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Remove All Group Without any contents

Participant ,
Jul 12, 2021 Jul 12, 2021

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Is that possible to remove all Group only without any contents ?

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Actions and scripting

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correct answers 1 Correct answer

Adobe Community Professional , Jul 13, 2021 Jul 13, 2021
You need to more clearly express your thought (not in "two words")   ungroup_folder(activeDocument); function ungroup_folder(f) { try { for (var i = f.layerSets.length-1; i >= 0; i--) { ungroup_folder(f.layerSets[i]); } if (f.typename == "LayerSet") { cTID = function(s) { return app.charIDToTypeID(s); }; sTID = function(s) { return app.stringIDToTypeID(s); }; var desc1 = new Acti...

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Adobe Community Professional ,
Jul 12, 2021 Jul 12, 2021

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Close to what you need:

File-> Scripts-> Delete All Empy Layers

 

For groups only, you need to edit the script

 

UPD. the code is taken from that script 

 

deleteAllEmptyLayerSets(activeDocument)

function deleteAllEmptyLayerSets(o){
    try{
        var bEmpty = true;
        for(var i = o.layerSets.length-1; 0 <= i; i--) {
            var layerSet = o.layerSets[i];
            if((layerSet.allLocked)||(0!=layerSet.linkedLayers.length)){
                continue; // skip locked or linked
            }
            if(deleteAllEmptyLayerSets(layerSet)){ // empty
                layerSet.remove(); // delete
            } else  bEmpty = false;      // not empty
        }
        if(0 != o.artLayers.length) bEmpty = false; // not empty
    }catch(e){
        ; // do nothing
    }
    return bEmpty;
}

 

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Participant ,
Jul 12, 2021 Jul 12, 2021

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Yes @r-bin , Can You Modify this !

cTID = function(s) { return app.charIDToTypeID(s); };
sTID = function(s) { return app.stringIDToTypeID(s); }; 

 var desc1 = new ActionDescriptor();
    var ref1 = new ActionReference();
    ref1.putEnumerated(cTID('Lyr '), cTID('Ordn'), cTID('Trgt'));
    desc1.putReference(cTID('null'), ref1);
    desc1.putBoolean(sTID("deleteContained"), false);
    executeAction(cTID('Dlt '), desc1, DialogModes.NO);

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Adobe Community Professional ,
Jul 13, 2021 Jul 13, 2021

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You need to more clearly express your thought (not in "two words")
ungroup_folder(activeDocument);

function ungroup_folder(f)
    {
    try {
        for (var i = f.layerSets.length-1; i >= 0; i--)
            {
            ungroup_folder(f.layerSets[i]);
            }

        if (f.typename == "LayerSet") 
            {
            cTID = function(s) { return app.charIDToTypeID(s); };
            sTID = function(s) { return app.stringIDToTypeID(s); }; 

            var desc1 = new ActionDescriptor();
            var ref1 = new ActionReference();
            //ref1.putEnumerated(cTID('Lyr '), cTID('Ordn'), cTID('Trgt'));
            ref1.putIdentifier(cTID('Lyr '), f.id);
            desc1.putReference(cTID('null'), ref1);
            desc1.putBoolean(sTID("deleteContained"), false);
            executeAction(cTID('Dlt '), desc1, DialogModes.NO);
            }
        }
    catch (e) { alert(e); }        
    }

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Participant ,
Jul 13, 2021 Jul 13, 2021

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Thanku so much @r-bin  I Worked Very Well !

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Adobe Community Professional ,
Jul 13, 2021 Jul 13, 2021

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"Remove All Group Without any contents" means "to remove only one group that does not contain any layer(Set)s". If you wanted to remove any group and to remain its content you would say: "remove all groups, but keep their content".


The first r-bin scirpt is then correct answer to your question, plus it scans more than one group as bonus. The Goolge translation doesn't work for you. Again we're in endless loop of misunderstandings and guessing. Tell us what is the problem of talking to us in Hindi if again another thread shows your English fails?

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Participant ,
Jul 13, 2021 Jul 13, 2021

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In Active Document "Remove All Group Without Content" Means I have 5Group Inside Many Layer so i want to remove Group Only, Anyway Answar is right from @r-bin 

 

What is not understanding tell me @Kukurykus , Everything is easily understand which point you can't understand tell me !

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Participant ,
Jul 13, 2021 Jul 13, 2021

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The first @r-bin  scirpt is then correct answer Of my question, why @r-bin   have said need to edit the script

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Participant ,
Jul 13, 2021 Jul 13, 2021

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Don't need to google translation because eveything is understanding , If you don't understand tell me which sentence is not clear ?

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Adobe Community Professional ,
Jul 13, 2021 Jul 13, 2021

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Your own words from Jul 12, 2021:

quote

Next Time I will try to Best Speak English Via Google Translator


By @MXKS

 

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Adobe Community Professional ,
Jul 13, 2021 Jul 13, 2021

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r-bin said there's need to edit the script and in no time presented version of edited script which originally removed empty layers, but still in context of your original request.

