• Global community
    • Language:
      • Deutsch
      • English
      • Español
      • Français
      • Português
  • 日本語コミュニティ
    Dedicated community for Japanese speakers
  • 한국 커뮤니티
    Dedicated community for Korean speakers
Exit
0

Mass export all images as individual JPEGs?

Community Beginner ,
Mar 13, 2017 Mar 13, 2017

Copy link to clipboard

Copied

Hi! I am new to Indesign. I have a file that contains images with Photoshop clipping paths. I want to export all the clipped images in a folder. I have tried doing the "Copy Links To" and it successfully exported the original images. However, I do not want the original images but the clipped images instead. Is there a way for me to export all the clipped images as JPEG or TIFF and not the original linked image? In short, I want to export the images without their background. I hope I'm making sense. I have about 800-1000 images so a batch processing method would be highly appreciated.

I actually found a way to export the images the way I want them to be. I just need to click the image container (not the image), go to File>Export and then export it as JPEG. In the pop up window, I choose export selection, maximum quality, and 2400 resolution. It exports the images the way I want them to be. But I have to do this one by one. I just have two concerns:

1. Is there a way for me to do this by batch? Like select all the image containers and export them one by one automatically?

2. Is there a way to automatically name the saved files according to the original image name?

Thank you for your help!

TOPICS
Scripting

Views

8.8K

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines

correct answers 1 Correct answer

Mentor , Mar 14, 2017 Mar 14, 2017

Hi,

I suggest to iterate through links instead of objects ==> so no link means no action

starting part of code:

var

    myDoc = app.activeDocument,

    apis = myDoc.links.everyItem().getElements(),

    rect, fileName;

while ( rect = apis.pop() )

{

    rect = rect.parent.parent;

    if ( !(rect.hasOwnProperty ("graphics") ){ continue; }

    fileName = File ( rect.graphics[0].itemLink.filePath ).name;

//.....

Jarek

Votes

Translate

Translate
Community Beginner ,
Mar 13, 2017 Mar 13, 2017

Copy link to clipboard

Copied

I found this script in another forum and modified it a bit to suit my needs. It appears to work in most of my INDD documents, but it fails in others. I wonder why. I get the error message that

Error string: null is not an object

Source: fileName = File ( rect.graphics[0].itemLink.filePath ).name;

I also noticed that it skips some objects and doesn't download all of the images.

test();

function test()

{

var myDoc = app.activeDocument,

apis = myDoc.allPageItems, rect, fileName;

while ( rect = apis.pop() )

{

    if ( !(rect instanceof Rectangle) || !rect.graphics[0].isValid ){ continue; }

    fileName = File ( rect.graphics[0].itemLink.filePath ).name;

    fileName = fileName.replace( /\.[a-z]{2,4}$/i, '.jpg' );

    app.jpegExportPreferences.exportResolution = 2400;

    app.jpegExportPreferences.jpegQuality = JPEGOptionsQuality.MAXIMUM;

    //give it a unique name

    var myFile = new File ("C:/Users/RANFacistol-Mata/Desktop/Image Trial/"+ fileName);

    rect.exportFile(ExportFormat.JPG, myFile);

}

}

Is there a way for me to modify this script such that instead of iterating through all the rectangles, I would iterate through all the objects instead, much like clicking this icon.Next.PNG

And then check if that object contains an image. If it does, then I will export it as scripted above.
Thanks!

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Mentor ,
Mar 14, 2017 Mar 14, 2017

Copy link to clipboard

Copied

Hi,

I suggest to iterate through links instead of objects ==> so no link means no action

starting part of code:

var

    myDoc = app.activeDocument,

    apis = myDoc.links.everyItem().getElements(),

    rect, fileName;

while ( rect = apis.pop() )

{

    rect = rect.parent.parent;

    if ( !(rect.hasOwnProperty ("graphics") ){ continue; }

    fileName = File ( rect.graphics[0].itemLink.filePath ).name;

//.....

Jarek

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Community Beginner ,
Mar 14, 2017 Mar 14, 2017

Copy link to clipboard

Copied

Hello Jarek,
Thank you for this suggestion. You're right. It's actually more efficient to iterate through the links than through the objects. However, I have one more concern. Not all of my linked images are in a rectangle. Some of them are in polygons, and some are in arbitrary shapes (like the edges have been followed). Can you suggest a way for me to catch those instances too?
Thanks!

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Community Beginner ,
Mar 14, 2017 Mar 14, 2017

Copy link to clipboard

Copied

Hi Jarek,
Your solution works like a charm.
Thank you!

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Mentor ,
Mar 14, 2017 Mar 14, 2017

Copy link to clipboard

Copied

Hi,

var rec covers all 'graphic' shapes. (link.parent.parent)

Its name is just left to reduce modifications

Jarek

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Guru ,
Mar 14, 2017 Mar 14, 2017

Copy link to clipboard

Copied

Hi Rachelle

I think Jarek has answered your question so please mark his answer as correct

Trevor

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
New Here ,
Feb 23, 2021 Feb 23, 2021

Copy link to clipboard

Copied

Hi everyone!

I just found this thread, I know it's been a while, but as I'd like to export some eps/ai/pdf linked in an INDD file as jpg. The script works but it esports the files with the same extension, I'd like them to be all converted to jpg, is that possible?

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Advocate ,
Jan 30, 2018 Jan 30, 2018

Copy link to clipboard

Copied

Is there a method for rachellefacistolmata script to export the image but take the orginal linked image into account. Now it exports a JPG using the frames ratio.

Not sure if this is clear, ive added some screengrabs to make it more clear

Placed image

Screen Shot 2018-01-30 at 11.13.39 AM.png

exported image

Screen Shot 2018-01-30 at 11.07.51 AM.png

Original linked image

Screen Shot 2018-01-30 at 11.08.57 AM.png

My guess its due to the "

rect = rect.parent.parent;

if (!(rect.hasOwnProperty("graphics"))) {

"

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Mentor ,
Feb 03, 2018 Feb 03, 2018

Copy link to clipboard

Copied

Hi,

In other words - is your goal to rename/change directory of original file instead of export?

if so there is a method:

oldFile.copy(newFile);

Jarek

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Advocate ,
Feb 03, 2018 Feb 03, 2018

Copy link to clipboard

Copied

@Jarek,

Not sure if you directed it at me. But i asked this question on StacjExchange as well and good help there. The script now exports the image and not images in form of the rectangle. I didnt even know that wa possible, exporting the shape from indesign?

Anyways here's the script if other would perhaps need it or change it. Better take out those alerts, perhaps the done can stay but the other is sort of useless

var myDoc = app.activeDocument,
  apis
= myDoc.links.everyItem().getElements(),
  items
, fileName;
var i = 0;
var MyPath = "C:/Users/xx/Desktop/test/"; // change your path here

alert
("Script is running. Press OK and wait until done...");

while (items = apis.pop()) {
  items
= items.parent.parent;
  
if (!(items.hasOwnProperty("graphics"))) {
  
continue;
  
}
  i
++;
  
try {
  fileName
= File(items.graphics[0].itemLink.filePath).name;
  fileName
= i + "_" + fileName.replace(/\.[a-z]{2,4}$/i, '.jpg');
  
} catch (e) {};

  app
.jpegExportPreferences.exportResolution = 2400;
  app
.jpegExportPreferences.jpegQuality = JPEGOptionsQuality.MAXIMUM;

  
//give it a unique name
  
var myFile = new File(MyPath + fileName);

  items
.graphics[0].exportFile(ExportFormat.JPG, myFile);
}

alert
("Done");

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Community Beginner ,
Feb 26, 2018 Feb 26, 2018

Copy link to clipboard

Copied

Hi there, thanks for the script - have been looking for something like that for some time.

  • In what order are the images exported? is it possible to change the order?
  • Is it possible to add the page-number to the name of the exported .jpeg?

Thanks

Christoph

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Community Expert ,
Feb 26, 2018 Feb 26, 2018

Copy link to clipboard

Copied

Hi Christoph,

from the code given in reply #9 the order is in the order of the links with array named apis.

What order do you prefer?

It's also possible to add a page name or the absolute number of a page in a document to the exported images.

To get the page object you could ask for link.parent.parent.parentPage. Note: if the object is on the pasteboard this will return null.

And if you have a valid page object then go for:

page.name

or:

( page.documentOffset + 1).toString()

See Jongware's DOM documentation:

Indesign JavaScript Help

Adobe InDesign CS6 (8.0) Object Model JS: Page

Or Gregor Fellenz' DOM documentation:

https://www.indesignjs.de/extendscriptAPI/indesign-latest/#Page.html

Regards,
Uwe

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Community Beginner ,
Feb 26, 2018 Feb 26, 2018

Copy link to clipboard

Copied

thanks for your reply - as i am totally unexperienced in java or any other language, i have to ask for more details.

the code from reply 9 states the file name as:

  1.   fileName = i + "_" + fileName.replace(/\.[a-z]{2,4}$/i, '.jpg'); 

so from what i understand, i have to add something here. Like:

  1.   fileName = i + "_" + link.parent.parent.parentPage +fileName.replace(/\.[a-z]{2,4}$/i, '.jpg');

but that is not working for me.

