Best way to update images using PHP / MySQL?

Report · Mar 12, 2011

HI
I want to update images using PHP/MySQL, so users can update their images and maybe some other files but mainly images.
thanks

Report · Mar 12, 2011

Restrict access to page, create a form on your page, link form to php script that uploads file and updates database table where id in database table = session variable for logged in user.

Report · Mar 12, 2011

link form to php script that uploads file and updates database table

Thanks for the help, can you please give example of the upload script?

Report · Mar 13, 2011

How messed up is this code?!

<?php
//connect to database
$con = mysql_connect("testhost","testuser","pass");

// file properies
$file = $_FILES['image']['tmp_name'];

if (!isset($file))

echo "please select an image";

else {
    $id = $_REQUEST['id_display'];

    $image = ($_FILES['image']['tmp_name']) ? file_get_contents ($_FILES['image']['tmp_name']) : '';


    $image_name = ($_FILES['image']['name']) ? addslashes($_FILES['image']['name']): '';


    $image_size = ($_FILES['image']['tmp_name']) ? getimagesize($_FILES['image']['tmp_name']): '';

    if ($image_size == FALSE)
    echo "You have not selected an image.";

    else {
        mysql_select_db("test_display", $con);
        mysql_query("UPDATE testtable SET image = '$image', imagename = '$image_name' WHERE id_display='$id'");
         }
    }
?>

And the upload page....

<?php require_once('Connections/testconn.php'); ?>
<?php
if (!function_exists("GetSQLValueString")) {
function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") 
{
  if (PHP_VERSION < 6) {
    $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;
  }

  $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);

  switch ($theType) {
    case "text":
      $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
      break;    
    case "long":
    case "int":
      $theValue = ($theValue != "") ? intval($theValue) : "NULL";
      break;
    case "double":
      $theValue = ($theValue != "") ? doubleval($theValue) : "NULL";
      break;
    case "date":
      $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
      break;
    case "defined":
      $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
      break;
  }
  return $theValue;
}
}

$colname_Recordset1 = "-1";
if (isset($_GET['id_display'])) {
  $colname_Recordset1 = $_GET['id_display'];
}
mysql_select_db($database_testconn, $testconn);
$query_Recordset1 = sprintf("SELECT * FROM testtable WHERE id_display = %s ORDER BY id_display DESC", GetSQLValueString($colname_Recordset1, "int"));
$Recordset1 = mysql_query($query_Recordset1, $testconn) or die(mysql_error());
$row_Recordset1 = mysql_fetch_assoc($Recordset1);
$totalRows_Recordset1 = mysql_num_rows($Recordset1);
?>
/*Update code */
<?php
//connect to database
$con = mysql_connect("testhost","testuser","pass");

// file properies
$file = $_FILES['image']['tmp_name'];

if (!isset($file))

echo "please select an image";

else {
     $id = $_REQUEST['id_display'];
     
    $image = ($_FILES['image']['tmp_name']) ? file_get_contents ($_FILES['image']['tmp_name']) : '';
          
     
     $image_name = ($_FILES['image']['name']) ? addslashes($_FILES['image']['name']): '';
     
     
     $image_size = ($_FILES['image']['tmp_name']) ? getimagesize($_FILES['image']['tmp_name']): '';
     
     if ($image_size == FALSE)
     echo "You have not selected an image.";
     
     else {
          mysql_select_db("test_display", $con);
          mysql_query("UPDATE testtable SET image = '$image', imagename = '$image_name' WHERE id_display='$id'");
           }
     }
?> /*End update code */
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>upload an image</title>
</head>

<body>

<form action="image_upload.php" method="post" enctype="multipart/form-data">
  <p>
    <input name="name" type="text" id="name" value="<?php echo $row_Recordset1['name']; ?>" />
    <input name="hiddenField" type="hidden" id="hiddenField" value="<?php echo $row_Recordset1['id_display']; ?>" />
  </p>
  <p>
    <input name="image" type="file" id="image" />
    <input name="upload" type="submit" id="upload" value="upload" />
  </p>
</form>

</body>
</html>
<?php
mysql_free_result($Recordset1);
?>

Report · Mar 13, 2011

help!

Report · Mar 14, 2011

hi you can try this "how to update an image in mysql"

Report · Mar 16, 2011

Thank you adobemasterps

FINALLY
Thanks alot

Best way to update images using PHP / MySQL?

1 Correct answer

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