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Adobe Community Professional ,
Jul 13, 2021 Jul 13, 2021

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I explained in simple words what "Remove All Group Without Content" means. The meaning you bring now is only that you 'see' in your head, not that the users can straigfuly understand from your words.

 

If "Remove All Group Without Content" means "I have 5Group Inside Many Layer so i want to remove Group Only" why you didn't say it at start?

 

Again that is even much harder to say what that does mean. The only what I can understand from "I have 5Group Inside Many Layer so i want to remove Group Only" is "I have some object named '5Group' inside of many layer (which again we have to guess you mean 'many layers', and what has no sense as layer can't contain a group, but can contain for ex. a text ie. '5Group' can be text content in this case) so I want to remove Group Only (that means you want to keep number '5' removing 'Group' suffix).

 

As you see all of this has no logic for someone who read it.

 

If 'Everything is easily understand' why first r-bin solution wasn't marked as correct, but he had to ask you for more than 'two words' to eventually post other code than originaly due to your original request?

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Participant ,
Jul 13, 2021 Jul 13, 2021

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Always You have problem with me @Kukurykus 

 

@r-bin  Said the First Answar:- 

Close to what you need:

File-> Scripts-> Delete All Empy Layers

For groups only, you need to edit the script

UPD. the code is taken from that script 

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Adobe Community Professional ,
Jul 13, 2021 Jul 13, 2021

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Adobe Community Professional ,
Jul 12, 2021 Jul 12, 2021

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You can also try this. It seems to delete all empty groups and will delete nested empty groups.

 

 

#target photoshop
var doc = activeDocument;
var useList = [];
var layerSets = 0
try{doc.backgroundLayer}
catch(e){layerSets=1}
var layerList = getLayerSetsData();


for (var i=0;i<layerList.length;i++){
    if(layerList[i].type == 7){
        useList.push(layerList[i].id)};
            }         
for(var i=0;i<useList.length;i++){
    multiSelectByIDs (useList[i]);
    if(doc.activeLayer.layers.length == 0){doc.activeLayer.remove()}
    }
    
function getLayerSetsData(){
    var lyrSets = [];
    
    while (true)
    {
        ref = new ActionReference();
        ref.putIndex(charIDToTypeID('Lyr '), layerSets);
        try
            {var d1 = executeActionGet(ref)}
        catch (err){
            break;
            };

        var c2t = function (s){return app.charIDToTypeID(s);};
        var s2t = function (s){return app.stringIDToTypeID(s);};
        var lyrSet = {};

        lyrSet.type = d1.getInteger(s2t("layerKind"));
        lyrSet.name = d1.getString(c2t("Nm  "));
        lyrSet.id = d1.getInteger(s2t("layerID"));
        
        lyrSets.push(lyrSet);
        layerSets++;
    }; 
    return lyrSets;
}; 

function doesIdExists( id ){// function to check if the id exists

   var res = true;
   var ref = new ActionReference();
   ref.putIdentifier(charIDToTypeID('Lyr '), id);
    try{var desc = executeActionGet(ref)}catch(err){res = false};
    return res;
}

function multiSelectByIDs(ids) {
    $.writeln(ids)
  if( ids.constructor != Array ) ids = [ ids ];
    var layers = new Array();
    var id54 = charIDToTypeID( "slct" );
    var desc12 = new ActionDescriptor();
    var id55 = charIDToTypeID( "null" );
    var ref9 = new ActionReference();
    for (var i = 0; i < ids.length; i++) {
       if(doesIdExists(ids[i]) == true){// a check to see if the id stil exists
           layers[i] = charIDToTypeID( "Lyr " );
           ref9.putIdentifier(layers[i], ids[i]);
       }
    }
    desc12.putReference( id55, ref9 );
    var id58 = charIDToTypeID( "MkVs" );
    desc12.putBoolean( id58, false );
    executeAction( id54, desc12, DialogModes.NO );
}

 

 

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Participant ,
Jul 12, 2021 Jul 12, 2021

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No , I will remove Group Only Without any content :-

cTID = function(s) { return app.charIDToTypeID(s); };
sTID = function(s) { return app.stringIDToTypeID(s); }; 

 var desc1 = new ActionDescriptor();
    var ref1 = new ActionReference();
    ref1.putEnumerated(cTID('Lyr '), cTID('Ordn'), cTID('Trgt'));
    desc1.putReference(cTID('null'), ref1);
    desc1.putBoolean(sTID("deleteContained"), false);
    executeAction(cTID('Dlt '), desc1, DialogModes.NO);

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Adobe Community Professional ,
Jul 13, 2021 Jul 13, 2021

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As far as the translation issue, I would post your questions and replies in both your native language and in English. Maybe someone can then better translate. I would also use more screen shots to show want you want.

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