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• How to calculate the new boundaries of an object a...

# How to calculate the new boundaries of an object after transformation?

Jul 28, 2021 Jul 28, 2021

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I have an object inside a layer, the initial boundaries of which are known, but I cannot get them directly (this is part of the image) . Object are described in the standard way in document coordinates - top, left, right, bottom. I need to perform a series of transformations of the entire layer and after that get the new coordinates of the object inside it (transformation in this case is only a change in scale, image rotation is not performed). I easily coped with move (x+dx) (y+dy), but I got stuck on the transformation with the center set manually (the coordinates of this point are known - x, y). It seems that I understand this combination of move + scale and a proportional change coordinates is required depending on their distance from the point x,y, but I cannot deduce the correct formula for calculating the new values ​​of top, left, right, bottom. Can someone help me with this?

P.S. it is clear that we can copy an object to a new layer and perform its transformation with the same parameters as the main layer (this is how the script works at the moment), but I want to speed up the script and get rid of unnecessary transformations (that is, get coordinates by calculation )

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Actions and scripting

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Adobe Community Professional , Jul 28, 2021 Jul 28, 2021
this.transform = function (dX, dY, scale, x, y, subject) { (r = new ActionReference()).putEnumerated(s2t('layer'), s2t('ordinal'), s2t('targetEnum')); (d = new ActionDescriptor()).putReference(s2t('null'), r); d.putEnumerated(s2t('freeTransformCenterState'), s2t('quadCenterState'), s2t('QCSIndependent')); ((d1 = new ActionDescriptor())).putUnitDouble(s2t('horizontal'), s2t('pixelsUnit'), x); d1.putUnitDouble(s2t('vertical'), s2t('pixelsUnit'), y); ...

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Jul 28, 2021 Jul 28, 2021

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`````` this.transform = function (dX, dY, scale, x, y, subject) {
(r = new ActionReference()).putEnumerated(s2t('layer'), s2t('ordinal'), s2t('targetEnum'));
(d = new ActionDescriptor()).putReference(s2t('null'), r);
((d1 = new ActionDescriptor())).putUnitDouble(s2t('horizontal'), s2t('pixelsUnit'), x);
d1.putUnitDouble(s2t('vertical'), s2t('pixelsUnit'), y);
d.putObject(s2t('position'), s2t('paint'), d1);
(d2 = new ActionDescriptor()).putUnitDouble(s2t('horizontal'), s2t('pixelsUnit'), dX);
d2.putUnitDouble(s2t('vertical'), s2t('pixelsUnit'), dY);
d.putObject(s2t('offset'), s2t('offset'), d2);
d.putUnitDouble(s2t('width'), s2t('percentUnit'), scale);
d.putUnitDouble(s2t('height'), s2t('percentUnit'), scale);
d.putEnumerated(s2t('interfaceIconFrameDimmed'), s2t('interpolationType'), s2t('bicubic'));
executeAction(s2t('transform'), d, DialogModes.NO);

if (subject) {
with (subject) {
var dV = (height * scale / 100 - (bottom - top)),
dH = (width * scale / 100 - (right - left));
top = top - (dV * (y - top) / height) + dY
bottom = bottom + (dV * (bottom - y) / height) + dY
left = left - (dH * (x - left) / width) + dX
right = right + (dH * (right - x) / width) + dX
height = height * scale / 100
width = width * scale / 100
}
}``````

* where subject is object with bounding box coordinates

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Jul 28, 2021 Jul 28, 2021

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Can you edit your code to working version to let me try out it on some layer with an object inside?

