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Z
zerops
Participant
December 21, 2008
Question

Trouble with IF

  • December 21, 2008
  • 3 replies
  • 566 views
Hi,

I am having trouble with the 'if' statement. Whenever I try to use 'if' for input text it doesn't work. EX. I make an input box and give it a var name of userInput. then i'll code:

if (userInput == 350){
output = "You just entered three fifty!";
} else {
output = "Cool";
}

but it won't work. what am i doing wrong?
This topic has been closed for replies.

3 replies

Z
zeropsAuthor
Participant
December 21, 2008
I don't actually get an actionscript error it just doesn't pay any attention to my 'if' it just will do what the 'else' commands.
I
ihong7
Inspiring
December 21, 2008
whats the error?
N
Newsgroup_User
Inspiring
December 21, 2008
You should avoid using variable names for text fields. Instead give them a
regular instance name, and access the text through the text property of the
instance. So erase get rid of the var and change the instance to userInput -
then:

if(userInput.text == "350"){
output.text = "you entered 350";
}else{
output.text = "cool";
}

--
Dave -
www.offroadfire.com
Head Developer
http://www.blurredistinction.com
Adobe Community Expert
http://www.adobe.com/communities/experts/


Z
zeropsAuthor
Participant
December 21, 2008
quote:
Originally posted by: Newsgroup User
You should avoid using variable names for text fields. Instead give them a
regular instance name, and access the text through the text property of the
instance. So erase get rid of the var and change the instance to userInput -
then:

if(userInput.text == "350"){
output.text = "you entered 350";
}else{
output.text = "cool";
}

--
Dave -
www.offroadfire.com
Head Developer
http://www.blurredistinction.com
Adobe Community Expert
http://www.adobe.com/communities/experts/




i tried that and it didn't work for me. I don't know what i'm doing wrong.

A
Anonymous
December 22, 2008
Since you sar var name rather than instance name in your post, try:

if(userInput == "350"){
output.text = "you entered 350";
}else{
output.text = "cool";
}

In other words, leave off the .text
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