It is possible to count area with 5 mm. offset?
I use this script and want to add a 5 mm offset in the count:
I want to count irregular square where shape like U form, + offset. Shape 10x10 cm size, with 5x5 cm cut. I want to get a shape area not 75 cm2 but 101cm2.
It is even possible or not?
obviously you can't get 101 cm2 if you start with 10x10. So, assuming you want to find the size of a rectangle that will give you 101 after substrating a 5x5 area, try this
// pseudo code
x2 = 101 cm2 + 25 cm2 = 126 cm2
x = Math.sqrt(x2) = 11.22497 cm
Only one question:
10cm ×10cm + offset 0,5cm (all sides)
11cm × 11cm
… or not? Am I wrong?
Yes. The description is still not clear for me.
And the result of 101cm² is even less clear to me.
Maybe a better screenshot with an offset-object in background an the black object in the foreground will give an enlightenment?
Everything that you all say is correct.
My issue is when, I have shape 100x100 mm with 50x50 cut, and that shape area is 7500 mm2.
Everything is ok if I count with this:
But I need that, area script count with like compensation. Count not original area but bigger shape like that(red dash line):
And then I get that my area is 10100 mm2. I Dont want to add that new one shape just for the count area, it is possible to make with the script?
It's possible. But why not simply do "offset path", run your line of code and then undo. It will take seconds. Scripting will just emulate this.
Maybe it's possible, but I need in the same script real area and with „Offset path“, and I have countless different shapes where I mus count that area. That's why I ask it is possible to make that script, and maybe someone knows how?
I see, you have to make the shape to be able to query its Area.
here's a script that adds the offset path, you can delete it after getting the area if you don't need it.
Select ONE shape before running