I realy think myButtons=app.documents[0].stories.everyItem().buttons; Is a much better way of getting a collection of the buttons in text boxes. I you want an array of all buttons then you can do this myButtons=[]; myButtons[0]=app.documents[0].stories.everyItem().buttons ; myButtons[1]=app.documents[0].buttons; Like this you don't waist the computers precious brain power on going though every page item and checking whether or now it is a button or not! Either way you  should mark what you consider as the correct answer. Trevor ... View more

To understand this make a doc with 3 buttons, 2 as regular buttons and 1 as an ancored object in a text frame. The following lines should be entered one at a time in the js console. app.documents[0].buttons.everyItem().fillColor="Black" app.documents[0].stories.everyItem().buttons.everyItem().fillColor="Black" app.documents[0].stories[0].buttons[0].fillColor="Paper" app.documents[0].buttons.length app.documents[0].stories.everyItem().buttons.length You should be able to figure out the rest by yourself Trevor ... View more

SRiegel Nice to see that somebody understood. ... View more

NO ... View more

A before and after screen shot would help ... View more

[Jongware] wrote: "This parameter has no effect unless the reference point is specified relative to a page." Did anybody figure this out yet? ... View more

Just putting the script together  with instruction as I made reference to it somewhere else. Instructions: Make a find change list either in the script of more efficiently with a tab delimitated .txt excel file Change the file path name in this line var filePath= "c:/Word Change List.txt"; // CHANGE TO CORRECT FILE NAME to the correct path. Make sure to have the / in the right direction. The normal search is semi-case sensitive i.e. will change if pussycat is the change from word then both pussycat and Pussycat would be changed PUSSYCAT or PussyCat would not. If Pussycat was the change word then only Pussycat would be changed and not pussycat. In other words the normal search will replace the word or the word with a capitol letter. If you want only the word changed but not the capitol form i.e. pussycat but not pussy cat then add the ` symbol (above the tab key on my keyboard) like this `pussycat If you want a non case sensitive find replace then add the ~ symbol like this ~pussycat this will change PUssycAt For a grep change add the ; symbol to the beginning of the grep. The excel file should be set up in this form The file doesn't actually have to be made in excell as long as the words are sepertated by tabs and the rows by returns and the file saved as a tab delimitated .txt file Enjoy // Made by Trevor http://forums.adobe.com/message/4602248#4602248 app.findTextPreferences = app.changeTextPreferences = null; app.changeGrepPreferences = app.findGrepPreferences = null; app.findChangeTextOptions.caseSensitive = 1; myDoc = app.documents[0]; /*  IF YOU DON'T WANT TO WORK WITH AN EXCEL FILE THEN DELETE THIS LINE !!!!!!! myChanges = [ 'over-sized' , 'oversize', '`pussy cat' , 'pussy', // Pussy cat will stay Pussy cat because of the ` tag 'CAT' , 'CAT®', 'school teacher' , 'schoolteacher', 'high schoolteacher' , 'high school teacher', ';(never)\\-(?=\\S)' , '$1' // Because of the ; (semicolon) tag will be dealt with as a grep ]; */ //  IF YOU DON'T WANT TO WORK WITH AN EXCEL FILE THEN DELETE THIS LINE !!!!!!! // /* IF YOU DON'T WANT TO WORK WITH AN EXCEL FILE THEN DELETE THE // AT THE BEGINING OF THIS LINE !!!!!!!     var filePath= "c:/Word Change List.txt"; // CHANGE TO CORRECT FILE NAME     var txtfFile=new File(filePath);     txtfFile.open();     fileContent = txtfFile.read();     txtfFile.close();     var myArrayString=fileContent.replace(/'/g, "QtQeQn4").replace(/\t/g, "','").replace (/\n/g, "' , '");     myArrayString=myArrayString.slice(0,-3);     eval ("var myChanges = ['"+myArrayString+"];");     $.writeln(myChanges);     for (var c=0; c<myChanges.length-1; c++) myChanges =myChanges .replace(/QtQeQn4/g, "'") // */ IF YOU DON'T WANT TO WORK WITH AN EXCEL FILE THEN DELETE THE // AT THE BEGINING OF THIS LINE !!!!!!! for (var c=0; c<myChanges.length;) { if  (myChanges [0] != "`" && myChanges [0] != ";" && myChanges [0] != "~") {     app.findChangeTextOptions.wholeWord = 1;     app.findTextPreferences.findWhat = myChanges ;     app.changeTextPreferences.changeTo = myChanges[c+1];     myDoc.changeText();     capitalChangeFrom =  myChanges [0].toUpperCase() + myChanges .slice(1,myChanges .length);     capitalChangeTo =  myChanges[c+1][0].toUpperCase() + myChanges[c+1].slice(1,myChanges[c+1].length);     app.findTextPreferences.findWhat = capitalChangeFrom;     app.changeTextPreferences.changeTo = capitalChangeTo;     myDoc.changeText(); } else if (myChanges [0] == "`") {     app.findChangeTextOptions.wholeWord = 1;     app.findTextPreferences.findWhat = myChanges .slice(1,myChanges .length);     app.changeTextPreferences.changeTo = myChanges[c+1];     myDoc.changeText(); } else if (myChanges [0] == "~") {     app.findChangeTextOptions.wholeWord = 0;     app.findTextPreferences.findWhat = myChanges .slice(1,myChanges .length);     app.changeTextPreferences.changeTo = myChanges[c+1];     myDoc.changeText(); } else {     app.findGrepPreferences.findWhat = myChanges .slice(1,myChanges .length);     app.changeGrepPreferences.changeTo = myChanges[c+1];     myDoc.changeGrep(); } c+=2; } ... View more

