SYMBOLS COUNT TABLE

[Ari Miaciro]

It´s possible to make a script that writes a table with all symbols instances count ? how difficult it would be?

[Loic.Aigon · Accepted solution]

var main = function() {
var doc;
if ( !app.documents.length ) {
alert("This scripts needs an open document !");
return;
}
doc = app.activeDocument;
var symbols = doc.symbolItems, n = symbols.length, nSymbol, db = {}, arr = [];
while ( n-- ) {
nSymbol = symbols.symbol;
db[ nSymbol.name ]  = db[ nSymbol.name ] || 0;
db[ nSymbol.name ]++;
}
for ( prop in db ) {
arr.push ( prop+" : "+db[prop] );
}
alert( "Result:\r"+arr.join("\r") );
}
main();

[Ari Miaciro]

thank you very much !

I made a little change in the script making illustrator to paste the results in a text frame, because I coulnd´t copy the text from the alert.

var main = function() { 

var doc; 

if ( !app.documents.length ) { 

alert("This scripts needs an open document !"); 

return; 

} 

doc = app.activeDocument; 

var symbols = doc.symbolItems, n = symbols.length, nSymbol, db = {}, arr = []; 

while ( n-- ) { 

nSymbol = symbols.symbol; 

db[ nSymbol.name ]  = db[ nSymbol.name ] || 0; 

db[ nSymbol.name ]++; 

} 

for ( prop in db ) { 

arr.push ( prop+" : "+db[prop] ); 

} 

var result = doc.textFrames.add();

result.contents = ( "Result:\r"+arr.join("\r") );

result.top = 700;

result.left = 400;

redraw();

} 

main(); 

I´ll try to refine a bit to make a table, but it works anyway.

Thank you !

[jcontois37]

Hello! 

Thank you for these! 

I am gettign an error. is it becuase I named my symbols? They are all static graphic symbols

thank you!

[Silly-V]

That is a strange error, are you running the script as written or did you have anything running before it, or have extra custom code?

[jcontois37]

I am running it as written. copy and pasted it into sublime text, and then saved it as a .js. 

i do not know code so copy and paste is my only option. 

[CarlosCanto · Accepted solution]

moving to the new Forums ruined all existing scripts, try this version

var main = function() { 

 

var doc; 

 

if ( !app.documents.length ) { 

alert("This scripts needs an open document !"); 

return; 

} 

 

 

doc = app.activeDocument; 

 

var symbols = doc.symbolItems, n = symbols.length, nSymbol, db = {}, arr = []; 

 

while ( n-- ) { 

nSymbol = symbols[n].symbol; 

db[ nSymbol.name ]  = db[ nSymbol.name ] || 0; 

db[ nSymbol.name ]++; 

} 

 

 

for ( prop in db ) { 

arr.push ( prop+" : "+db[prop] ); 

} 

var result = doc.textFrames.add();

result.contents = ( "Result:\r"+arr.join("\r") );

result.top = 700;

result.left = 400;

redraw();

 

} 

 

 

main(); 

[jcontois37]

Thank you so much, that worked! 

[Rtvkeith58]

Carlos,

Thank you for the excellent script. Is it possible to have the symbol itself show in the resulting list instead of the name? How would a person code that?

Thanks, so much.

rtvkeith

[CarlosCanto]

Hi keith, what do you mean? can you elaborate?

[defaultr3832lsllkw3]

Is there a mac version of this?

[Larry G. Schneider]

The updated script by Carlos when used on a Mac should work. Two things, if you use TextEdit on the Mac be sure when you save it it is Plain Text not RTF. Use .jsx as the extension.

[defaultr3832lsllkw3]

Yes! That worked!

[jcontois37]

Hey! 

it works both on mac (i am on one) 

you just need to paste it into text edit and save it as a .js then open in illustrator like any other script 

[defaultr3832lsllkw3]

Yes, I was pasting into script editor before and it wouldn't work. Used text editor and converted to Plain Text, added the .jsx at the end and it works as described. I don't think it will do what I needed it to do which is keep a live running tally of multiple different symbols as they are added and removed.

[CarlosCanto]

no, the script runs once and stops, you would need to run it each time it's needed

[defaultr3832lsllkw3]

Ok, that's what I thought. I know basically nothing about scripts, but is a "live" script that is constantly running and updating info a possibility? I'm being asked to come up with a way to keep a tally of symbols on a floor plan in Illustrator. 

[Jatohniedan]

Would there also be a way of having this script mention only visible symbols?

[Sergey Osokin]

Copy the above code by Carlos Canto. And add the following IF check to the WHILE loop:

while (n--) {
  if (symbols[n].hidden == true) continue;
  nSymbol = symbols[n].symbol;
  db[nSymbol.name] = db[nSymbol.name] || 0;
  db[nSymbol.name]++;
}

[Jatohniedan]

Thanks for assisting! For some reason though, it still returns numbers for all symbol instances; visible and non-visible... 

[Sergey Osokin]

Full code and a screenshot of the test. If it doesn't work for you, can you show a simple example of what happens for you?

var main = function () {
  if (!app.documents.length) {
    alert("This scripts needs an open document !");
    return;
  }

  var doc = app.activeDocument;
  var symbols = doc.symbolItems;
  var n = symbols.length;
  var nSymbol, db = {};
  var arr = [];

  while (n--) {
    if (symbols[n].hidden == true) continue;
    nSymbol = symbols[n].symbol;
    db[nSymbol.name] = db[nSymbol.name] || 0;
    db[nSymbol.name]++;
  }

  for (prop in db) {
    arr.push(prop + " : " + db[prop]);
  }

  var result = doc.textFrames.add();
  result.contents = ("Result:\r" + arr.join("\r"));
  result.top = 700;
  result.left = 400;
  redraw();
}

main();

 

[Jatohniedan]

I found it only works correctly if all the symbols are in the same layer, as in your screenshot. As soon as I move some symbols to another (inactive/hidden) layer, it starts counting them again.

[Jatohniedan]

Slight rephrase: it only works for individually hidden symbols, not for symbols that are "active" but in a hidden layer. If that makes any sense... thanks though, it's already a big improvement 🙂

[Sergey Osokin]

function main() {
  if (!app.documents.length) {
    alert("This scripts needs an open document !");
    return;
  }

  var doc = app.activeDocument;
  var symbols = doc.symbolItems;
  var n = symbols.length;
  var nSymbol, db = {};
  var arr = [];

  while (n--) {
    if (isHidden(symbols[n])) continue;
    nSymbol = symbols[n].symbol;
    db[nSymbol.name] = db[nSymbol.name] || 0;
    db[nSymbol.name]++;
  }

  for (prop in db) {
    arr.push(prop + " : " + db[prop]);
  }

  var lay = getEditableLayer(doc);
  var result = lay.textFrames.add();
  result.contents = ("Result:\r" + arr.join("\r"));
  result.top = 700;
  result.left = 400;
  redraw();
}

function isHidden(item) {
  if (item.hasOwnProperty("hidden") && item.hidden == true) {
    return true;
  }
  if (item.hasOwnProperty("visible") && item.visible == false) {
    return true;
  }
  var result = false;
  var prnt = item.parent;
  switch (prnt.typename) {
    case "GroupItem":
      result = isHidden(prnt);
      break;
    case "Layer":
      result = isHidden(prnt);
      break;
    default:
      break;
  }
  return result;
}

function getEditableLayer(doc) {
  var aLay = doc.activeLayer;
  if (aLay.visible && !aLay.locked) return aLay;
  for (var i = 0, len = doc.layers.length; i < len; i++) {
    var curLay = doc.layers[i];
    if (curLay.visible && !curLay.locked) {
      doc.activeLayer = curLay;
      return curLay;
    }
  }
  doc.layers[0].visible = true
  doc.layers[0].locked = false;
  doc.activeLayer = doc.layers[0];
  return doc.layers[0];
}

main();

[Jatohniedan]

You're my hero! Thank you very much. Works a charm.