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How to do loopIn("cycle",3) on PATH ANIMATION?

Explorer ,
May 24, 2024 May 24, 2024

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I have a kind of unique situation, where I have an animation on a path, and I want to loopIn the first three keyframes, and then have more animations on that path afterwards that don't get repeated. (In case that didn't make sense, I'll explain the situation being animated. I bring a character on the screen, and she's waving hi. Afterwards, she puts her arm down. I'd like the part where she's waving back and forth to be looped in, but not the part where she puts her arm down.)

 

I've seen in various places on the web that there are existing expressions for a plain "loopOut" expression for paths (such as here), but I haven't seen any that are "loopIn." And I also haven't found any loopOut expressions that will limit the loop to some of the keyframes.

 

So, to sum up, what I'd like help with is an expression that would be equivalent to

 

loopIn("cycle", [INSERT NUM KEYS]);

 

that would work on path animations. And while you're at it, it would be awesome if you could write an equivalent expression for loopOut that also includes the [INSERT NUM KEYS] part.

 

Thanks in advance!

TOPICS
Expressions , How to , Scripting

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correct answers 2 Correct answers

Community Expert , May 24, 2024 May 24, 2024

I think this will work. It could use some additional code to make sure there are at least nKeys keyframes, but this is the basic method:

nKeys = 3;
if (time > key(1).time){
  value;
}else{
  d = key(nKeys).time - key(1).time;
  t = (key(1).time - time)%d;
  valueAtTime(key(nKeys).time - t)
}

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Community Expert , May 24, 2024 May 24, 2024

Here's the loopOut("cycle",nKeys) version:

nKeys = 3;
if (time < key(numKeys).time){
  value;
}else{
  t1 = key(numKeys-nKeys+1).time;
  d = key(numKeys).time - t1;
  t = (time - key(numKeys).time)%d;
  valueAtTime(t1 + t)
}

 

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Community Expert ,
May 24, 2024 May 24, 2024

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I think this will work. It could use some additional code to make sure there are at least nKeys keyframes, but this is the basic method:

nKeys = 3;
if (time > key(1).time){
  value;
}else{
  d = key(nKeys).time - key(1).time;
  t = (key(1).time - time)%d;
  valueAtTime(key(nKeys).time - t)
}

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Explorer ,
May 24, 2024 May 24, 2024

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Thanks Dan! You're the best, as always! Works like a charm. I'll just make sure I only use this expression if I have more than nKeys number of keyframes already put in.

 

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Community Expert ,
May 24, 2024 May 24, 2024

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Here's the loopOut("cycle",nKeys) version:

nKeys = 3;
if (time < key(numKeys).time){
  value;
}else{
  t1 = key(numKeys-nKeys+1).time;
  d = key(numKeys).time - t1;
  t = (time - key(numKeys).time)%d;
  valueAtTime(t1 + t)
}

 

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Explorer ,
May 26, 2024 May 26, 2024

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Works great! Thanks again Dan.

 

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