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Button

Participant ,
Aug 20, 2020 Aug 20, 2020

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In my slide show I have HTML5 canvas and there I have a button that changes an image but when you press the button
then nothing happens on the first press but the second press so it happens the image is displayed.
I want it to happen on the first print.
Here is the code:
this.button.addEventListener("click", Toggle3.bind(this));
var on = 0;
this.nr60b_btn.visible = false;
this.nr60a_btn.visible = false;
function Toggle3() {
if (on == 0) {
this.nr60b_btn.visible = true;
this.nr60a_btn.visible = true;
this.stop();
on = 1;
} else {
this.nr60b_btn.visible = false;
this.nr60a_btn.visible = false;
on = 0;
}
}

TOPICS
How to , Other , Performance

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correct answers 1 Correct answer

Community Expert , Aug 20, 2020 Aug 20, 2020

Hi.

 

It think this is a great opportunity to use the logical NOT (!) operator.

 

this.button.addEventListener("click", Toggle3.bind(this));
this.nr60b_btn.visible = false;
this.nr60a_btn.visible = false;

function Toggle3()
{
	this.nr60b_btn.visible = !this.nr60b_btn.visible;
	this.nr60a_btn.visible = !this.nr60a_btn.visible;
	
	if (this.nr60b_btn.visible)
		this.stop();
}

 

 

Please let us know.

 

Regards,

JC

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Community Expert ,
Aug 20, 2020 Aug 20, 2020

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Hi.

 

It think this is a great opportunity to use the logical NOT (!) operator.

 

this.button.addEventListener("click", Toggle3.bind(this));
this.nr60b_btn.visible = false;
this.nr60a_btn.visible = false;

function Toggle3()
{
	this.nr60b_btn.visible = !this.nr60b_btn.visible;
	this.nr60a_btn.visible = !this.nr60a_btn.visible;
	
	if (this.nr60b_btn.visible)
		this.stop();
}

 

 

Please let us know.

 

Regards,

JC

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Participant ,
Aug 20, 2020 Aug 20, 2020

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Thank you so much for the help because this works with the code you gave works at once when I press the button instead of the second time with the previous code I had.

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