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Jorge,
As I (mis)understand it, The colour transition (beige to black) and the opacity/transparency transition (full opacity to full transparency) work in opposite directions.
This gives the strange transition starting with a greying of the beige (transition towards black), continuing in a darkening (owing to black being darker/denser than beige) along with a fuller greying, ending in a fading into nothing of the fully grey/diluted black.
So, the colour actually ends as a full black, only
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Since it is zero opacity it equals zero or none color.
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Eu coloquei a cor preta e está branco como transparÊncia,porém o mesmo predominou o preto,como posso resolver ?
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I may have misunderstood your question.
The color on the right is used to calculate the intermediant colors until it reaches zero opacity.
If you don't want that, use the same color in the start and end stops.
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Jorge,
As I (mis)understand it, The colour transition (beige to black) and the opacity/transparency transition (full opacity to full transparency) work in opposite directions.
This gives the strange transition starting with a greying of the beige (transition towards black), continuing in a darkening (owing to black being darker/denser than beige) along with a fuller greying, ending in a fading into nothing of the fully grey/diluted black.
So, the colour actually ends as a full black, only there is nothing left of it because it is also fully transparent.
"it is white as transparency"
Mayby what puzzles you is: at the end you are actually looking at the background which appears white(ish) because the gradient has finally withdrawn fully.
You can also say that the end transparency is a full black that is not there.
This nonsense may make more sense if you hide the image and look at the gradient in front of a white background.
I hope this sounds sufficiently woolly and unintelligible.
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I could not have said it better!