Different labels or the same one?
All the same label. If you see the picture I am wasting 3 labels for every 1 label that I print.
How about just moving copies of the artwork for one label across by the distance between the centres/same sides of the labels?
So in adobe itself just have 4 labels set up? I thought about that, but it seems like a more manual way of going about it. I was wondering if there was a button of function that allows me to say how many labels there were across and just have the printer print multiple labels at once. If not, then I would just have to have an artboard 4x the size and make 4 labels that are proportional to the actual label.
Illy (job description Adobe Illustrator) is very friendly and always eager to help, but how can she know where the labels are?
Unless you have software for the (label) printer that sorts it out, you will have to set it up.
Here is an improved version of how, which makes it easier to edit if needed; I usually suggest that, but I am afraid I was in too much of a hurry when posting before, sorry:
With the label placed, you can use Effect>Distort & Transform>Transform, then set the Horizontal/Vertical Move (whichever applies) to the the distance between the centres/same sides of the labels and set the number of Copies to 3.
If you print on sheets with 4 x 2 labels (as it looks in the photo), you can apply the same effect in the other direction (Vertical/Horizontal) with the corresponding distance, thereby printing the whole sheet in one go.
With the Effect way, you only have 1 actual/live label, which you can edit, and then the edit will apply to all the effect copies as well.
Is an easy task in llustrator, various ways to do it, heres is one method
1. Select yor artwork and group it
2. Go to Effect - Distort and transform - Transform
3. Set up the number of copies and the distance for horizontal movement
4. Again go to Effect - Distort and transform - Transform and choose aply new effect
5. Set up the number of copies and the distance for vertical movement
Just must know exactly de distance between centers horizontally and vertically
Se attached picture