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getting symbol from the library folder… jsfl

Community Beginner ,
Mar 27, 2020

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I am looking for some MC I can set by "prompt" window, find it and doing some edits, but my script works only when MC which I am looking for is located in the root of the library without folder. Need some advice on how I can get an element (symbol) from the folder in the library

 

var result = prompt("Enter the name of MC:");
var CurrentFlaFile = an.getDocumentDOM();
var itemsArr = CurrentFlaFile.library.items;
for(var ArreysElement=0; ArreysElement<itemsArr.length; ArreysElement++){
var checkingElement = itemsArr[ArreysElement];
if(checkingElement.itemType=="movie clip" && checkingElement.name == result){
CurrentFlaFile.library.addItemToDocument({x:0, y:0}, result);
CurrentFlaFile.enterEditMode('inPlace');
CurrentFlaFile.getTimeline().addNewLayer("my_layer_ADDED");
CurrentFlaFile.exitEditMode();
CurrentFlaFile.deleteSelection();
an.trace(an.getDocumentDOM().library.items[ArreysElement].name);
}
}

Adobe Community Professional
Correct answer by ClayUUID | Adobe Community Professional

The folder path is just part of the name. The JSFL documentation has numerous examples of this in the library object section.

 

And you don't need to loop through the library to find an item name. That's what findItemIndex() is for.

 

Having users specify a movieclip by name and searching in all folders is a bad idea though, because folders allow you to have multiple movieclips with the same name.

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Code, How to, Missing feature, Other

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getting symbol from the library folder… jsfl

Community Beginner ,
Mar 27, 2020

Copy link to clipboard

Copied

I am looking for some MC I can set by "prompt" window, find it and doing some edits, but my script works only when MC which I am looking for is located in the root of the library without folder. Need some advice on how I can get an element (symbol) from the folder in the library

 

var result = prompt("Enter the name of MC:");
var CurrentFlaFile = an.getDocumentDOM();
var itemsArr = CurrentFlaFile.library.items;
for(var ArreysElement=0; ArreysElement<itemsArr.length; ArreysElement++){
var checkingElement = itemsArr[ArreysElement];
if(checkingElement.itemType=="movie clip" && checkingElement.name == result){
CurrentFlaFile.library.addItemToDocument({x:0, y:0}, result);
CurrentFlaFile.enterEditMode('inPlace');
CurrentFlaFile.getTimeline().addNewLayer("my_layer_ADDED");
CurrentFlaFile.exitEditMode();
CurrentFlaFile.deleteSelection();
an.trace(an.getDocumentDOM().library.items[ArreysElement].name);
}
}

Adobe Community Professional
Correct answer by ClayUUID | Adobe Community Professional

The folder path is just part of the name. The JSFL documentation has numerous examples of this in the library object section.

 

And you don't need to loop through the library to find an item name. That's what findItemIndex() is for.

 

Having users specify a movieclip by name and searching in all folders is a bad idea though, because folders allow you to have multiple movieclips with the same name.

TOPICS
Code, How to, Missing feature, Other

Views

236

Likes

Translate

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Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
Mar 27, 2020 0
Adobe Community Professional ,
Mar 27, 2020

Copy link to clipboard

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The folder path is just part of the name. The JSFL documentation has numerous examples of this in the library object section.

 

And you don't need to loop through the library to find an item name. That's what findItemIndex() is for.

 

Having users specify a movieclip by name and searching in all folders is a bad idea though, because folders allow you to have multiple movieclips with the same name.

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Translate

Translate

Report

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Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
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