get scale (h, v)

[jhonperezph]

Hi,

I need help, I need to know the scale percentage of the image placed in illustrator. I can get it from matrix,  but after I rotate the image,  everything changed. What I need is exactly the same what I see in Link Information  " scale (h, v)"    - this when you double click the image from the link panel.

Thank you.

[Loic.Aigon]

Seems like nothing works best than matrices:

alert("Horizontal Scale : "+Math.round((app.selection[0].matrix.mValueA*100)*100)/100+"\r"+"Vertical Scale : "+Math.round((app.selection[0].matrix.mValueD*100)*100)/100+"%");

[jhonperezph]

Thanks for the help!!!

But if forgot to mention that I'm using applescript .

Anyway, I found this...    do shell script "ruby -e 'puts Math.atan2(" & mvalue_b of m & "," & mvalue_a of m & ") / Math::PI * 180'"  by (_simon) - this will give the rotation percentage of the image.

So I use it to rotate back my image to 0 deg to get the right scale percentage:

set z to selection

set x to do shell script "ruby -e 'puts Math.atan2(" & mvalue_b of m & "," & mvalue_a of m & ") / Math::PI * 180'"

set y to get mvalue_b of matrix of the selection

if y is not equal to 0 then

rotate z angle x about top right

set z to get mvalue_a of matrix of the selection

undo

else

set z to get mvalue_a of matrix of the selection

end if

this works for me, but if you can still give me a better syntax, ill appreciate.  Thank you!

Jhon

[Silly-V]

Does applescript not have the trig math operations?

[Ten A]

Hi Loic,

I agree to your solution. However, we can't get correct scale when it had a rotatation angle like below.

[Ten A]

Here is a PoC code, get scale from rotated image.

var tg = app.selection[0];
var mx = tg.matrix;
var deg = Math.atan2(mx.mValueB, mx.mValueA) * 180 / Math.PI;
var nm = new Matrix;
nm.mValueA = nm.mValueD = 1;
nm.mValueB = nm.mValueC = 0;
var rtmx = app.concatenateRotationMatrix(nm, deg);
var sc = mx.mValueA / rtmx.mValueA;
alert(sc);

I'm stacking math a few month ago. Thank you for your info jhonperezph!

[renél80416020]

Bonjour,

merci Ten A

// JavaScript Document Illustrator
// elleere Sun, 25 February 2018 21:08:12 GMT
{
  if (selection) {
  var sel = selection[0];
    if(sel.typename=='RasterItem' || sel.typename == 'PlacedItem') {
      var propT =  getscale1(sel);
      alert("scale1(H,V) : ("+propT.H+"%, "+propT.V+"%), Rotation : "+propT.A+" °");
      var propT =  getscale2(sel);
      alert("scale2(H,V) : ("+propT.H+"%, "+propT.V+"%), Rotation : "+propT.A+" °");
    }
  }
//---------------
  function  getscale1(tg) {
    var mtx, deg, degArd, scH, scV;
        mtx = tg.matrix;
        deg = Math.atan2(mtx.mValueB, mtx.mValueA) * 180 / Math.PI;
        degArd =getArrondi(deg,3);
        tg.rotate(-deg);
        mtx = tg.matrix;
        scH = getArrondi(mtx.mValueA * 100,3);
        scV = getArrondi(mtx.mValueD * 100,3);
        tg.rotate(deg);
        return {H:scH,V:scV,A:degArd}
    }
  function getscale2(tg){
    var mx, deg, degArd, nm, rtmx,scH, scV;
        mx = tg.matrix;
        deg = Math.atan2(mx.mValueB, mx.mValueA) * 180 / Math.PI;
        degArd =getArrondi(deg,3);
        nm = new Matrix;
        nm.mValueA = nm.mValueD = 1;
        nm.mValueB = nm.mValueC = 0;
        rtmx = app.concatenateRotationMatrix(nm, deg);
        scH = getArrondi(mx.mValueA / rtmx.mValueA * 100,3);
        scV = getArrondi(mx.mValueD / rtmx.mValueD * 100,3);
        return {H:scH,V:scV,A:degArd}
  }
  //---------------
  function getArrondi(nb,N) {
  //arrondi nb a N chiffres apres la virgule
  return Math.round(Math.pow(10,N)*nb)/Math.pow(10,N);
  }
//---------------
}

[Ten A]

Bon travail!

Merci de l'avoir partagé.

[renél80416020]

Rectificatif pour le script donné plus haut :

Inverser la valeur de l'angle

deg = -Math.atan2(mtx.mValueB, mtx.mValueA) * 180 / Math.PI;

scV valeur absolue

scV = Math.abs(getArrondi(mx.mValueD / rtmx.mValueD*100,3));

Désolé LR