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Clipping Mask Disturb When Paste Layer

Participant ,
Jun 09, 2021 Jun 09, 2021

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I have 2layers. Like Layer1 and Layer 2, I want to paste new layer above layer 2, But Layer 3 is automatic clipping mask, Is that possible to normal layer.....

tt.JPG

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Actions and scripting

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Adobe
Community Expert ,
Jun 09, 2021 Jun 09, 2021

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Hi

You can either right click on layer 3 and select "Release Clipping Mask" or ALT + left click between layer 2 and 3 to release the clipping mask

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Community Expert ,
Jun 09, 2021 Jun 09, 2021

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When none of the layers is selected, Photoshop should place pasted content of top of the layers stack without to clip to layer below.

 

Another option that is available is to create blank new layer and to position it where you want in the layers panel. With blank layer selected paste copied pixel content which should be pasted on that blank layer as its content. Otherwise content will be pasted above blank layer without to create automatic clipping mask.

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Community Expert ,
Jun 09, 2021 Jun 09, 2021

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Will the layers always have the same names?

 

Will the layers always have the same stacking order/position?

 

Layer 3 appears to be a copy/paste of layer 1? Will you always copy and paste from the clipboard? Would you drag the layer to the new layer icon to duplicate?

 

Are you looking for an action or script?


Any other info?


Edit: do you want to trigger/execute this manually, or do you want this to automatically happen whenever you paste a layer above an existing clipping group layer?

 

 

 

 

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Participant ,
Jun 09, 2021 Jun 09, 2021

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This is script file, I want to Paste Above Clipping Layer,  Paste Layer also have clipping layer, Don't want to clipping layer

 

#target photoshop
//
// LayerC.jsx
//

//
// Generated Sat Jan 23 2021 23:22:57 GMT+0530
//

cTID = function(s) { return app.charIDToTypeID(s); };
sTID = function(s) { return app.stringIDToTypeID(s); };

//
//==================== LayerC ==============
//
function LayerC() {
// Make
function step1(enabled, withDialog) {
if (enabled != undefined && !enabled)
return;
var dialogMode = (withDialog ? DialogModes.ALL : DialogModes.NO);
var desc1 = new ActionDescriptor();
var ref1 = new ActionReference();
ref1.putClass(sTID("contentLayer"));
desc1.putReference(cTID('null'), ref1);
var desc2 = new ActionDescriptor();
desc2.putBoolean(cTID('Grup'), true);
var desc3 = new ActionDescriptor();
var desc4 = new ActionDescriptor();
desc4.putDouble(cTID('Rd '), 255);
desc4.putDouble(cTID('Grn '), 23.5564198717475);
desc4.putDouble(cTID('Bl '), 0);
desc3.putObject(cTID('Clr '), sTID("RGBColor"), desc4);
desc2.putObject(cTID('Type'), sTID("solidColorLayer"), desc3);
desc1.putObject(cTID('Usng'), sTID("contentLayer"), desc2);
executeAction(cTID('Mk '), desc1, dialogMode);
};

// Move
function step2(enabled, withDialog) {
if (enabled != undefined && !enabled)
return;
var dialogMode = (withDialog ? DialogModes.ALL : DialogModes.NO);
var desc1 = new ActionDescriptor();
var ref1 = new ActionReference();
ref1.putEnumerated(cTID('Lyr '), cTID('Ordn'), cTID('Trgt'));
desc1.putReference(cTID('null'), ref1);
var ref2 = new ActionReference();
ref2.putEnumerated(cTID('Lyr '), cTID('Ordn'), cTID('Frnt'));
desc1.putReference(cTID('T '), ref2);
executeAction(cTID('move'), desc1, dialogMode);
};

step1(); // Make
step2(); // Move
};

 

//=========================================
// LayerC.main
//=========================================
//

LayerC.main = function () {
LayerC();
};

LayerC.main();

// EOF

"LayerC.jsx"
// EOF

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Community Expert ,
Jun 09, 2021 Jun 09, 2021

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Sadly, I have no idea what you want, I was hoping for answers to my previous questions, perhaps I'm lost in translation.

 

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LEGEND ,
Jun 18, 2021 Jun 18, 2021

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He creates many threads with different requests and then don't visit them to get final help.

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Participant ,
Jun 19, 2021 Jun 19, 2021

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Many therads i visisted @Kukurykus 

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LEGEND ,
Jun 19, 2021 Jun 19, 2021

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You don't answer to other users questions but expect they will help you. You didn't mark any final solution as correct, or at least said that is correct, even when asked for. Follow etiquette.

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Participant ,
Jun 19, 2021 Jun 19, 2021

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Ok @Kukurykus  I will mark

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