Recognise word in text block and then change it's colour

i don't really understand what you're attempting there? with the code you've written your checking sequence is always going to come up with correct. this is because you're setting a variable to something and then checking if it equals that same something... make sense? eg. in simple terms you've said:
a=b
if a==b ...

(if you're confused i'm referring to the following line, when j=0)
if (myArr == searchString) {

in addition you've set a variable matchesFound that though it may been a good idea, you're not using elsewhere...

ok i see you're trying though, yet struggling, so i think it might be time for another big push in the right direction. remember when i said this?
>>>>but probably an easier way is set them both Array.toString() because you can compare two strings to eachother. eg. if (array1.toString()==array2.toString()) {

here's an implementation of that(see attached code). the main differences are:
as i suggested in an earlier post, i've initialised the wordSelected array with false.
i've set the text field to a shorter sentence to make this simpler for testing.
i've created an array called correctWordSelected which you'll have to update with the words that should be selected.
the checking code compares the two arrays by converting them to strings first.
i've changed the selection color to red for no apparent reason...

Ok I've been reading through LiveDocs and am about to get to Loops, but I came across Switches and was wondering if we could use this when the check button is clicked:

switch (condition) {

case A :
(this._parent.textbox.wordSelected[2]!=true || this._parent.textbox.wordSelected[4]!=true)
_root.feedback.gotoAndStop("correct");
break;

default :
_root.feedback.gotoAndStop("incorrect");
break;
}

I'm not sure what the condition would be, but i noticed in LiveDocs they had an example where if you didn't click any keyboards keys then the code automatically went to "default", so I was wondering if we could do the same here.

But I'll be reading up on loops tomorrow, but for now it's home time :)

ok if you need to check not only that some words are selected but also that some words are not, then your checking section is just going to have to be a longer if statement. perhaps something like:

if (this._parent.textbox.wordSelected[2]==true && this._parent.textbox.wordSelected[4]==true && this._parent.textbox.wordSelected[5]!=true && etc) {
//correct words selected
}

by the way, i am writing !=true instead of ==false because we don't have any initialisation of these variables at the beginning. how the code is set up at the moment, if a word is not selected it could either equal false, or undefined. initialisation would involve a for loop looping through all the variables in the array(of which there are as many as there are words in the text box) and setting them all to false. if you did this, then you could set up your checking code differently.

for example, you could set up a 'correct words' array(which is basically how you want your 'selected words' array to look when the correct words are selected). you could then check if your 'selected words' array is equivalent to the correct words array. unfortunately you can't just say if (array1==array2) - well you can but two identical arrays won't return true.

its okay though - there are ways you can do this. you could use a for loop to loop through both arrays comparing each element to the equivalent in the other array looking for discrepancies. but probably an easier way is set them both Array.toString() because you can compare two strings to eachother. eg. if (array1.toString()==array2.toString()) {

see how you go with that information...

it really depends what words are selected...?

do you understand that i was saying that what you wrote:
>>if (this._parent.textbox.wordSelected[2]!=true || this._parent.textbox.wordSelected[4]!=true) {

...can be translated into english like so:
if the second word is not selected or the fourth word is not selected(or neither!)