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Is there an indesign script to arrange multiple objects in a matrix?

Explorer ,
Oct 25, 2020

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can control the spacing and size.
The size can be controlled by calling the object style.
For example, I want to arrange 6 plates into: 2 columns and 3 rows.
The horizontal spacing is 4mm, and the vertical spacing is 8mm.

Adobe Community Professional
Correct answer by rob day | Adobe Community Professional

There are a lot of possible variables—are the objects different sizes, does their placement in the matrix matter, where is the position of the matrix on the page? This arranges a selection of same sized objects:

 


#target indesign

app.activeDocument.viewPreferences.horizontalMeasurementUnits = MeasurementUnits.MILLIMETERS;
app.activeDocument.viewPreferences.verticalMeasurementUnits = MeasurementUnits.MILLIMETERS;

var s = app.activeDocument.selection;

//number of columns and rows
var col = 2; var row = 3;

//space between the frames
var xgut = 4;
var ygut = 8;

var colw = getPos(s)[0];
var colh = getPos(s)[1];
var xoff = getPos(s)[2];
var yoff = getPos(s)[3] - (colh + ygut);
var startX = xoff;

//make matrix using modulo to set the columns
for (var i = 0; i < s.length; i++){
    if (i % col > 0) {
        xoff = xoff + colw + xgut;
    }else{
        xoff = startX;
        yoff = yoff + colh + ygut;
    }
    s[i].move( [xoff, yoff] );
};   



/**
* Get matrix tile position 
* @Param the selection to arrange 
* @Return an array with colwidth, rowheight, x, and y 
* 
*/
function getPos(sel){
    var x = sel[0].geometricBounds[1];
    var y = sel[0].geometricBounds[0];
    
    var w = 0;
    var h = 0;
    var a = []
    for (var i = 0; i < sel.length; i++){
        var b = sel[i].geometricBounds;
        if (b[1] < x) {
            x = b[1]
        } 
        if (b[0] < y) {
            y = b[0]
        } 
        if (b[3]-b[1] > w) {
            w = b[3]-b[1]
        } 
        if (b[2]-b[0] > h) {
            h = b[2]-b[0]
        }
    };
    a=[w, h, x, y];
    return a
}

 

Screen Shot 11.pngScreen Shot 12.png

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Is there an indesign script to arrange multiple objects in a matrix?

Explorer ,
Oct 25, 2020

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can control the spacing and size.
The size can be controlled by calling the object style.
For example, I want to arrange 6 plates into: 2 columns and 3 rows.
The horizontal spacing is 4mm, and the vertical spacing is 8mm.

Adobe Community Professional
Correct answer by rob day | Adobe Community Professional

There are a lot of possible variables—are the objects different sizes, does their placement in the matrix matter, where is the position of the matrix on the page? This arranges a selection of same sized objects:

 


#target indesign

app.activeDocument.viewPreferences.horizontalMeasurementUnits = MeasurementUnits.MILLIMETERS;
app.activeDocument.viewPreferences.verticalMeasurementUnits = MeasurementUnits.MILLIMETERS;

var s = app.activeDocument.selection;

//number of columns and rows
var col = 2; var row = 3;

//space between the frames
var xgut = 4;
var ygut = 8;

var colw = getPos(s)[0];
var colh = getPos(s)[1];
var xoff = getPos(s)[2];
var yoff = getPos(s)[3] - (colh + ygut);
var startX = xoff;

//make matrix using modulo to set the columns
for (var i = 0; i < s.length; i++){
    if (i % col > 0) {
        xoff = xoff + colw + xgut;
    }else{
        xoff = startX;
        yoff = yoff + colh + ygut;
    }
    s[i].move( [xoff, yoff] );
};   



/**
* Get matrix tile position 
* @Param the selection to arrange 
* @Return an array with colwidth, rowheight, x, and y 
* 
*/
function getPos(sel){
    var x = sel[0].geometricBounds[1];
    var y = sel[0].geometricBounds[0];
    
    var w = 0;
    var h = 0;
    var a = []
    for (var i = 0; i < sel.length; i++){
        var b = sel[i].geometricBounds;
        if (b[1] < x) {
            x = b[1]
        } 
        if (b[0] < y) {
            y = b[0]
        } 
        if (b[3]-b[1] > w) {
            w = b[3]-b[1]
        } 
        if (b[2]-b[0] > h) {
            h = b[2]-b[0]
        }
    };
    a=[w, h, x, y];
    return a
}

 

Screen Shot 11.pngScreen Shot 12.png

TOPICS
Bug, How to, Import and export, Scripting, Server developers

Views

128

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Oct 25, 2020 0
Adobe Community Professional ,
Oct 25, 2020

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Can you share some screenshots for better understanding?

 

Sunil

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Oct 25, 2020 0
Explorer ,
Nov 01, 2020

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Sorry, I was a bit busy lately and did not reply in time.
Like this, 6 different pictures, I want to quickly get 2 columns, 3 rows, the spacing is 4mm.

There are hundreds of such pictures, if the number of columns, rows, and spacing may also change

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Nov 01, 2020 0
Contributor ,
Oct 25, 2020

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What type of objects?

Maybe "MakeGrid" which comes with InDesign is kind of what you're looking for?