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It is difficult for me to provide a working code, since I am getting the coordinates of the object with the layer from another program. But there is no difference, you can just calculate the bounding rect of the current layer after transformation.

``````var lr = new AM('layer'),
subject = lr.descToObject(lr.getProperty('boundsNoEffects'));

lr.transform(100, 200, 150, 70, 120, subject)
var newBounds = lr.descToObject(lr.getProperty('boundsNoEffects'));
alert ('calculated:\ntop: '+subject.top +', left: ' +subject.left + ', right: ' + subject.right + ', bottom: ' + subject.bottom + '\nreal:\ntop: '
+newBounds.top +', left: ' +newBounds.left + ', right: ' +newBounds.right + ', bottom: ' + newBounds.bottom + '\nreal:\n')

function AM(target, order) {
var s2t = stringIDToTypeID,
t2s = typeIDToStringID;

target = s2t(target)

this.getProperty = function (property, descMode, id, idxMode, parent, parentIdx) {
property = s2t(property);
(r = new ActionReference()).putProperty(s2t('property'), property);
id != undefined ? (idxMode ? r.putIndex(target, id) : r.putIdentifier(target, id)) :
r.putEnumerated(target, s2t('ordinal'), order ? s2t(order) : s2t('targetEnum'));
if (parent) r.putIndex(s2t(parent), parentIdx);
return descMode ? executeActionGet(r) : getDescValue(executeActionGet(r), property)
}

this.descToObject = function (d) {
var o = {}
for (var i = 0; i < d.count; i++) {
var k = d.getKey(i)
o[t2s(k)] = getDescValue(d, k)
}
return o
}

this.transform = function (dX, dY, scale, x, y, subject) {
(r = new ActionReference()).putEnumerated(s2t('layer'), s2t('ordinal'), s2t('targetEnum'));
(d = new ActionDescriptor()).putReference(s2t('null'), r);
((d1 = new ActionDescriptor())).putUnitDouble(s2t('horizontal'), s2t('pixelsUnit'), x);
d1.putUnitDouble(s2t('vertical'), s2t('pixelsUnit'), y);
d.putObject(s2t('position'), s2t('paint'), d1);
(d2 = new ActionDescriptor()).putUnitDouble(s2t('horizontal'), s2t('pixelsUnit'), dX);
d2.putUnitDouble(s2t('vertical'), s2t('pixelsUnit'), dY);
d.putObject(s2t('offset'), s2t('offset'), d2);
d.putUnitDouble(s2t('width'), s2t('percentUnit'), scale);
d.putUnitDouble(s2t('height'), s2t('percentUnit'), scale);
d.putEnumerated(s2t('interfaceIconFrameDimmed'), s2t('interpolationType'), s2t('bicubic'));
executeAction(s2t('transform'), d, DialogModes.NO);

if (subject) {
with (subject) {
var dV = (height * scale / 100 - (bottom - top)),
dH = (width * scale / 100 - (right - left));
top = top - (dV * (y - top) / height) + dY
bottom = bottom + (dV * (bottom - y) / height) + dY
left = left - (dH * (x - left) / width) + dX
right = right + (dH * (right - x) / width) + dX
height = height * scale / 100
width = width * scale / 100
}
}
}

function getDescValue(d, p) {
switch (d.getType(p)) {
case DescValueType.OBJECTTYPE: return (d.getObjectValue(p));
case DescValueType.LISTTYPE: return d.getList(p);
case DescValueType.REFERENCETYPE: return d.getReference(p);
case DescValueType.BOOLEANTYPE: return d.getBoolean(p);
case DescValueType.STRINGTYPE: return d.getString(p);
case DescValueType.INTEGERTYPE: return d.getInteger(p);
case DescValueType.LARGEINTEGERTYPE: return d.getLargeInteger(p);
case DescValueType.DOUBLETYPE: return d.getDouble(p);
case DescValueType.ALIASTYPE: return d.getPath(p);
case DescValueType.CLASSTYPE: return d.getClass(p);
case DescValueType.UNITDOUBLE: return (d.getUnitDoubleValue(p));
case DescValueType.ENUMERATEDTYPE: return [t2s(d.getEnumerationType(p)), t2s(d.getEnumerationValue(p))];
default: break;
};
}
}``````

PS. I would like to recalculate coordinates after rotation. Now I don't need it, but one day it might come in handy.

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Jul 28, 2021 Jul 28, 2021

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What kind of layer is it? Do you mean by layer the entire gray area, while the blue square is an object with some x, y point inside? Or gray area is some background of other layer while the mentioned layer is a blue square, that said, the x, y object would be then an object?

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Jul 28, 2021 Jul 28, 2021

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gray area - layer, blue square - object in this layer

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