remove multiple elements from array

[cmoke73]

Hi.

I have an almost finished script. Unfortunately it doesn´t work like I want:

var
myDoc = app.activeDocument
myParGroup = myDoc.paragraphStyleGroups;
myParStyles = myDoc.paragraphStyles.everyItem().name;

afGrArray = [], afArray =  [], doubAfArray = [];
afGrNr = myDoc.paragraphStyleGroups.count();


for (s=0;s<myDoc.paragraphStyles.count(); s++) {
    afArray.push(myParStyles[s]);
    }


for (i=0 ; i<afGrNr; i++) {
    
    afGr = myParGroup[i]; //.name + "\r"
    afGrName = afGr.name;
        
    afNr = myParGroup[i].paragraphStyles.count();
    
    for (n = 0; n < afNr; n++) {
        
        af = afGr.paragraphStyles[n];
        afName = af.name;
        
        afArray.push(afName);
        
        }
    
    }

   function checkMultiple(element, index) {
      for(t = 0; t < afArray.length;t++) {

        for(u = 0; u < afArray.length;u++) {
            
            if(u !== t) {

                if(afArray[u] === afArray[t] ){
                   
                    doubAfArray.push(afArray[t]); 
                    break;
                   
                    }
                }
            
         }

      }
  
  if(doubAfArray.length>0) {
     alert(doubAfArray);
  } 
  
  else {
         alert('There are no double elements');
      }
   }   

checkMultiple();

When I get the results they are double.

Like "paragraphStyle 1paragraphStyle 5paragraphStyle 1paragraphStyle 5"

Correct would be "paragraphStyle 1paragraphStyle 5". Why this doubling?

[Laubender]

Hi cmoke73,

if you want to work with an array of all available paragraph styles then work with:

app.documents[0].allParagraphStyles

This returns an array of paragraph styles.

Loop the array to get all the names.

If you want to know the specific paragraph style group one of the styles is in, check the value of parent of an individual style. If parent is your document the style is in the "root". If parent is not your document the parent is the paragraph style group that holds the style.

Note: One can have two or more paragraph styles with the same name. But that requires different paragraph style groups.

Regards,
Uwe Laubender

( ACP )

[brianp311 · Accepted solution]

It looks like you're trying to identify if a style with the same name is used multiple times within a document. Building on Uwe's suggestion to use allParagraphStyles, here's a simplified version of your script: 

var checkMultiple = function() {
    var myDoc = app.activeDocument,
        allPstyles = myDoc.allParagraphStyles,
        nameArr = [],
        doubleName = [];

    for (var p = 0; p < allPstyles.length; p++) {
        nameArr.push(allPstyles[p].name);
    }
    nameArr.sort();
    
    for (var i = nameArr.length - 1; i > 0; i--) {
        if (nameArr[i] == nameArr[i-1]) {
            doubleName.push(nameArr[i]);
            do {
                i--;
                if (i == 0) { break; } 
            }
            while (nameArr[i] == nameArr[-1]);
        }
    }
    
    if (doubleName.length == 0) {
        alert("No duplicate Paragraph Style names");
    } else {
        doubleName.sort();
        alert(doubleName);
    }
};

checkMultiple();

[brianp311]

Error in my post, and I can't edit it. The while line should be: 

while (nameArr[i] == nameArr[i-1]);

If there weren't more than three of the same name it shouldn't matter. 

[cmoke73]

Looks good Brian. I´ll try!

Thanks in advance

[cmoke73]

Update: it works fine!

🙂

[cmoke73]

Hi Uwe.

This "special way" that I created the script is because the first step was to reach the groups as well. This resulted in this form.

But good to know, your´s more elegant. 🙂

thanks!

[Sunil Yadav]

You are getting double because there are for loop two times in your code.

Just remove the second for loop. Doubling won't happen.

Reason is in first loop you are pushing all style naimes in Array named afArray.

Just remove second for loop.

Best

Sunil

[cmoke73]

Oh, okay.

But, shame on me, I can't make this adjustment to my script. 😞

Will try to understand the process in brians script with my mechanical brain...

regards

Andreas