Fixing an array index's out of range error

[saratogacoach]

Hi,

Am stuck in an eLearning project that I am working on and need some help fixing a 2007 error that seems to point to an index for an array being out of range.

Here is the previous posting where there are more details: http://forums.adobe.com/message/4685789#4685789

With much help (thank you once again kglad), the script looks like:

var index:int = 0;var numToDisplay:int = 10;var groupA:Array = ["1","2","3"]var groupB:Array = ["4","5","6"]var groupC:Array = ["7","8","9"]var word_array:Array = [];var i:int;for(i=0;i<3;i++){word_array.push(groupA[groupA.length*Math.random()]);}for(i=0;i<3;i++){word_array.push(groupB[groupB.length*Math.random()]);}for(i=0;i<3;i++){word_array.push(groupC[groupC.length*Math.random()]);}

This is used in another part of the script:

function randomWord() {    if(index<numToDisplay){        wordT.text=word_array[index++];        t.reset();        t.start();    } else {  wordT.text= "";    // display score    }    }

The error message (2007) points to:

wordT.text=word_array[index++];

When I trace (word_array)  I get

,,,,,,

,,,,,,,

,,,,,,,,

Out of range index for this array?

How can I fix this out of range index?

Any help appreciated.

[Ned Murphy]

Since there appear to be only 9 elements getting added to the array, and your numDisplay is set to be 10, your condition ( if(index<numToDisplay){ ) allows index++ to get to 10, which will be out of range for your array.  See if changing the value of numDisplay to 9 solves the problem.

[saratogacoach]

Thanks, Ned for this suggestion.

Changing to 9 does not prevent the error.

[kglad]

(that's my fault.  i forgot to include Math.floor to adjust those random numbers to ints.)