Using PHP variable inside MySQL recordset

Okay,

sorry folks, Ignore my last message. I seem to have been a bit stupid here. Thanks to the { } revelation i've now realised I can do exactly what I want in a more direct way - by incorporating the input form the drop down menu directly into the recordset like this:

FROM rsca_users WHERE rsca_public_region = %s AND rsca_public_{$_POST['qualification']}

Which I'm sure will work but I when I open the page now I get
An error message "Unknown column 'rsca_public_' in 'where clause'."

I guess the page is try ing to create the recordset and not finding a value for $_POST['qualification'] as it hasn't been submitted yet.

I tested that theory by adding a line that assigns $_POST['qualification'] a value at the top of the page and the page opens but the drop down menu doesn't seem to change $_POST['qualification'] after that.

I could really do with a little pointer here as I'm not sure where to look for the solution.

Cheers


Dave

Any chance you can help me with phase 2.
I'm trying to get determine $qualificationchoice by the setting of a form menu $_POST['qualification']

I know I'm close but it just won't quite work

Here's what I have right now:

*************************
if (isset($_POST['qualification'])) {
$colname2_rs_Instructorsearch = (get_magic_quotes_gpc()) ? $_POST['qualification'] : addslashes($_POST['qualification']);
}
//code to set qualification choice
if($_POST['qualification']==1) {$qualificationchoice="CWA";}
elseif ($_POST['qualification']==2) {$qualificationchoice="SPA";}
elseif ($_POST['qualification']==3) {$qualificationchoice="WGL";}
elseif ($_POST['qualification']==4) {$qualificationchoice="ML";}
elseif ($_POST['qualification']==5) {$qualificationchoice="MLW";}
elseif ($_POST['qualification']==6) {$qualificationchoice="MIA";}
elseif ($_POST['qualification']==7) {$qualificationchoice="MIC";}
elseif ($_POST['qualification']==8) {$qualificationchoice="guide";}
// code to set qualification choice ends

$colname_rs_Instructorsearch = "-1";
if (isset($_POST['region'])) {
$colname_rs_Instructorsearch = (get_magic_quotes_gpc()) ? $_POST['region'] : addslashes($_POST['region']);
}
mysql_select_db($database_con_rsca, $con_rsca);
$query_rs_Instructorsearch = sprintf("SELECT * FROM rsca_users WHERE rsca_public_region = %s AND rsca_public_{$qualificationchoice} = 1 AND rsca_public_listme =1 AND expired =0", GetSQLValueString($colname_rs_Instructorsearch, "text"));
$rs_Instructorsearch = mysql_query($query_rs_Instructorsearch, $con_rsca) or die(mysql_error());
$row_rs_Instructorsearch = mysql_fetch_assoc($rs_Instructorsearch);
$totalRows_rs_Instructorsearch = mysql_num_rows($rs_Instructorsearch);
?>

*************************************

Any suggestion would be great

Thanks


Dave

Thanks 10191 - the { } tip worked brilliantly!!

davecheet wrote:
> The code below is what I have at present but it white
> screens me when I try open it the page in the browser.

Getting a white screen means that you don't have display_errors turned
on in your development environment. If you did, you would see that the
problem is a syntax error, caused by your use of quotes. Remove the
quotes from around $qualificationchoice.

--
David Powers
Adobe Community Expert, Dreamweaver
http://foundationphp.com

maybe try {$qualificationchoice}