Help with deleting all characters before a given word in a line?

[samanthaz57569910]

(Beginner here) I'm working on an answer key for an (unofficial) ACT Solutions Manual, and I'm working with text from a placed Word document. This answer key is compiled of lines that begin with manually inserted bulleted numbers before a given answer letter. Example:

1. Answer: B

2. Answer: C

However, this lack of systematic formatting me no way to edit or reformat all of the bullets as one style. So, I created a paragraph style and applied bulleted numbers as part of the formatting for each "Answer" line. The problem is, the previously inputted numbers remain. So it looks like this:

1.  1. Answer: B

2.  2. Answer: C

Is there any way through which I can identify and delete those manually inputted digits so that I am left with just the formatted bullets? There is a math section among the parts of this answer key so it wouldn't work to delete all digits. I figured there would be some method by which I find and delete all characters before "Answer:", but could not find a way to do this. I am new and not familiar with GERP codes, so any help is appreciated! 🙂

[Manan Joshi · Accepted solution]

Try the following, Find Grep dialog

Find What

^(\d+\.\s+)(?=Answer:)

Change to remains blank and you can then find/change or change all

-Manan

[samanthaz57569910]

It worked! Thank you so much!