trouble echoing image

[future-architect]

I always get confused using " and '.  here is my code, where i am trying to echo out an image:

echo "<td>". if($attachment==1) { echo"<img src='http://mysite.com/images/attachment.png' width='20' height='20' />"; } ."</td>";

How do i rewrite this so I no longer get an error?

[bregent]

The code looks completely wrong to me. You're concatenating an IF statement that contains an echo within another echo construnct. I'm not very good with PHP syntax, but try:

echo "<td>";

if($attachment==1) {

     echo "<img src='http://example.com/images/attachment.png' width='20' height='20' />" };

echo "</td>";

[future-architect]

close

if($attachment == 1) {

    echo "<img src=

'http://example.com/images/attachment.png

' width='20' height='20' />" ;

}

echo "</td>";

thanks though!

[bregent]

Ah yes, I am always misplacing my semi colons.