When i execute the script - the files are not renamed - but saved with their old filename

Concerning the order - i would like to order it by pagenumber and from top left to the right bottom.

Thanks!!

Christoph

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Community Expert ,
Feb 26, 2018 Feb 26, 2018

Copy link to clipboard

Copied

Hi Christoph,

link.parent.parent.parentPage.name

The value of property name of a page is the string you are looking for.

Regards,
Uwe

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Community Beginner ,
Feb 26, 2018 Feb 26, 2018

Copy link to clipboard

Copied

Hi Uwe,

sorry - but it is not working - i am using indesign cc on a mac, by the way.

Without  the link.parent.parent.parentPage.name the images are renamed correctly.

Could you check the code?

Thanks

Christoph

var myDoc = app.activeDocument,

  apis = myDoc.links.everyItem().getElements(),

  items, fileName;

var i = 0;

var MyPath = "/Users/cko/Desktop/asd/"; // change your path here

alert("Script is running. Press OK and wait until done...");

while (items = apis.pop()) {

  items = items.parent.parent;

   if (!(items.hasOwnProperty("graphics"))) {

   continue;

   }

  i++;

   try {

  fileName = File(items.graphics[0].itemLink.filePath).name;

  fileName = i + "_" + link.parent.parent.parentPage.name + fileName.replace(/\.[a-z]{2,4}$/i, '.jpg');

   } catch (e) {};

  app.jpegExportPreferences.exportResolution = 2400;

  app.jpegExportPreferences.jpegQuality = JPEGOptionsQuality.MAXIMUM;

   //give it a unique name

   var myFile = new File(MyPath + fileName);

  items.graphics[0].exportFile(ExportFormat.JPG, myFile);

}

alert("Done");

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Community Expert ,
Feb 26, 2018 Feb 26, 2018

Copy link to clipboard

Copied

Hi Christoph,

it's not working because my link in the code is referring to an actual link in the document.
You have to translate that to the actual code you are working with.

The array of links in your code is apis.

The current link the while loop is working on is items.

But items is redefined with items.parent.parent which is the container of the image.

So in the end you'll need:

items.parentPage.name

to define the name of the page.

Regards,
Uwe

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Community Beginner ,
Feb 26, 2018 Feb 26, 2018

Copy link to clipboard

Copied

Hi Uwe,

thanks! Now it works..

You saved my weekend!!

Kind Regards

Christoph

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Community Expert ,
Feb 23, 2021 Feb 23, 2021

Copy link to clipboard

Copied

Laura said: "The script works but it exports the files with the same extension, I'd like them to be all converted to jpg, is that possible?"

 

Hi Laura,

I'd think something is wrong with your code.

Please post the full code you are currently using.

 

Format it with the forum editor's "Insert/Edit code sample" controls that look like that: </>

Chose JavaScript as language.

 

Thanks,
Uwe Laubender

( ACP )

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
New Here ,
Feb 24, 2021 Feb 24, 2021

Copy link to clipboard

Copied

LATEST

Thanks Uwe,

I made another attempt this morning and now it works! (I think I mistakenly deleted one line of code). Also, there was a missing ")" at the end of line 21.

I am now using this and it works, in case anyone needs it I'll just copy it here.

Have a nice day!

Laura

test();

function test()

{

var

    myDoc = app.activeDocument,

    apis = myDoc.links.everyItem().getElements(),

    rect, fileName;

while ( rect = apis.pop() )

{

    rect = rect.parent.parent;

    if ( !(rect.hasOwnProperty ("graphics") ))
    { continue; }

    fileName = File ( rect.graphics[0].itemLink.filePath ).name;

    fileName = fileName.replace( /\.[a-z]{2,4}$/i, '.jpg' );

    app.jpegExportPreferences.exportResolution = 2400;

    app.jpegExportPreferences.jpegQuality = JPEGOptionsQuality.MAXIMUM;

    //give it a unique name

    var myFile = new File ("C:/Users/Laura/Desktop/_IMG OUT/"+ fileName);

    rect.exportFile(ExportFormat.JPG, myFile);

}

}

 

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines