20 understands automatically that is the 100%. So to the chart the shapes changes automatically and understands that for the No1 with the value 15 is the 75% (15*100/20) and for the No2 with the value 5 is the 25% (5*100/20).

Probably i need for the value of the mumbers a Solid with Numbers effect and not a text? And if someone knows the expressions...

Sorry for my english, is not very well

Thank you all - Σας ευχαριστώ όλους (in Greek)

friendly John K.

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LEGEND
,
Feb 06, 2017
Feb 06, 2017

In your code the reference merely points to the layer name. A correct notation would be

thisComp.layer("A").text.sourceText

Mylenium

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/t5/after-effects-discussions/after-effects-sum-numbers-expressions/m-p/8806240#M18173
Feb 05, 2017
Feb 05, 2017

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No requirement for any Numbers effect. Native text layers can happily accept all kinds of expressions in their source Text property and in case of an addition, it works just like in the real world: a+b=c. Conversely, converting to percentages would be merely another division and multiplication, though yopu would wire it through a linear() interpolator. Therefore you get:

a=15;

b=5;

c=a+b;

percent_a=linear(a,0,c,0,100);

percent_a=linear(b,0,c,0,100);

The same formulas could then be applied to the scale of a rectangle or a linear wipe effect to control the length of your bars. You really don't need much more than this trivial stuff. Of course you may want to link the inputs to sliders or the actual input text layers for easy changes.

Mylenium

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/t5/after-effects-discussions/after-effects-sum-numbers-expressions/m-p/8806241#M18174
Feb 05, 2017
Feb 05, 2017

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...however, I reecommend that you avoid LARGE numbers. You would soon run out of room on the screen.

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Cameraman84
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/t5/after-effects-discussions/after-effects-sum-numbers-expressions/m-p/8806242#M18175
Feb 06, 2017
Feb 06, 2017

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/t5/after-effects-discussions/after-effects-sum-numbers-expressions/m-p/8806243#M18176
Feb 06, 2017
Feb 06, 2017

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In your code the reference merely points to the layer name. A correct notation would be

thisComp.layer("A").text.sourceText

Mylenium

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Cameraman84
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/t5/after-effects-discussions/after-effects-sum-numbers-expressions/m-p/8806244#M18177
Feb 06, 2017
Feb 06, 2017

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Sorry for the inconvenience again, but joins me numbers, no adds them...

Thanks you again for your time my friend!

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/t5/after-effects-discussions/after-effects-sum-numbers-expressions/m-p/8806245#M18178
Feb 06, 2017
Feb 06, 2017

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Yeah, sorry. AE treats them as strings. You neet to convert them to numbers again:

parseInt(thisComp.layer("A").text.sourceText)

Mylenium

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Cameraman84
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/t5/after-effects-discussions/after-effects-sum-numbers-expressions/m-p/8806246#M18179
Feb 06, 2017
Feb 06, 2017

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You are Master, Faster, Sweet Disaster!

Thanks my friend! You are welcome!

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/t5/after-effects-discussions/after-effects-sum-numbers-expressions/m-p/14459430#M244859
Mar 01, 2024
Mar 01, 2024

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Hi Hello.

Good morning. So I am trying to get 3 different source text layers to come to a total number and I am not able to figure this one out so far.

This is the expression I wrote:

var currentAmmount = parseInt(thisComp.layer("Drink 1 - Sum").text.sourceText + thisComp.layer("Drink 2 - Sum").text.sourceText + thisComp.layer("Drink 3 - Sum").text.sourceText);

'$' + currentAmmount.toLocaleString();

The result is $ NaN .... ????

Thank you for any helping voice out there

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/t5/after-effects-discussions/after-effects-sum-numbers-expressions/m-p/14459476#M244860
Mar 01, 2024
Mar 01, 2024

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For me your expression doesn't return NaN but the concatenation of values

try this expresion:

```
var currentAmmount =
parseInt(thisComp.layer("Drink 1 - Sum").text.sourceText) +
parseInt(thisComp.layer("Drink 2 - Sum").text.sourceText) +
parseInt(thisComp.layer("Drink 3 - Sum").text.sourceText);
'$' + currentAmmount.toLocaleString();
```

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/t5/after-effects-discussions/after-effects-sum-numbers-expressions/m-p/14459812#M244869
Mar 01, 2024
Mar 01, 2024

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Gotcha! That makes a lot of sense. Sorry I am a total newbie at this stuff

🙂

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/t5/after-effects-discussions/after-effects-sum-numbers-expressions/m-p/14459840#M244870
Mar 01, 2024
Mar 01, 2024

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I guess I jumped the gun. I thought it would work but the source for each "drink" is not a number but a function with a sum of data relating to a series of days... I tried your expression and it still doesn't work. What's NaN?

Thank you

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Engaged
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LATEST
/t5/after-effects-discussions/after-effects-sum-numbers-expressions/m-p/14459895#M244871
Mar 01, 2024
Mar 01, 2024

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You need to use parseInt() :

```
parseInt(thisComp.layer("data.json")("Data")("Outline")(drink)("Sunday")) +
parseInt(thisComp.layer("data.json")("Data")("Outline")(drink)("Monday")) +
// and so on...
```

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