"Visible If" not working

[Ayush Bakshi]

Hi! People,

There's a boolean input node having indentifer name as "bevel_type"

There's a second input value node.

I want input value node to be visible when "bevel_type" is true.

I'm finding such a simple stuff difficult.

I used this as guide:

Visible if: control visibility of inputs, outputs and parameters | Substance 3D Designer (adobe.com)

The expression I entered in the "Visible If" of input value node is:

input["bevel_type"] == True

input.bevel_type == True

A) There's no way to add line_break/ENTER/Return in "Visible If" field as shown in the documentation link above.

B) It's just giving me yellow exclamation.

[davescm]

Hi

If the identifier for your Boolean Input parameter is bevel_type You just need

input.bevel_type == true

Note the spaces before and after == and also lowercase true

This looks like a Substance Designer question so I will move the thread to that forum

Dave

[Ayush Bakshi]

Hey, Thanks for the quick reply.

I tried:

input.bevel_type == true

and

input["bevel_type"] == true

Unfortunately that didn't work.

In such problem I don't know what else to check. The identifier exists, the letter case is correct, good syntax.

[davescm]

Can you show a screenshot of the input parameter labelling and also the other input visible if entry as below (where it is working here)

Dave

[Ayush Bakshi]

Here's the screenshot:

I want to control the visibility of two inputs (Bevel In and Bevel Out) using the bevel_type input (boolean type).

[davescm · Accepted solution]

Thanks for the screenshot, now I see the difference between what we were doing.

As far as I am aware, Visible If has to reference an input parameter (in the input parameters section) rather than an input value node.

Dave