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How to create a counting number but starting with Zeros

New Here ,
Sep 25, 2019 Sep 25, 2019

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Hello

I want to create a counting number with 6 decimals. I want to get the number 934 896, but I want to start with all decimals in zero like this: 000 000.

I wrote this expression:

t += "";
t.replace(/(\d)(?=(\d\d\d)+(?!\d))/g, "\$1 ");

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Advocate , Sep 26, 2019 Sep 26, 2019

Here is a robust way to do what you are looking for. The method of adding extra characters on left or right of the string is called padding. So here's a function that converts your number into a string and pads it to a given length of 6 characters. In case you need more '0' characters at the start, simply change number 6 to some other value.

Cheers.

``````function padStart(string, targetLength, character) {
// Convert 'string' into a string primitive
string = (string instanceof String) ? string ``````
...

6 Replies 6
Community Expert ,
Sep 25, 2019 Sep 25, 2019

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Try this:

n = 6 - t.toString().length;
"00000".substr(0,n) + t

Dan

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New Here ,
Sep 27, 2019 Sep 27, 2019

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Hi Dan!

Your answer really helped me, although I need a space in the middle of the number like this: 000 000

With your expression I got this: 000000

I tried to mix your expression with mine, but it didn't work.

Could you help me with this issue?

Thanks a lot!

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Sep 27, 2019 Sep 27, 2019

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Here's how you do it: split the string into an array of N size items (chunks) and join the result with a separator. Simply change stringchunkSize and separator variables to your needs.

Given a string 123456789 with a chunkSize of value 3 and a separator as - the result would be 123-456-789

``````function splitStringIntoChunks(string, chunkSize) {
var chunks, pattern;

// Convert 'string' into a string primitive
string = (string instanceof String) ? string : string.toString();

// Floor the size
chunkSize = Math.floor(chunkSize);

// Build RegExp pattern
pattern = new RegExp('.{0,' + chunkSize + '}', 'g');

// Get array of matches
chunks = string.match(pattern);

return chunks;
}

var string = 123456789;
var chunkSize = 3;
var separator = ' ';

var chunks = splitStringIntoChunks(string, chunkSize);
var result = chunks.join(separator);

result;``````

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Sep 26, 2019 Sep 26, 2019

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Here is a robust way to do what you are looking for. The method of adding extra characters on left or right of the string is called padding. So here's a function that converts your number into a string and pads it to a given length of 6 characters. In case you need more '0' characters at the start, simply change number 6 to some other value.

Cheers.

``````function padStart(string, targetLength, character) {
// Convert 'string' into a string primitive
string = (string instanceof String) ? string : string.toString();

// floor if number, or convert non-number to 0;
targetLength = targetLength >> 0;

character = character || ' ';

while (string.length < targetLength) {
string = character + string;
}

return string;
};

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New Here ,
Sep 29, 2020 Sep 29, 2020

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Hi! Thank's for this!

I have a problem with decimals though, I don't want them. How do I get rid of them?

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New Here ,
Sep 27, 2021 Sep 27, 2021

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LATEST

Hi Tomas - was hoping you might be able to help me with a similar issue? I am trying to add a 0 just for the counting numbers 1-9 then continue normally. For example 00,01,02,03,04...10,11,12, etc. Any thoughts? Please see my post here: https://community.adobe.com/t5/after-effects-discussions/how-to-create-counting-numbers-keeping-zero...