Start numbering but not at 1

Report · Aug 05, 2011

Hi there,

I'm try to figure out how to make a numbering like this:

1.

2.

3.

A.

4.

5.

6.

B.

4.

5.

6.

How can I tell my numbering to start at specific number, in this case a 4.? Any ideas?

Thanks.

Greetings.

Report · Aug 05, 2011

In your example, the numbered list doesn't actually start at 4, it just continues after a differently numbered item.

In the document structure, you should have some way to tell which items belong to the 1,2,3 sequence and which items belong to the A,B,C sequence. In the same way, EDD formatting rules can apply the correct format. To keep the items apart, you could use different elements for the items, or an attribute.

For the paragraph autonumber format, you'd have to use two different sequences, for example:

1,2,3 sequence: N:<N=1> for the first item and N:<n+> for all others

A,B,C sequence: A:<A=1> for the first item and A:<A+> for all others

Johannes

Report · Aug 05, 2011

Hi Johannes,

but how do I tell FrameMaker to continue the numbering serveral times. When I have something like in my example FrameMaker continues with a 4. after the A. but not start continue with 4. after the B. It keeps counting so that it continues with a 7. after the B.

Greetings.

Report · Aug 05, 2011

Dokuteam1 wrote:

When I have something like in my example FrameMaker continues with a 4. after the A. but not start continue with 4. after the B. It keeps counting so that it continues with a 7. after the B.

You'll have to include series labels, as in my example above. I've chosen "A" as the series label for A,B,C,... and "N" as the series label for 1,2,3,...

See also http://help.adobe.com/en_US/FrameMaker/9.0/Using/WSF176D8C8-8133-4860-88E3-AF69262623F0.html

Johannes

Report · Aug 05, 2011

It's not clear from the information you've provided whether the items listed under "A" correspond to those listed under "B". Is it coincidental that both blocks contain list items 4, 5, and 6 or is it the nature of the document that the number of items is the same?

If the numbers must match, you can use autonumbers in the first block and cross-references in all others. For example, suppose you use the same autonumber sequence, say L, for both the numbers and letters, using the first counter level for letters and the second for numbers. You could then assign autonumbers to elements as indicated below:

1. (autonumber L:< ><n=1>)

2. (autonumber L:< ><n+>)

3. (autonumber L:< ><n+>)

A (autonumber L:<A+>< >)

4. (autonumber L:< ><n+>)

5. (autonumber L:< ><n+>)

6. (autonumber L:< ><n+>)

B (autonumber L:<A+>< >)

4. (cross-reference to A4)

5. (cross-reference to A5)

6. (cross-reference to A6)

However, if the number of items in the two blocks is independent, you'd like to start the same way but set the last three items with something like the following instead:

4. (autonumber L:< ><n=4>)

5. (autonumber L:< ><n+>)

6. (autonumber L:< ><n+>)

The problem is that an EDD can use a particular number in a building block (like <n=4>), but the starting value must be hard-coded. Thus, it can set <n=4>, but it can't set n to the value used in a selected item. It can't even set it to an attribute value. You could consider a script or FDK client that would set it the way you want.

--Lynne

Report · Aug 05, 2011

Thanks Johannes,

it is like you suggested in the last block of your answer. The numbering shouldn't be hardcoded. The first listitem in B should have the same value as the first list item in A.

But now I know at least that it won't work like this and I can spent my time figure out how a can change my documentstructure so it works out without.

Greetings.