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August 21, 2009
Question

PHP / MySQL Update Query

Hi guys,

Probably an easy one:

I have a script.php page that creates a directory, made up of an Order Number and a Document Title.

The script.php page also has a Record set (rsProjects), which is filtered from a Form Variable (order).

What I need to happen is that if the MKDIR is sucessful, then UPDATE tbl_projects SET projdir='y' WHEN projid=colname ? ? ?

Here's the code:

(SCRIPT.PHP)

<?php
// URL
$url = "/Server/Folder1/Folder2/". $_POST['order']." ".$_POST['documentname'];

// Create It
$create = mkdir("$url");
          mkdir("$url/Incoming");
          mkdir("$url/Outgoing");
          mkdir("$url/Work");

if($create)
{$mess = "<p>Directory created<p>"; }
else
{$mess = "<p>Directory could not be created, this may be due to the possibility of the directory already exisiting on the Server. Please check the Folder2 directory. Alternatively, contact the Administrator</p>"; }
?>
<?php require_once('../Connections/conndb2.php'); ?>
<?php
if (!function_exists("GetSQLValueString")) {
function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
{
  $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;

  $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);

  switch ($theType) {
    case "text":
      $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
      break;   
    case "long":
    case "int":
      $theValue = ($theValue != "") ? intval($theValue) : "NULL";
      break;
    case "double":
      $theValue = ($theValue != "") ? "'" . doubleval($theValue) . "'" : "NULL";
      break;
    case "date":
      $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
      break;
    case "defined":
      $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
      break;
  }
  return $theValue;
}
}

$colname_rsProjects = "-1";
if (isset($_POST['order'])) {
  $colname_rsProjects = $_POST['order'];
}
mysql_select_db($database_conndb2, $conndb2);
$query_rsProjects = sprintf("SELECT * FROM tbl_projects WHERE projid = %s", GetSQLValueString($colname_rsProjects, "int"));
$rsProjects = mysql_query($query_rsProjects, $conndb2) or die(mysql_error());
$row_rsProjects = mysql_fetch_assoc($rsProjects);
$totalRows_rsProjects = mysql_num_rows($rsProjects);
?>

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1 reply

August 24, 2009

http://www.sitepoint.com/forums/showthread.php?t=633695&goto=newpost

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