Hi Vamitul Start another thread. This question is a little bit off the topic Trevor ... View more

Sorry Julien Still not clear on what to need. Maybe try writing the problem in French, Marc's pretty fluent in French and there are quite a lot of French speakers that visit the Forum à bientôt Trevor ... View more

Ah Peter you didn't move the #targetengine "session" to page 1 ... View more

Hi Julien Nice to see you are still alive. I'm sorry I couldn't understand your English. Please can you write that again more clearly in a better English. Trevor ... View more

Very Nice, Just one last word before we meet again on a different post. I just looked over your greps Take this example and check your Green one for the same mistakes FAIL RED ([1-7]\d.\d\d%)|([0].\d\d%)|(-\d?\d.\d\d%) 1) This is going to fail on 80.53% the ([0].\d\d%) is going to "catch" the 0.53% You missed the little (big) mistake that I pointed out above need to add an ^ at the beginning of each  | or statement or bracket the or statements together and put the ^ (means beginning of line) at the beginning of the line 2) The or statement in this case don't need to be bracketed in this case, although doesn't harm (might slow things down slightly, not to sure) 3) The 0 does not need to be put in a [character class] 4) The . needs escaping \. otherwise it meens any character or space THIS IS AN IMPORTANT RULE The correct grep in this case would be ^([1-7]\d\.\d\d%|0\.\d\d%|-\d?\d\.\d\d%) or better still ^([1-7]\d\.\d\d|0\.\d\d|-\d?\d\.\d\d)% VERY WORTHWHILE READING LEARNING UP PETER KARHELS BOOK ON GREPS You can well see from this post how powerful Greps can be. Regards Trevor ... View more

Pleasure, glad it worked, there's a lot to learn on the forum. So just how long did it take to do the 1000 tables? ... View more

(Sorry about the hard to read code...for some reason it doesn't paste well into these forums??) I'll get back later ... View more

Can you do a little manual work and fomat 1 table as you want the final results (without the names of with them changed) You can use the ink dropper tool to make it quick. Send another screen shot and I'll be back in a few hours. This will help a lot Trevor ... View more

Hi Nate // Group labelled items spread by spread // ===================================== LABEL_PREFIX = ["kkk22_33_","Fred_55","George"]; // if you don't like Fred and George you can change to Marc & Trevor ;-) a=[]; var y=app.documents.length && app.activeDocument && app.activeDocument.spreads && LABEL_PREFIX.length; while (y--) { a =[]; var doc = app.documents.length && app.activeDocument,        spreads = doc && doc.spreads,         s = spreads ? spreads.length : 0, z, i, items;     while ( s-- )         {         items = spreads .pageItems.everyItem().getElements();         i = items.length;         z = 0;         while( i-- )             {             if( 0 != (t=items).label.indexOf(LABEL_PREFIX ) ) continue;             a [z++] = t;             }         z && spreads .groups.add(a );         } } a.length = 0; I tested this works for me ... View more

~ Trevor ~ wrote: Not tested so I may well (probably) have made some major goof . Well I did say probably! You can of course put Marc's code into a function like this // Group labelled items spread by spread // Functionized by Trevor // ===================================== MarcsGroupLabelledItemsSpreadBySpreadScript("kkk22_33_"); MarcsGroupLabelledItemsSpreadBySpreadScript("Nate"); MarcsGroupLabelledItemsSpreadBySpreadScript("Fred"); function MarcsGroupLabelledItemsSpreadBySpreadScript(LABEL_PREFIX) { var doc = app.documents.length && app.activeDocument,     spreads = doc && doc.spreads,     s = spreads ? spreads.length : 0,     items, a=[], t, i, z=0; while( s-- )     {     items = spreads .pageItems.everyItem().getElements();     i = items.length;     z = 0;     while( i-- )         {         if( 0 != (t=items).label.indexOf(LABEL_PREFIX) ) continue;         a[z++] = t;         }     z && spreads .groups.add(a);     a.length = 0;     } } This will work, but is not realy the way to go about things in bigger examples. This will make 3 seperate groups if you want to make one group containing all three lables then it won't work. I saw a few of major goofs (it was late and I was very tired) that I made in the origional script I posted but the basic idea of using a sub array is I think correct Trevor ... View more

