How to find path?

[Guest]

From this path...
srv01/iplant/home/apps/dir.txt


<cfset path = 'srv01/iplant/home/apps/dir.txt'

i want to find filename and path....

<cfset filename = listlast(path,'/')>
filename : <cfoutput>#filename#</cfoutput><br />



How will i find filepath?
filepath = srv01/iplant/home/apps/

[davidsimms]

1. Treat srv01/iplant/home/apps/dir.txt as slash-delimited list.
2. Remove the last element in that list.

[Guest]

we got a list function to remove an element in list?

[Guest]

Path always changes...

so i want to remove filename in path...

how can i do?

filepath = path - filename

[Newsgroup_User]

Amm85 wrote:
> we got a list function to remove an element in list?

Yes, check out listrest().

But in reality, I would use the ever so handy getDirectoryFromPath()
function.

I.E.
<cfoutput>#getDirectoryFromPath(getCurrentTemplatePath())#</cfoutput> is
a pretty useful construct.

[Guest]

Thanks Ian,

i want last element removed...
ListRest

Description

Gets a list, without its first element.

[Guest]

I getting this path from a text file...
then parsing this path to find
filename and filepath.

so i can't use getDirectoryFromPath

[Newsgroup_User]

Amm85 wrote:
> Thanks Ian,
>
> i want last element removed...
> ListRest
>
> Description
>
> Gets a list, without its first element.
>

Not uncommon and fairly easy to flip an list.

[Newsgroup_User]

Amm85 wrote:
> I getting this path from a text file...
> then parsing this path to find
> filename and filepath.
>
> so i can't use getDirectoryFromPath

Why not? Is it not a path? If it is a path, I would expect
getDirectoryFromPath() to remove the file from the end and return the
rest of the list. Probably using the above mentioned listRest()
function internally.

[Newsgroup_User]

<cfset fullpath = "srv01/iplant/home/apps/dir.txt">
<cfoutput>
file: #getfilefrompath(fullpath)#<br />
dir: #getdirectoryfrompath(fullpath)#
</cfoutput>


Azadi Saryev
Sabai-dee.com
http://www.sabai-dee.com/