Query

[Anhialator]

Hello. How do I write the query for:

SELECT * FROM shirt;
+----+---------+--------+-------+
| id | name | num1| num2 |
+----+---------+--------+-------+
| 1 | nancy | 2 | 2 |
| 1 | bill | 1 | 4 |
| 2 | nancy | 3 | 16 |
| 2| bill | 7 | 2 |
| 2| steve | 7 | 6 |
| 3 | pam |8 | 7 |
| 3 | nancy | 1 | 8 |
| 3 | bill | 2 | 7 |
+----+---------+--------+-------+

Which will return this:

+----+---------+--------+-------+
| count | name | num1| num2 |
+----+---------+--------+-------+
| 3 | nancy | 6 | 26 |
| 3 | bill | 10 | 13 |
| 1 | steve | 7 | 6 |
| 1| pam | 8 | 7 |
+----+---------+--------+-------+

Primary Key (ID, unique)

I don't know if I've written everything correctly. I need to count the occurrance of ID for each Name and then show the sum of the values in Num1 and Num2 for each name.

Can anyone help me?

Thank you so much.

[Newsgroup_User]

.oO(Anhialator)

> I don't know if I've written everything correctly. I need to count the
>occurrance of ID for each Name and then show the sum of the values in Num1 and
>Num2 for each name.

Try

SELECT
COUNT(*) AS count,
name,
SUM(num1) AS num1,
SUM(num2) AS num2
FROM shirt
GROUP BY name

Micha

[Anhialator]

Micha! THANK YOU! It worked! I'm soooooooooo happy! You're brilliant, and you make it look so easy, which for you, it was, I'm sure!
Thank you!

[Newsgroup_User]

.oO(Anhialator)

>Thank you!

You're welcome.

Micha