Made a little (big) mistake in the grep I showed in the screenshot it should have had a ^ and been ^(([89]\d\.?\d*%)|100%) ~ Trevor ~ wrote: P.P.s. If you wanted all numbers above 80 to be green but not 80 then the grep would be too complicated for me to work out at this time of night. (in the morning should be a doddle) Wasn't such a doddle but the grep would be ^(80\.?(\d+)*(?=[1-9])\d*\%|8[1-9]\.?\d*?%|(9\d\.?\d*%)|100%) Of course one could just swap the colors and change the grep to ^([1-7]\d\.?d*%|80\.?0*%) ... View more

Hi Chris This is a better method. Leave the table style alone just set up the other styles Then apply this code myCells=app.documents[0].stories.everyItem().tables.everyItem().columns[0].cells.everyItem() myCells.appliedCellStyle="Cell Style 1"; myCells.cells.everyItem().clearCellStyleOverrides (1) This will just change the 1st column in every table but leave evrything else alone Trevor ... View more

Hi Chris, Oh dear I had to get up for something anyway presuming that you don't specifically need to make script, rather get the job done. This should take about 3 minutes BUT try it out first on a one page doc!!! before. 1) set up a character style call it "green" and use your wild imagination to define it's properties i.e. set the color to green. 2) set up a paragraph style and call it something like cell. set the text color to red and in the grep style do this!!!! 3) Set up another paragraph style call it something like cell2 (Yawn) set the color to black 4) Set up a cell style call it cell style 2 and set the paragraph style to cell2 5) Set up a cell style call it cell style 1 and set the paragraph style to cell 6) Set up a table style call it Table style 1 and do this !!!! Set the left column to cel style 1 and the body rows to cell style 2 Voila Now for the scripty bit something very ish like (NOT TESTED AT THIS TIME OF NIGHT) myDoc.tables.everyItem().appliedTableStyles="Table Style 1" Good Luck Trevor P.s. Learn Grep Styles, they can be very powerfull P.P.s. If you wanted all numbers above 80 to be green but not 80 then the grep would be too complicated for me to work out at this time of night. (in the morning should be a doddle) P.P.P.s I got my angelic wings ~ Trevor ~ because I couldn't get Trevor I didn't go mad but might have been already ... View more

Hi Chris, I'm going to sleep now, but if you could show a screen shot of a table or part of it then I'll try have some code in the morning. 2:35am in my part of the planet. Trevor ... View more

Hello Mad, ehr Chris, Welcome to the forum Why don't you just set up table styles with cell styles with paragraph styles with grep styles and character styles? That would be very stylish Should be easy to script and quick. Trevor ... View more

If the scripts are not too long and not too private it might help to post them ... View more

Hi Nate, This is how I would do it. Not tested so I may well (probably) have made some major goof . Marc, PLEASE, PLEASE let me know if you would have done this differently. Julien, Marc wrote you a nice little script here so maybe you could show him a little gratitude and say thank you and mark hi answer as correct. Regards Trevor Take note of the annotations // Group labelled items spread by spread // ===================================== var LABEL_PREFIX = ["kkk22_33_","Fred_55","George"]; // if you don't like Fred and George you can change to Marc & Trevor ;-) var doc = app.documents.length && app.activeDocument,     spreads = doc && doc.spreads,     s = spreads ? spreads.length : 0,     items, a=[], t, i, z=0, y=LABEL_PREFIX.length; // added y here while( y-- ) // added this loop a =[]; // to allow values to be assigned to the sub arrays. LINE A {     while( s-- )         {         items = spreads .pageItems.everyItem().getElements();         i = items.length;         z = 0;         while( i-- )             {             if( 0 != (t=items).label.indexOf(LABEL_PREFIX ) ) continue; // add the no matter what.             a [z++] = t; // see the y LINE B             }         z && spreads .groups.add(a ); // see the y. LINE C         // If you want all 3 lables in the same group then erase LINE A,  and Leave LINE B and LINE C as the were without the .         a.length = 0;         } } // see the  } ... View more

Hi Marc, That was a very clear explanation. I thought to add an explanation of the way you are using && as resourceful non standard shortcut. var doc = app.documents.length && app.activeDocument,     spreads = doc && doc.spreads,     s = spreads ? spreads.length : 0, doc is going to be assign to app.activeDocument only if the active document has a length to it, i.e. it has pages otherwise it's going to be made 0. spreads is going to be made doc.spreads if the document has a length to it and therefore doc is not 0, otherwise if doc is 0 then speads is going to be made 0. s is made spreads.length   if the the document has a length to it, otherwise it's going to be made 0 and the script would end here without giving any nasty error messages . The line z && spreads .groups.add(a); Is saying if the labels were found and therefore z is a positive integer then add to a to the group. The longer (albeit in this case just slightly) more commonly used for would be. if (z > 0) spreads .groups.add(a); Very coding! Please let me know if I explained something incorrectly. Regards Trevor ... View more

Hello Larry I'm not quite holding at the close to 4,000 post you have but this was not my 1st. I was using the advanced editor that's how the first snippet in the same post got formatted correctly, things seem to be a bit buggy on the forum lately see the tea cher bug that both Nekulus and myself had above. Saw some other post today were the word was split but with that one I can't know if it was a forum bug or a typo. Trevor ... View more