Help with Gradients

If you weren't using that before it would be difficult to get the correct matrix, Its a Matrix utility method specifically for gradients. Pleased to hear its all making sense now :)

Hey --

Thanks so much! I didn't realize I needed the gradientBox!

Rich


"GWD" <webforumsuser@macromedia.com> wrote in message
news:gll1om$o09$1@forums.macromedia.com...
> Give this a try:
>
>
> var m:Matrix = new Matrix();
>
> m.createGradientBox(200,100,0,0,0);
>
> var s:Shape = new Shape()
> addChild(s)
>
> s.graphics.beginGradientFill('linear',[0xff0000,0x0000ff,0x00ff00],[1,1,1],[0,12
> 8,255],m)
> s.graphics.drawRect(0,0,200,100)
>
> //above works fine because the gradient box defines the fill for the
> target
> rectangle.
> //you need the fill matrix to be correct for each different target
> location.
> //e.g. draw another box further over at x=300
> //need to transform (simple translate in this case) the gradient matrix to
> the
> new location
> m.translate(300,0)
> //the above is just using the original matrix and moving it to target the
> new
> location
> //you could also create a new one specifically for the new target if that
> made
> more sense
>
> s.graphics.beginGradientFill('linear',[0xff0000,0x0000ff,0x00ff00],[1,1,1],[0,12
> 8,255],m)
> s.graphics.drawRect(300,0,200,100)
>

Give this a try:


var m:Matrix = new Matrix();

m.createGradientBox(200,100,0,0,0);

var s:Shape = new Shape()
addChild(s)
s.graphics.beginGradientFill('linear',[0xff0000,0x0000ff,0x00ff00],[1,1,1],[0,128,255],m)
s.graphics.drawRect(0,0,200,100)

//above works fine because the gradient box defines the fill for the target rectangle.
//you need the fill matrix to be correct for each different target location.
//e.g. draw another box further over at x=300
//need to transform (simple translate in this case) the gradient matrix to the new location
m.translate(300,0)
//the above is just using the original matrix and moving it to target the new location
//you could also create a new one specifically for the new target if that made more sense
s.graphics.beginGradientFill('linear',[0xff0000,0x0000ff,0x00ff00],[1,1,1],[0,128,255],m)
s.graphics.drawRect(300,0,200,100)