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cfloop over cfif

Forum|Forum|16 years ago
December 29, 2009
2 replies
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I have a group of variables that I want to perform the same cfif statement for. I don't know the correct syntax for it and can't seem to find it anywhere. I know the code below doesn't work, but it shows what I'm trying to do.

How do I combine text and a variable together such as URL.#cookieName#?

<cfloop index="cookieName" list="myPro,myPub,myUni,myLes,peerPro,peerPub,peerUni,peerLes">

<cfif StructKeyExists(URL, "#cookieName#") AND URL.#cookieName# EQ "t" AND COOKIE.#cookieName# EQ "on">

<cfset COOKIE.#cookieName# = "off">

<cfelseif StructKeyExists(URL, "#cookieName#") AND URL.#cookieName# EQ "t" AND COOKIE.#cookieName# EQ "off">

<cfset COOKIE.#cookieName# = "on">

</cfif>

</cfloop>

This topic has been closed for replies.

Correct answer BKBK

<cfloop index="cookieName" list="myPro,myPub,myUni,myLes,peerPro,peerPub,peerUni,peerLes">

<cfif StructKeyExists(URL, cookieName) AND URL[cookieName] EQ "t" AND COOKIE[cookieName] EQ "on">

<cfset COOKIE[cookieName] = "off">

<cfelseif StructKeyExists(URL, cookieName) AND URL[cookieName] EQ "t" AND COOKIE[cookieName] EQ "off">

<cfset COOKIE[cookieName] = "on">

</cfif>

</cfloop>

Inspiring

One of the "little secrets" of ColdFusion is that a "struct" is actually like what would be called a "hash" in other languages. It supports a hybrid syntax, so that mystruct.foo and mystruct['foo'] are the same. The very important difference in the second syntax-form is that the index can be specified using another variable or by any arbitrary expression, e.g. "bar = 'foo'; mystruct[bar]"

Community Expert

Correct answer

Community Expert

<cfloop index="cookieName" list="myPro,myPub,myUni,myLes,peerPro,peerPub,peerUni,peerLes">

<cfif StructKeyExists(URL, cookieName) AND URL[cookieName] EQ "t" AND COOKIE[cookieName] EQ "on">

<cfset COOKIE[cookieName] = "off">

<cfelseif StructKeyExists(URL, cookieName) AND URL[cookieName] EQ "t" AND COOKIE[cookieName] EQ "off">

<cfset COOKIE[cookieName] = "on">

</cfif>

</cfloop>

Lee CrockettAuthor

Known Participant

Thanks, that does the trick. I looked all over for how to write that and just couldn't find it.