How to use HTML5 to create an empty movie clip and add it to the stage

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How to create a new movie clip using HTML5 code.

And add movie clips to the Stage.

I also need to name movie clips.

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Colin HolgateCorrect answer

Inspiring

I don't think you can access a movieclip using a property value that you have set. And Animated_Container is a variable that belongs in the current context, exportRoot doesn't know about that variable either.

If you need everything to be global, you could do this:

exportRoot.Animated_Container = new createjs.MovieClip();
exportRoot.Animated_Container.name = "Co_name";
exportRoot.addChild(exportRoot.Animated_Container);
exportRoot.Animated_Container.addChild(new createjs.MovieClip());

The name property won't be needed.

What's the reason you need to involve exportRoot?

kglad

Community Expert

var mc = new createjs.MovieClip();

mc.name="mc_name";

this.addChild(mc);

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chenjil43641795Author

Legend

Thank you for your reply.

I use that name.(exportRoot.this name)

But the name is undefined

var Animated_Container = new createjs.MovieClip();
Animated_Container.name="Co_name";
exportRoot.addChild(Animated_Container);

console.log(exportRoot.Co_name)
exportRoot.Co_name.addChild(new lib.child_mc1());

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Colin HolgateCorrect answer

Inspiring

I don't think you can access a movieclip using a property value that you have set. And Animated_Container is a variable that belongs in the current context, exportRoot doesn't know about that variable either.

If you need everything to be global, you could do this:

exportRoot.Animated_Container = new createjs.MovieClip();
exportRoot.Animated_Container.name = "Co_name";
exportRoot.addChild(exportRoot.Animated_Container);
exportRoot.Animated_Container.addChild(new createjs.MovieClip());

The name property won't be needed.

What's the reason you need to involve exportRoot?

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