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How can I rename a layer group or a layer with the same name using an action?

Participant ,
Nov 02, 2021 Nov 02, 2021

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I have quite a bit projects which contain a layer group by the name "Cover" and I want to rename it to "Cover Group" using this action.
2.jpg

But into "Cover" layer group there is a layer with the same name. So when my action starts, instead of find and rename the layer group "Cover", renames the layer "Cover"!!!
1.jpg1a.jpg

Any idea how can I define my action so to rename the layer group and not the layer?

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Actions and scripting, Windows

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correct answers 1 Correct answer

Adobe Community Professional , Nov 02, 2021 Nov 02, 2021
You may need to script that, Script can use logic to process layersets and also  test the object kind that is targeted or currently active.  Layers can be addressed by the Layer ID which is unique where Name need not be unique. You can have many layers with the name cover,  In Actions it best to navigate layers relatively then by name.  Even that can be a problem for only visible layer will be targeted relatively. If you  want to do complex processing Scripting is your best option.

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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You may need to script that, Script can use logic to process layersets and also  test the object kind that is targeted or currently active.  Layers can be addressed by the Layer ID which is unique where Name need not be unique. You can have many layers with the name cover,  In Actions it best to navigate layers relatively then by name.  Even that can be a problem for only visible layer will be targeted relatively. If you  want to do complex processing Scripting is your best option.

JJMack

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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As JJ mentioned, scripts are the way to go. Even with scripts, if you have two or more layers with the same name, you can run into issues. You can use a command to get a layer by name, but it will only find the first instance of that name. Unless you know the exact ID of the layer, you might need to loop through the layers to detect a match. In your case, checking to see it the layer is an art layer or a layer set. 

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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#target photoshop

s2t = stringIDToTypeID;

renameGroup('Cover', 'Cover Group')

function renameGroup(from, to) {
    (ref = new ActionReference()).putProperty(s2t('property'), p = s2t('numberOfLayers'));
    ref.putEnumerated(s2t('document'), s2t('ordinal'), s2t('targetEnum'));
    var len = executeActionGet(ref).getInteger(p);
    for (var i = 1; i <= len; i++) {
        (r = new ActionReference()).putProperty(s2t('property'), p = s2t('layerSection'));
        r.putIndex(s2t('layer'), i);
        if (typeIDToStringID(executeActionGet(r).getEnumerationValue(p)) == 'layerSectionEnd') continue;

        (r = new ActionReference()).putProperty(s2t('property'), p = s2t('layerKind'));
        r.putIndex(s2t('layer'), i);
        if (executeActionGet(r).getInteger(p) != 7) continue;

        (ref = new ActionReference()).putProperty(s2t('property'), p = s2t('name'));
        ref.putIndex(s2t('layer'), i);
        if (executeActionGet(ref).getString(p).match(new RegExp(from, 'i'))) {
            (r = new ActionReference()).putIndex(s2t('layer'), i);
            (d = new ActionDescriptor()).putReference(s2t('null'), r);
            (d1 = new ActionDescriptor()).putString(s2t('name'), to);
            d.putObject(s2t('to'), s2t('layer'), d1);
            executeAction(s2t('set'), d, DialogModes.NO);
        }
    }
}

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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doesn't seem to work ...

(ps2020)

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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Maybe we need to select group before renaming? I have no 20 version to check

 

#target photoshop

s2t = stringIDToTypeID;

renameGroup('Cover', 'Cover Group')

function renameGroup(from, to) {
    (r = new ActionReference()).putProperty(s2t('property'), p = s2t('numberOfLayers'));
    r.putEnumerated(s2t('document'), s2t('ordinal'), s2t('targetEnum'));
    var len = executeActionGet(r).getInteger(p);
    for (var i = 1; i <= len; i++) {
        (r = new ActionReference()).putProperty(s2t('property'), p = s2t('layerSection'));
        r.putIndex(s2t('layer'), i);
        if (typeIDToStringID(executeActionGet(r).getEnumerationValue(p)) == 'layerSectionEnd') continue;

        (r = new ActionReference()).putProperty(s2t('property'), p = s2t('layerKind'));
        r.putIndex(s2t('layer'), i);
        if (executeActionGet(r).getInteger(p) != 7) continue;

        (r = new ActionReference()).putProperty(s2t('property'), p = s2t('name'));
        r.putIndex(s2t('layer'), i);
        if (executeActionGet(r).getString(p).match(new RegExp(from, 'i'))) {
            (r = new ActionReference()).putIndex(s2t("layer"), i);
            (d = new ActionDescriptor()).putReference(s2t("null"), r);
            executeAction(s2t("select"), d, DialogModes.NO);

            (r = new ActionReference()).putEnumerated(s2t('layer'), s2t('ordinal'), s2t('targetEnum'));
            (d = new ActionDescriptor()).putReference(s2t('null'), r);
            (d1 = new ActionDescriptor()).putString(s2t('name'), to);
            d.putObject(s2t('to'), s2t('layer'), d1);
            executeAction(s2t('set'), d, DialogModes.NO);
        }
    }
}

 

 

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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According to given scenario you may use below script:

 

aD.activeLayer = (aD = activeDocument).layerSets.getByName('Cover')

 

or directly rename it (so without selecting):

 

activeDocument.layerSets.getByName('Cover').name += ' Group'

 

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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select layer Cover

rename CoverTmp

select layer Cover

rename CoverGroup

select layer CoverTmp

rename Cover

 

 

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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Loll, I had earlier to suggest exaclty same workaround, but then thought, nah, too nasty 😉

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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what is "nah" ? : )

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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That's english slang - antitype for yeah 😄

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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In Russian, the meaning is about the same, but this is an obscene vocabulary 😄

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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Yea, not obscene in the U.S., at least, as far as I know. But then there are a lot of crazies getting upset at all sorts of our words.

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Adobe Community Professional ,
Nov 03, 2021 Nov 03, 2021

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Oh yeah, I recently found on this forum this problem the US deals with (how ever it seems for many it's positive). That was few days ago in InDesign community where one commonly used M-word was banned from 2022 edition.

 

I am happy to see not all world goes crazy, and r-bin with jazz-y smiled after I unconsciously used a word of that type. Although we have access to global environment via internet, perhpas the reason we are not affected by that trend, is we live in countries on other part of planet, where laugh is more valued than wrath.

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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If the relative position of the layers in all documents is the same, then you can use the commands for moving along the layers palette to select the desired element, for example: 

2021-11-03_00-43-14.png

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Adobe Community Professional ,
Nov 02, 2021 Nov 02, 2021

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Another idea stolen from my mind! How were you able to take it over so fast?

 

Actually I was close. I missed out collapsing grups and it doesn't work for invisible layers.

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Adobe Community Professional ,
Nov 03, 2021 Nov 03, 2021

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There can be a problem Targeting layers relatively in Actions.  Select Front, Back, Forward, Backward layer.  Only select visible layer you can not select layers that have the visibility turned off.  So which layer be be select can change. There is a dependency on the layers visibility state.

JJMack

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