ArrayEach

Question

How do you break out of the arrayEach function - stop execution?break acts like continueCode myArray = [ 1, 2, 3, 4, 5, 6, 7, 8, 9 ]; writeoutput("

Loop

"); for ( counter=1; counter<=arrayLen(myArray); counter++ ) { thisElement = myArray[counter]; if ( counter == 5 ) { continue; } if ( counter == 8 ) { break; } outString = counter & " : " & thisElement & "
"; writeOutput(outString); }; writeoutput("

"); counter = 0; arrayEach( myArray , function( thisElement ){ counter += 1; if ( counter == 5 ) { continue; } if ( counter == 8 ) { break; } outString = counter & " : " & thisElement & "
"; writeOutput(outString); }); OutputLoop 1 : 1 2 : 2 3 : 3 4 : 4 6 : 6 7 : 7 ArrayEach 1 : 1 2 : 2 3 : 3 4 : 4 6 : 6 7 : 7 9 : 9 this should not be here Answer would be much appreciated, no documentation.

BKBK · Accepted Answer

Hi martiehen2,One key consideration: we should, optimally, use language features as documented. By that I mean, as they are designed to be used and according to the official documentation. This is especially relevant in a weakly-typed language like ColdFusion. Accordingly, in ColdFusion, break;/ and continue;/ are designed to be used in ordinary loops, not in iterative loops such as arrayEach() and structEach(). So, even if break; or continue; worked in an iterative loop, I wouldn't use it. I would think of it as suboptimal and risky, what is usually called 'undocumented'. Much like isDate('1a') or isDate('2p'), which return True.

WolfShade · Answer

arrayEach doesn't have a break out. Much like a forEach loop, it iterates over everything. The only way to break out is to throw an exception. Same for .map() or arrayMap(). Or so I understood. Didn't think a continue would work within an arrayEach, but apparently it does.

If you want something that you can break out of, a for loop is probably best.

V/r,

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