• Global community
    • Language:
      • Deutsch
      • English
      • Español
      • Français
      • Português
  • 日本語コミュニティ
    Dedicated community for Japanese speakers
  • 한국 커뮤니티
    Dedicated community for Korean speakers
Exit
0

Combining tables as a product list

Community Expert ,
Jan 08, 2013 Jan 08, 2013

Copy link to clipboard

Copied

I've been at this for about 4 days now. It's should be simple but I can't figure out how to display the data from a product table without duplicates. Here's a simplified description of what I've got.

Products table:

idProduct
1extra large shirt
2large shirt
3medium shirt
4small shirt

Colors Table

idColor
1red
2white
3

blue

Available Colors table

idproductIDColorID
111
212
313
421
523
632
741
842

Combining matching up the shirts and the colors is easy with a simple WHEN product.id = Available.productID AND color.id = Available.colorID

I get this result from the table:

Shirts:

  • Extra Large Shirt
    • Red
  • Extra Large Shirt
    • White
  • Extra large Shirt
    • Blue
  • Large Shirt
    • Red
  • Large Shirt
    • Blue
  • Medium Shirt
    • White
  • Small Shirt
    • Red
  • Small Shirt
    • Blue

Everything is correct but the display is awful as a list or a table. What I want is to eliminate the duplicate listing of the Shirt Type and end up with a clean list like this:

  • Extra Large Shirt
    • Red
    • White
    • Blue
  • Large Shirt
    • White
    • Blue
  • Medium Shirt
    • White
  • Small Shirt
    • Red
    • Blue

I've tried left join, unique, and if statements for hours. I've searched all over the web and I can't figure out how to get this code to work correctly.

Here's some code that produces the messy list:

<?php

echo '<ul>';

$sql = "SELECT *

FROM products, colors, available

WHERE products.id = available.productID

AND color.id = available.colorID

";

     $result = mysql_query($sql);

     echo '<ul>';

          if (mysql_num_rows($result) > 0) {

               while ($rec = mysql_fetch_assoc($result)) {

          echo '<li>', $rec['product'],

          '<ul><li>', $rec['color'],'</ul></li>';

     }

}

echo '</ul>';

?>

TOPICS
Server side applications

Views

745

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Guru ,
Jan 08, 2013 Jan 08, 2013

Copy link to clipboard

Copied

Have you tried SELECT DISTINCT

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Community Expert ,
Jan 08, 2013 Jan 08, 2013

Copy link to clipboard

Copied

Distinct will only return one value. It's got to be in the PHP loop. I'm working on that now. Still haven't got it.

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
LEGEND ,
Jan 08, 2013 Jan 08, 2013

Copy link to clipboard

Copied

PHP is not my strong suit, but try this:

<?php

echo '<ul>';

$sql = "SELECT *

FROM products, colors, available

WHERE products.id = available.productID

AND color.id = available.colorID";

     $result = mysql_query($sql);

     $last_product = ""

     echo '<ul>';

          if (mysql_num_rows($result) > 0) {

               while ($rec = mysql_fetch_assoc($result)) {

              if ($last_product <> $rec['product']){

            echo '<li>', $rec['product'];

        }

          echo '<ul><li>', $rec['color'],'</ul></li>';

    $last_product = $rec['product'];

     }

}

echo '</ul>';

?>

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Community Expert ,
Jan 08, 2013 Jan 08, 2013

Copy link to clipboard

Copied

LATEST

That was prety close. Here's the actual code that works. The tables are obviously different.

<?php

$sql = "SELECT

pvtDocLog.id, pvtDocLog.title,

bizCats.bcName,

docBizCats.bizCatID, docBizCats.assignedDocID

FROM pvtDocLog, bizCats, docBizCats

WHERE bizCats.id = docBizCats.bizCatID

AND pvtDocLog.id = docBizCats.assignedDocID

ORDER BY bizCats.id, pvtDocLog.id

";

$result = mysql_query($sql);

if(is_resource($result)){

    $results = array();

    while($rec = mysql_fetch_assoc($result)) {

        if(array_key_exists($rec['bcName'], $results)){

            array_push($results[$rec['bcName']], $rec['title']);

        }else{

            $results[$rec['bcName']] = array($rec['title']);

        }

    }

    echo '<ul>';

    foreach($results as $class => $names){

        echo '<li>'.$class.'<ul>';

        foreach($names as $name){

            echo '<li>'.$name.'</li>';

        }

        echo '</ul></li>';

    }

    echo '</ul>';

}

?>     

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
LEGEND ,
Jan 08, 2013 Jan 08, 2013

Copy link to clipboard

Copied

>I've tried left join, unique, and if statements for hours. I've searched all over

>the web and I can't figure out how to get this code to work correctly.

You're looking in the wrong place   The problem has nothing to do with your SQL. DISTINCT, LEFT or other modifications to your SELECT won't solve your problem - you are misunderstanding what they do. Your original SQL is fine.

You need to solve this in your PHP code. You can modify the code so it only prints the type the first time. Quite simply, in your loop you need to store the value of the ShirtType in a variable. Compare the value of this variable to the current record value and then supress the printing of the Type when the type has not changed since the last iteration.

Votes

Translate

Translate

Report

Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines