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A
Anonymous
October 20, 2009
Question

how do I pass a username form variable from a drop down list/menu to another page?

  • October 20, 2009
  • 1 reply
  • 658 views

Hi,

I have a login_success.php page that has a drop down list/menu (which lists usernames). I want the user to click on their user name, and when they click the submit button the username information to be passed over to the username.php page which will contain a recordset, sorted by username.

How do I pass the username info from the drop down list/menu to the username.php page?

The drop down menu is connected to a recordset listUsername, I have filtered the recordset with the Form Variable = username, and I have used the POST method to send the username to the page username.php. I'm not sure how to structure the php or which page to place it on.

<form id="form1" name="form1 method="post" action="username.php">

     <label for="username_id">choose username:</label>

     <select name="username_id" id-"username_id">

          <option value="1">username1</option>

          <option value="2">username2</option>

          <option value="3">username3</option>

          <option value="4">username4</option>

     </select>

     <input type="submit" name="send" id="send" value="Submit" />

     <input type="username" type="hidden" id="username" value="<?php echo $row_listUsername['username']; ?>" />

</form>

Could somebody help me please?

Thanks.

This topic has been closed for replies.

1 reply

A
Anonymous
October 21, 2009

I would not post the variable over, In this case I personally would send it through the URL and use the $_GET method to retreve it. For Example.

<html>
     <head>
          <title>Test Page</title>
          <script type="text/javascript">
               function userID(){
                    //var ID = form1.userIDs.selectedIndex;
                    var user = form1.userIDs.options[form1.userIDs.selectedIndex].value;
                    window.location = "test.html?userID=" + user;
               }
          </script>
     </head>
     <body>
          <form id="form1">
               <select name="userIDs" id="userIDs" onchange="userID();">
                    <option>Select a User</option>
                    <option value="1">User 1</option>
                    <option value="2">User 2</option>
                    <option value="3">User 3</option>
                    <option value="4">User 4</option>
               </select>
          </form>
     </body>
</html>

//PAGE TO RETRIEVE THE USERNAME
<?php
if(isset($_GET['userID'])
{
     $userID = $_GET['userID'];
     echo $userID;
     die;
}

A
Anonymous
October 21, 2009

Hi Cody.Rob,

thanks for getting back to me, I'm really new to PHP and I don't know anything about JavaScript.

I noticed in your sample code that the method and action aswell as the submit button had been left out. If I use the Get method to retrieve the code on my second page how do i send it from the first page?

Do I add the userIDs record primary key to a query string and pass it through a link instead of a submit button?

Thanks.

A
Anonymous
October 21, 2009

You could, perhaps, store the value in a session?

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