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timesheet calculations

Guest
May 21, 2019 May 21, 2019

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I know this topic has been covered extensively but I have spent too much time searching past questions/answers.  If anyone can point me to the right place I would much appreciate it. 

I am creating a timesheet in PDF form and although I can calculate the difference in starttime, lunchout, lunchin, endtime the result does not format properly.

Instead of getting say 5.5 hrs the result is 5.30 hrs.   7:00 starttime; 10:30 lunchout; 11:00 lunchin; 13:00 endtime.

Here's my code so far:

// start
var start = this.getField("Start1_1").value;
var startArr = start.split(":");

//lunchout
var lunchout = this.getField("LunchOut1").value;
var lunchoutArr = lunchout.split(":");

//lunchin
var lunchin = this.getField("LunchIn1").value;
var lunchinArr = lunchin.split(":");

// finish
var finish = this.getField("End1_1").value;
var finishArr = finish.split(":");

// difference
var hourDiff = Math.abs(lunchoutArr[0] - startArr[0])+ Math.abs(finishArr[0]-lunchinArr[0]);
var minDiff = (Math.abs(lunchoutArr[1]-startArr[1])+ Math.abs(finishArr[1]-lunchinArr[1])/60*100);
if (minDiff.toString().length == 1)
    minDiff = '0' + minDiff;

var output = hourDiff + "." + minDiff;
event.value = output;

Thanks so much for any assistance.  I really need to get this finished.

Lynda

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Acrobat SDK and JavaScript , Windows

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correct answers 1 Correct answer

Community Expert , May 21, 2019 May 21, 2019

Change this:

var output = hourDiff + "." + minDiff;

To:

var output = hourDiff + (minDiff/60);

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Community Expert ,
May 21, 2019 May 21, 2019

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Change this:

var output = hourDiff + "." + minDiff;

To:

var output = hourDiff + (minDiff/60);

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Guest
May 21, 2019 May 21, 2019

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You are my new best friend!!!!

Thank you so much. : )

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Guest
May 21, 2019 May 21, 2019

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Oy, now I need to adjust the code to allow NO lunch break.  Any suggestion?

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Community Expert ,
May 21, 2019 May 21, 2019

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You need to be more specific than that.

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Guest
May 22, 2019 May 22, 2019

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Of course, sorry.

I need to modify this code in the event that the employee does not take a lunch break.

// start
var start = this.getField("Start1_1").value;
var startArr = start.split(":");

//lunchout
var lunchout = this.getField("LunchOut1").value;
var lunchoutArr = lunchout.split(":");

//lunchin
var lunchin = this.getField("LunchIn1").value;
var lunchinArr = lunchin.split(":");

// finish
var finish = this.getField("End1_1").value;
var finishArr = finish.split(":");

// difference
var hourDiff = Math.abs(lunchoutArr[0] - startArr[0])+ Math.abs(finishArr[0]-lunchinArr[0]);
var minDiff = (Math.abs(lunchoutArr[1]-startArr[1])+ Math.abs(finishArr[1]-lunchinArr[1])/60*100);
if (minDiff.toString().length == 1)
    minDiff = '0' + minDiff;

var output = hourDiff + (minDiff/60);
event.value = output;

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Community Expert ,
May 22, 2019 May 22, 2019

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Yeah, you need to modify it quite a bit. Especially the lines where you calculate the hourDiff and minDiff variables.

You should break them up into smaller calculations and then you'll be able to check if the lunch fields are empty or not, before including the results in this formula.

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Guest
May 22, 2019 May 22, 2019

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Thanks.  Took a stab at it: (I get an error that there's a missing ';' at line 15 but I'm not seeing the problem.

// start

var start = this.getField("Start1_1").value;

var startArr = start.split(":");

//lunchout

var lunchout = this.getField("LunchOut1").value;

var lunchoutArr = lunchout.split(":");

//lunchin

var lunchin = this.getField("LunchIn1").value;

var lunchinArr = lunchin.split(":");

// finish

var finish = this.getField("End1_1").value;

var finishArr = finish.split(":");

// difference in start/finish time

var hourWDiff = Math.abs(finishArr[0] - startArr[0]);

var minWDiff = finishArr[1] - startArr[1])/60*100);

//difference in lunchin/lunchout time

var hourLDiff = Math.abs(lunchoutArr[0] - lunchinArr[0]);

var minLDiff = (Math.abs(lunchoutArr[1] - lunchinArr[1])/60*100);

if (minWDiff.toString().length == 1)

    minWDiff = '0' + minWDiff;

if (minLDiff.toString().length == 1)

    minLDiff = '0' + minLDiff;

var totalHrs = hourWDiff + (minWDiff/60) + hourLDiff + (minLDiff/60);

var output = totalHrs;

event.value = output;

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Community Expert ,
May 22, 2019 May 22, 2019

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The problem is with this line:

var minWDiff = finishArr[1] - startArr[1])/60*100);

You're missing the opening parenthesis.

