6 random numbers without repeat

[92244890john]

I'm trying to make a 6 digit random number generator between 1 and 48. When the user click a button 6 random numbers show up in 6 different textFeilds. The problem is that I don't want the same number twice. How can I generate 6 different random numbers without using return and breaking out of the function?

import flash.events.Event;

stop();

btn.addEventListener (MouseEvent.CLICK, random1);

function random1 (evt:Event) {

          display1.text = "";

          display2.text = "";

          display3.text = "";

          display4.text = "";

          display5.text = "";

          display6.text = "";

          var r1 = Math.floor(Math.random()*(1+48-1))+1;

          var r2 = Math.floor(Math.random()*(1+48-1))+1;

          var r3 = Math.floor(Math.random()*(1+48-1))+1;

          var r4 = Math.floor(Math.random()*(1+48-1))+1;

          var r5 = Math.floor(Math.random()*(1+48-1))+1;

          var r6 = Math.floor(Math.random()*(1+48-1))+1;

          if (r2 == r1 || r3 == r2 || r4 == r3 || r5 == r4 || r6 == r5) {

                    return;

          }

          var liste:Array = new Array();

          liste.push(r1,r2,r3,r4,r5,r6);

          liste.sort(Array.NUMERIC);

          display1.text = String(liste[0]);

          display2.text = String(liste[1]);

          display3.text = String(liste[2]);

          display4.text = String(liste[3]);

          display5.text = String(liste[4]);

          display6.text = String(liste[5]);

}

[Ned Murphy]

One way would be to create an array containing the numbers (do it with code to save typing), shuffle the array, and then pick the first 6 numbers out of it.

[Ned Murphy · Accepted solution]

Here's the code for the approach mentioned with your textfields included

btn.addEventListener (MouseEvent.CLICK, random1);

function random1 (evt:Event) {

    var nums:Array = new Array();

    // fill the array of numbers

    for(var i:uint=1; i<=48; i++){
        nums.push(i);
    }

    shuffle(nums);

    // grab the first six in the shuffled array

    var liste:Array = nums.splice(0,6);

    // assign the values to the textfields

    for(var j:uint=1; j<=6; j++){
        this["display"+String(j)].text = String(liste);
    }
}

function shuffle(a:Array) {
    var p:int;
    var t:*;
    var ivar:int;
    for (ivar = a.length-1; ivar>=0; ivar--) {
        p=Math.floor((ivar+1)*Math.random());
        t = a[ivar];
        a[ivar] = a

;
        a

= t;
    }
}

[robdillon]

Here's a simpler way to get six unique numbers:

var liste:Array = new Array();

var i:int = 0;

var r1:Number;

while (i<6)

{

               r1 = Math.floor(Math.random() * 48) + 1;

               if (i>0)

               {

                              if (liste.indexOf(r1) == -1)

                              {

                                             i++;

                                             liste.push(r1);

                              }

               }

                    else

               {

                              liste.push(r1);

                              i++;

               }

}

[vigneshvicky]

here the simplest way for 6 random non repeating numbers from 1 to 20  you need more u can add it into array

var arr:Array=new Array("1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19","20");

function randomize(a : * ,b : *) : int {

  return(Math.random() > .5) ? 1 : -1;

}

arr.sort(randomize);

txt1.text=arr[0];

txt2.text=arr[1];

txt3.text=arr[2];

txt4.text=arr[3];

txt5.text=arr[4];

txt6.text=arr[5];