MakeGrid.gif

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Oct 25, 2020 1
Adobe Community Professional ,
Nov 01, 2020

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There are a lot of possible variables—are the objects different sizes, does their placement in the matrix matter, where is the position of the matrix on the page? This arranges a selection of same sized objects:

 


#target indesign

app.activeDocument.viewPreferences.horizontalMeasurementUnits = MeasurementUnits.MILLIMETERS;
app.activeDocument.viewPreferences.verticalMeasurementUnits = MeasurementUnits.MILLIMETERS;

var s = app.activeDocument.selection;

//number of columns and rows
var col = 2; var row = 3;

//space between the frames
var xgut = 4;
var ygut = 8;

var colw = getPos(s)[0];
var colh = getPos(s)[1];
var xoff = getPos(s)[2];
var yoff = getPos(s)[3] - (colh + ygut);
var startX = xoff;

//make matrix using modulo to set the columns
for (var i = 0; i < s.length; i++){
    if (i % col > 0) {
        xoff = xoff + colw + xgut;
    }else{
        xoff = startX;
        yoff = yoff + colh + ygut;
    }
    s[i].move( [xoff, yoff] );
};   



/**
* Get matrix tile position 
* @Param the selection to arrange 
* @Return an array with colwidth, rowheight, x, and y 
* 
*/
function getPos(sel){
    var x = sel[0].geometricBounds[1];
    var y = sel[0].geometricBounds[0];
    
    var w = 0;
    var h = 0;
    var a = []
    for (var i = 0; i < sel.length; i++){
        var b = sel[i].geometricBounds;
        if (b[1] < x) {
            x = b[1]
        } 
        if (b[0] < y) {
            y = b[0]
        } 
        if (b[3]-b[1] > w) {
            w = b[3]-b[1]
        } 
        if (b[2]-b[0] > h) {
            h = b[2]-b[0]
        }
    };
    a=[w, h, x, y];
    return a
}

 

Screen Shot 11.pngScreen Shot 12.png

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Nov 01, 2020 2
Explorer ,
Nov 01, 2020

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Thanks Rob Day
You are very nice

This is exactly what i want

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Nov 01, 2020 0
rob day LATEST
Adobe Community Professional ,
Nov 03, 2020

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This seems like a useful script so I added a dialog. It defaults to millimeters, but you can use any InDesign measurement unit, i.e. 1in. Haven’t tested much.

 

#target indesign
#targetengine "session"

//check for a doc
var s = app.activeDocument.selection;
if (s.length > 1) {
    makeDialog();
} else {alert("Please Select Some Frames.")}

//result variables
var xoff, syoff, col, row, xgut, ygut; 

/**
* Make the export settings dialog 
* @Return 
* 
*/
function makeDialog(){
    var mw = 90;

    //the dialog name
    var theDialog = app.dialogs.add({name:"Arrange Matrix", canCancel:true});
    with(theDialog){
        with(dialogColumns.add()){
            with(borderPanels.add()){
                with(dialogColumns.add()){
                    staticTexts.add({staticLabel:"Matrix X Pos:"});
                    staticTexts.add({staticLabel:"Matrix Y Pos:"});
                    staticTexts.add({staticLabel:"Columns:"});
                    staticTexts.add({staticLabel:"Rows:"});
                    staticTexts.add({staticLabel:"Column Gutter:"});
                    staticTexts.add({staticLabel:"Row Gutter:"});
                }
                with(dialogColumns.add()){
                    var matrixX = measurementEditboxes.add({editUnits:MeasurementUnits.MILLIMETERS, editValue:0, minWidth:mw});
                    var matrixY = measurementEditboxes.add({editUnits:MeasurementUnits.MILLIMETERS, editValue:0, minWidth:mw});
                    var nCol = integerEditboxes.add({editValue:2, minWidth:mw});
                    var nRow = integerEditboxes.add({editValue:2, minWidth:mw});
                    var colGutter = measurementEditboxes.add({editUnits:MeasurementUnits.MILLIMETERS, editValue:0, minWidth:mw});
                    var rowGutter = measurementEditboxes.add({editUnits:MeasurementUnits.MILLIMETERS, editValue:0, minWidth:mw});
                }
            }
        }
    }
	
    var dResult = theDialog.show();
    if(dResult == true){
        xoff = matrixX.editValue;
        syoff = matrixY.editValue;
        col = nCol.editValue;
        row = nRow.editValue;
        xgut = colGutter.editValue;
        ygut = rowGutter.editValue
        theDialog.destroy();
        makeMatrix();
	}else{
		theDialog.destroy();
	}
}



/**
* Discription 
* @Return void 
* 
*/
function makeMatrix(){
    
    var ohm = app.activeDocument.viewPreferences.horizontalMeasurementUnits;
    var ovm = app.activeDocument.viewPreferences.horizontalMeasurementUnits;
    app.activeDocument.viewPreferences.horizontalMeasurementUnits = MeasurementUnits.POINTS;
    app.activeDocument.viewPreferences.verticalMeasurementUnits = MeasurementUnits.POINTS;
    

    var colw = getPos(s)[0];
    var colh = getPos(s)[1];
    var yoff = syoff - (colh + ygut);
    var startX = xoff;

    //make matrix using modulo to set the columns
    for (var i = 0; i < s.length; i++){
        if (i % col > 0) {
            xoff = xoff + colw + xgut;
        }else{
            xoff = startX;
            yoff = yoff + colh + ygut;
        }
            s[i].move( [xoff, yoff] );
    };   

    app.activeDocument.viewPreferences.horizontalMeasurementUnits = ohm;
    app.activeDocument.viewPreferences.verticalMeasurementUnits = ovm;
}


/**
* Get matrix tile position 
* @Param the selection to arrange 
* @Return an array with colwidth, rowheight 
* 
*/
function getPos(sel){
    var w = 0;
    var h = 0;
    var a = []
    for (var i = 0; i < sel.length; i++){
        var b = sel[i].geometricBounds;
        if (b[3]-b[1] > w) {
            w = b[3]-b[1]
        } 
        if (b[2]-b[0] > h) {
            h = b[2]-b[0]
        }
    };
    a=[w, h];
    return a
}

 

Screen Shot 36.png

 

 

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Nov 03, 2020 0