You still have the it too mixed up. Separate the part that calculates the lunch time entirely from the rest of the calculation.

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Guest
May 22, 2019 May 22, 2019

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Thanks - I couldn't see that.

I'm not a javascript programmer and I sure appreciate your help. 

Do  you have time to suggest a solution?

// start

var start = this.getField("Start1_1").value;

var startArr = start.split(":");

//lunchout

var lunchout = this.getField("LunchOut1").value;

var lunchoutArr = lunchout.split(":");

//lunchin

var lunchin = this.getField("LunchIn1").value;

var lunchinArr = lunchin.split(":");

// finish

var finish = this.getField("End1_1").value;

var finishArr = finish.split(":");

// difference in start/finish time

var hourWDiff = Math.abs(finishArr[0] - startArr[0]);

var minWDiff = (Math.abs(finishArr[1] - startArr[1])/60*100);

//difference in lunchin/lunchout time

var hourLDiff = Math.abs(lunchoutArr[0] - lunchinArr[0]);

var minLDiff = (Math.abs(lunchoutArr[1] - lunchinArr[1])/60*100);

if (minWDiff.toString().length == 1)

    minWDiff = '0' + minWDiff;

if (minLDiff.toString().length == 1)

    minLDiff = '0' + minLDiff;

var totalHrs = hourWDiff + (minWDiff/60) + hourLDiff + (minLDiff/60);

var output = totalHrs;

event.value = output;

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Community Expert ,
May 22, 2019 May 22, 2019

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Try this:

var start = this.getField("Start1_1").value;

var finish = this.getField("End1_1").value;

if (start=="" || finish=="") event.value = "";

else {

    var lunchout = this.getField("LunchOut1").value;

    var lunchin = this.getField("LunchIn1").value;

    var startArr = start.split(":");

    var finishArr = finish.split(":");

    var hourWDiff = Math.abs(finishArr[0] - startArr[0]);

    var minWDiff = (Math.abs(finishArr[1] - startArr[1])/60*100);

    var hourLDiff = 0;

    var minLDiff = 0;

    if (lunchout!="" && lunchin!="") {

        var lunchoutArr = lunchout.split(":");

        var lunchinArr = lunchin.split(":");

        hourLDiff = Math.abs(lunchoutArr[0] - lunchinArr[0]);

        minLDiff = (Math.abs(lunchoutArr[1] - lunchinArr[1])/60*100);  

    }

    var totalHrs = hourWDiff + (minWDiff/60) + hourLDiff + (minLDiff/60);

    event.value = totalHrs;

}

I removed some lines that seems incorrect to me, and fixed one or two other small issues, as well.

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Guest
May 22, 2019 May 22, 2019

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Excellent! I just needed to change the ‘+’ to ‘-‘ in the totalHrs line at the end.

var totalHrs = hourWDiff + (minWDiff/60) - hourLDiff + (minLDiff/60);

Kudos : )

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Community Expert ,
May 22, 2019 May 22, 2019

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Well, that part I didn't change...

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New Here ,
Sep 14, 2021 Sep 14, 2021

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Im still having trouble using this code below. If you use anything outside of whole hours it breaks the calculations. Any suggestions?    Example: 1 = 08:00  2 = 12:00 3 = 13:30   4 = 17:00

Field 1 = Clock In

Feild 2 = Lunch out

Feild 3 = Lunch In

Feild 4 = Clock Out

 

var start = this.getField("1").value;

var finish = this.getField("4").value;

if (start=="" || finish=="") event.value = "";

else {

var lunchout = this.getField("2").value;

var lunchin = this.getField("3").value;

var startArr = start.split(":");

var finishArr = finish.split(":");

var hourWDiff = Math.abs(finishArr[0] - startArr[0]);

var minWDiff = (Math.abs(finishArr[1] - startArr[1])/60*100);

var hourLDiff = 0;

var minLDiff = 0;

if (lunchout!="" && lunchin!="") {

var lunchoutArr = lunchout.split(":");

var lunchinArr = lunchin.split(":");

hourLDiff = Math.abs(lunchoutArr[0] - lunchinArr[0]);

minLDiff = (Math.abs(lunchoutArr[1] - lunchinArr[1])/60*100);

}

var totalHrs = hourWDiff + (minWDiff/60) - hourLDiff + (minLDiff/60);

event.value = totalHrs;

}

Would also be nice if it could not be military time.

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Community Expert ,
Sep 14, 2021 Sep 14, 2021

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I recommend converting the strings to Date objects (using the scand method of the util object). That will give you full control over what format they have, and will make calculating time differences much easier.

 

If you're interested, I've actually created a (paid-for) tool that can do all of that for you. It doesn't have the lunch option built-in, but that's certainly something I can add for you. You can find it here:

https://www.try67.com/tool/acrobat-calculate-time-differences-in-a-worksheet

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Guest
May 21, 2019 May 21, 2019

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You are my new best friend!!! 

Thank you for saving me more time down the rat hole.

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