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land_down_under
Participant
June 27, 2006
Question

bandwidth? flash media server? hosting service??

  • June 27, 2006
  • 2 replies
  • 347 views
HI All
We have a potential client who is looking at putting a number of courses available on-line (from traditional face to face teaching)
THe online version would be a series of videos (flv) along with corresponding slides (jpgs) at cue points
The flvs are encoded using on2vp2 codec @256k
In order that say 10 web users can access the content at the same time, and with the same bandwidth of delivery (i.e 256k), what do i need (i.e my internet service provider or potentially the client themselves) to support this??

a) 256k * 10 = 2.56Mb bandwidth (pipe)??
b) flash media server??
c) dedicated server???

Any suggestions or help would be welcomed in solving this
-C

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    2 replies

    egyserv
    Known Participant
    July 5, 2006
    for the On demand Video (one to many) Here is the Formula

    Bws: bandwidth of the server that u need for ur application

    N = Number of users
    S = Stream encoded Constant kbps

    Bws = N*S

    The Formula of the Many to Many video
    BWS=(P*N)*S
    P= Number of the Puplisher (who is using a camera )
    N= Number of Subscriper [ all the the users who have cam or havn't]
    S == Stream encoded Constant kbps

    if u see its the same formula but in case 1 the puplisher always = 1 thats why we didnt put it in the formula for the one to many

    to find a good shared hosting services with good prices
    http://www.influxis.com

    and my company soon ;) but im still building my own Control panel for the shared Flash Media server hosting

    Before i go to calculate your Data Transfer per month use this formula

    Datatransfer per month with bits= N*S*Month with seconds
    month with seconds = 60*60*12*30

    thats how to have an application strategy
    Note: this Data transfer will be at most [ if the Number of users will be Connected every second in the month]
    try to guss how long the user will be online or try to find average for the time beeing connectted with this Users Number

    i wish thats will help
    land_down_underAuthor
    Participant
    July 5, 2006
    Cheers for that :-)
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