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Channel selection setting?

Community Beginner ,
Nov 10, 2022 Nov 10, 2022

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i work with channels in PS daily; it has always been this way (and i honestly do not know why) but when you Cntrl (PC) click on the channel it always chooses the inverse of the channel.  Is there a setting where you can change it to choose the actual info in the channel?  I have tried other keyboard shortcut combos with no luck.

...and while we are at it, why would the default be to select the inverse?  I am not being clever, just interested to know why.

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Community Expert ,
Nov 10, 2022 Nov 10, 2022

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I'm puzzled. Ctrl+Click on a channel here just loads the channel as a selection, no inverse just a straightforward selection

 

Photoshop v24.0.0 Windows 10

 

Dave

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Community Expert ,
Nov 10, 2022 Nov 10, 2022

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Could you please post screenshots with the pertinent Panels (Toolbar, Layers, Channels, Options Bar, …) visible? 

What are the Channel’s Options?

Edit: »Masked Areas« or »Selected Areas« in particular?

Screenshot 2022-11-10 at 16.56.11.png

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Community Beginner ,
Nov 10, 2022 Nov 10, 2022

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here is the requested screen shot (thank you guys!)

it is an RGB file; what you are seeing is a cntrl click on the RED channel; as you can see, it is an inverted selection.

side note: if i create a custom spot channel and do the same cntrl click it chooses the right selection.

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Community Expert ,
Nov 10, 2022 Nov 10, 2022

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That is not an inverted channel selection. In RGB the lighter the pixel the closer to 100% selected, the darker the pixel the closer to 0% selected.

 

Dave

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Community Expert ,
Nov 10, 2022 Nov 10, 2022

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As @davescm already stated the white pixels are intended to signify the selected, the black ones the unselected pixels by default. 

With Alpha Channels one can change the display via the Channel Options, but with the RGB-Channels the Selection you get is as expected and intended. 

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Community Beginner ,
Nov 10, 2022 Nov 10, 2022

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i think i get it.....

the value of black in RGB is 0, so it selects the 0% areas.  But it raises the question: why does it also behave the same way in CMYK?

 

(thanks for the notes on the alpha channels)

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