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Get selected xml element and xpath of the selected node in structure pane by javascript

Community Beginner ,
May 10, 2021 May 10, 2021

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Hi All, 

Is it possible to get selected  XML elements and Xpath of the the selected XML node from the InDesign structure pane?

 

I found below thread which select the XML node in the structure pane but I'm trying to get the selected elements and Xpath of the element.

Reference link: https://community.adobe.com/t5/indesign/select-xml-element-in-structure-pane-by-javascript/m-p/87620...

 

Thanks,

Yogita

TOPICS
How to , Scripting , SDK

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correct answers 1 Correct answer

Advocate , May 10, 2021 May 10, 2021

This below is snippet for it:

 

if(app.selection[0].constructor.name == "XMLElement" || app.selection[0].constructor.name == "XMLAttribute"){
    if(app.selection[0].constructor.name == "XMLAttribute") var node = app.selection[0].parent;
    else var node = app.selection[0];
    var root = app.documents[0].xmlElements[0];
    var tN = node;
    var xPath = "";
    while(tN != root){
        var attr = "/"+tN.markupTag.name;
        for(var x = 0; x < tN.xmlAttributes.length; x++){
            if
...

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Advocate ,
May 10, 2021 May 10, 2021

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Try this below snippet :

First select any XML Element or XML Attribute for XPATH generation & then execute the script.

generate Xpath.png

Best

Sunil

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Advocate ,
May 10, 2021 May 10, 2021

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This below is snippet for it:

 

if(app.selection[0].constructor.name == "XMLElement" || app.selection[0].constructor.name == "XMLAttribute"){
    if(app.selection[0].constructor.name == "XMLAttribute") var node = app.selection[0].parent;
    else var node = app.selection[0];
    var root = app.documents[0].xmlElements[0];
    var tN = node;
    var xPath = "";
    while(tN != root){
        var attr = "/"+tN.markupTag.name;
        for(var x = 0; x < tN.xmlAttributes.length; x++){
            if(tN.xmlAttributes[x].name.indexOf(":") == -1) attr += "[@"+tN.xmlAttributes[x].name+"='"+tN.xmlAttributes[x].value+"']";
            }
        tN = tN.parent;
        xPath = attr+xPath;
        }
    xPath = "//"+tN.markupTag.name+"/"+xPath;
    var dialog = new Window("dialog"); 
    dialog.text = "Generated Xpath"; 
    dialog.orientation = "column"; 
    dialog.alignChildren = ["right","top"]; 
    dialog.spacing = 10; 
    dialog.graphics.backgroundColor = dialog.graphics.newBrush (dialog.graphics.BrushType.SOLID_COLOR, [0, 0.251, 0.251]);
    var edittext1 = dialog.add('edittext {properties: {name: "edittext1", multiline: true, scrollable: true}}'); 
    edittext1.preferredSize.width = 400; 
    edittext1.preferredSize.height = 100; 
    edittext1.text = xPath;
    var statictext1 = dialog.add("statictext", undefined, undefined, {name: "statictext1"}); 
    statictext1.text = "Created By Sunil Yadav (Adobe Community Professional)";
    edittext1.active = true;
    dialog.show();
    }

 

Best

Sunil

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Community Beginner ,
May 10, 2021 May 10, 2021

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Thank you so much! It is woking for me.

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Engaged ,
Feb 21, 2022 Feb 21, 2022

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In that script, having elements with the same name in the same hierarchy might not work.

What about this script?

if(app.activeDocument.selection[0].constructor.name == "XMLElement"){

    absoluteXPath = getAbsoluteXPath(app.activeDocument.selection[0],"");
    
    alert(absoluteXPath);
}

function getAbsoluteXPath(targetElement,absoluteXPath){

    var elementNameCount = 0;
    
    if(targetElement.parent.constructor.name == "XMLElement"){

        for(var i = 0; i <=  targetElement.index; i++){
                
            if(targetElement.parent.xmlElements.item(i).markupTag.name == targetElement.markupTag.name){
                    
                elementNameCount++;
            }
        }
    
        absoluteXPath = "/" + targetElement.markupTag.name + "[" + elementNameCount + "]" + absoluteXPath ;
                        
        absoluteXPath = getAbsoluteXPath(targetElement.parent,absoluteXPath);
    
    }else{
        
        absoluteXPath = "/" + targetElement.markupTag.name  + absoluteXPath ;
    }

    return absoluteXPath;
}

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Advocate ,
Dec 04, 2022 Dec 04, 2022

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With this approach of generating XPath will only find that specific node, even if other elements are available with the same xpath.

So if you don't want to find other matching element with the same xpath then this approach can be used. Some people may say this as hardcoding approach.

 

And if counter of element changes within the same parent, then this XPath will not work.

 

Sunil

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