How to show all records by default on search result page?
Hi
I am trying to make a search page that would execute the search in the database based on one or more field constraints.
(Using MySQL,PHP)
I have 2 columns in the database "vm_ip" (primary key) <IP address>, "Operating_System" <Any, Windows, Solaris, AIX>
need to search vm_ip based on other two fields.
PROBLEM: Need to show all the record when I select "Any" in the Operating_System drop down menu.
<p>Operating System:
<select name="os_select" id="os_select">
<?php
$os_count=1;
foreach($os_type as $value) //(os_type is array with possible values of OS)
{
echo "<option value=".$os_count.">".$value."</option>";
$os_count++;
}
?>
<option value=" " selected="selected">Any</option>
</select>
</p>
this code POSts NULL value to the search page.
Below code is of recordset on search page
$varOS_virtual = "Operating_System"; // recordset variable set to same as column name (default value) if (isset($_POST['os_select'])) //this should not be true
{ $varOS_virtual = $_POST['os_select']; }
mysql_select_db($database_xyz_db, $xyz_db); $query_virtual = sprintf("SELECT table.VM_IP FROM table
WHERE table.Operating_System=%s", GetSQLValueString($varOS_virtual, "int"));
$virtual = mysql_query($query_virtual, $xyz_db) or die(mysql_error()); $row_virtual = mysql_fetch_assoc($virtual); $totalRows_virtual = mysql_num_rows($virtual);
I expected the 'os_select' field to be null and default value of Operating_System to be "Operating_System" so that the Query shows all records.
But instead the value being passed in the Query is "0". and no records are shown.
What can I do to show all records?
As probably obvious I am new to php/MySQL so all the help is most welcomed .
Thanks