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- Drawing arcs with ESTK ...

Advocate
,

Dec 27, 2018

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Dear friends,

Next step after lines and polylines: I want to draw arcs (with a constant radius) and encounter a similar problem as with the lines in the different quadrants.

The blue lines are what I want to achieve. The outer three are correct, their starting angle is ≥ 0. The inner ones have starting angles -90, -60 and -30 degrees, which converted to 270, 300 and 330 respectively - because negative values are not allowed (they are interpreted as 0).

I do not see how to force the Arc object to draw what I want. Drawing with UI is not easier: To get the desired angles is quite simple, but to get the arc in correct position after rotation …

It seems that I need a comparable approach to the Line function (a multitude of transformations).

#target framemaker

main();

function main () {

var j, oDoc, oFrame, x0, y0, r, th0, thf, aArcs = [];

CM = 1857713, PT = 65536, DEGREE = 65536, pi = Math.PI;

oDoc = app.ActiveDoc;

oFrame = oDoc.FirstSelectedGraphicInDoc;

if (!oFrame.ObjectValid()) {

Alert("Select an anchored frame and try again.", Constants.FF_ALERT_CONTINUE_WARN);

return;

}

for (j= 0; j < 6; j++) { // FM-coordinate systemin cm

r = 2 + j*0.5; // 2, 2.5, 3.0, ...

th0 = -90 + j* 30; // -30, 0, 30, ...

thf = th0 + 90;

aArcs

= DrawArc(oDoc, oFrame, 5, 5, r, th0, thf); aArcs

.BorderWidth = 0.05*CM; aArcs

.Color = oDoc.GetNamedColor("Magenta"); aArcs

.HeadArrow = 1; // default arrows }

} //--- end main

function DrawArc(oDoc, oFrame, x0, y0, r, th0, thf) { // === Draw an arc ==========================

// Arguments x0/y0 coordinates of center point [CM] FM coord system

// r radius of circular arc

// th0 Angle (degrees) of start-point

// thf Angle (degrees) of end-point

// Returns object (e.g. for grouping)

var oArc, th1,

CM = 1857713, PT = 65536, DEGREE = 65536, pi = Math.PI;

oArc = oDoc.NewArc(oFrame);

oArc.Width = r * CM;

oArc.Height= r * CM; // let's start with a square 90° arc

oArc.LocX = x0 * CM;

oArc.LocY = (y0 - r) * CM;

if (th0 < 0) {th0 = th0 + 360;}

oArc.Theta = th0 * DEGREE;

oArc.DTheta = (th0 - thf)* DEGREE;

oArc.Theta = th0 * DEGREE;

oArc.DTheta = (thf - th0)* DEGREE;

return oArc;

} //--- end DrawArc

TOPICS

Scripting

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Advocate
,
Jan 05, 2019

Well, after much fiddling around and expeiments with various angles etc. I have this insight:Angle is the rotation angle relative to the original objectTheta and DTheta exist only for object ArcTrying to work in a mathematical/geometrical space for drawing requires some transformation.The solution I found is documented in https://daube.ch/zz_tests/FM-graphics.pdf see page 29 of current issueBut:There is a very strange thing with rotation. Any object rotated (by UI or by script) reflect the rotat...

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K.Daube
AUTHOR

Advocate
,

Dec 28, 2018

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Modifying line 42 to

if (th0 < 0) {

th0 = th0 + 360;

thf = thf + 360;

}

did the trick at least for this set of angles...

Community Guidelines

Be kind and respectful, give credit to the original source of content, and search for duplicates before posting.
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Advocate
,

Jan 05, 2019

Copy link to clipboard

Copied

Well, after much fiddling around and expeiments with various angles etc. I have this insight:

- Angle is the rotation angle relative to the original object
- Theta and DTheta exist only for object Arc
- Trying to work in a mathematical/geometrical space for drawing requires some transformation.
- The solution I found is documented in https://daube.ch/zz_tests/FM-graphics.pdf see page 29 of current issue

But:

There is a very strange thing with rotation. Any object rotated (by UI or by script) reflect the rotation in property Ange - but not so for Line. This object always displays 0 for the rotation angle!

See the experiment describe on pages 30-31 of the mentioned pdf.

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Be kind and respectful, give credit to the original source of content, and search for duplicates before posting.
Learn more

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