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cmoke73
Engagé
cmoke73
Engagé
Activité
sept. 24, 2020
01:19 AM
Oh, okay. But, shame on me, I can't make this adjustment to my script. 😞 Will try to understand the process in brians script with my mechanical brain... regards Andreas
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sept. 23, 2020
11:43 PM
Looks good Brian. I´ll try! Thanks in advance
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sept. 23, 2020
11:40 PM
Hi Uwe. This "special way" that I created the script is because the first step was to reach the groups as well. This resulted in this form. But good to know, your´s more elegant. 🙂 thanks!
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sept. 23, 2020
08:11 AM
Hi. I have an almost finished script. Unfortunately it doesn´t work like I want: var
myDoc = app.activeDocument
myParGroup = myDoc.paragraphStyleGroups;
myParStyles = myDoc.paragraphStyles.everyItem().name;
afGrArray = [], afArray = [], doubAfArray = [];
afGrNr = myDoc.paragraphStyleGroups.count();
for (s=0;s<myDoc.paragraphStyles.count(); s++) {
afArray.push(myParStyles[s]);
}
for (i=0 ; i<afGrNr; i++) {
afGr = myParGroup[i]; //.name + "\r"
afGrName = afGr.name;
afNr = myParGroup[i].paragraphStyles.count();
for (n = 0; n < afNr; n++) {
af = afGr.paragraphStyles[n];
afName = af.name;
afArray.push(afName);
}
}
function checkMultiple(element, index) {
for(t = 0; t < afArray.length;t++) {
for(u = 0; u < afArray.length;u++) {
if(u !== t) {
if(afArray[u] === afArray[t] ){
doubAfArray.push(afArray[t]);
break;
}
}
}
}
if(doubAfArray.length>0) {
alert(doubAfArray);
}
else {
alert('There are no double elements');
}
}
checkMultiple(); When I get the results they are double. Like "paragraphStyle 1paragraphStyle 5paragraphStyle 1paragraphStyle 5" Correct would be "paragraphStyle 1paragraphStyle 5". Why this doubling?
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sept. 10, 2020
06:15 AM
Okay guys. You´re right and I will do that. BUT: Can you explain the phenomenon to me I mentioned in my question?! Maybe it will still be useful at some point ...
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sept. 10, 2020
05:44 AM
I could, if I would want to replace it by a 100% opacity of the new swatch. But I need only 10% for this special element.
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sept. 10, 2020
01:58 AM
Hi. There are a lot of swatches in a larg document. Some of them were imported by accident. My intention is to replace some of them. For exemple I want to search for a solid color to change it into an existing swatch (CMYK - 10%). At the first time I´m searching it will be found. But then the index (yellow mark) of the colour shoud be search for will be increasing. And the searchengine doesn´t find anything. Can this index be deleted?
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sept. 07, 2020
11:46 PM
Hi Meenakshi My idea was something like to work with two documents in parallel, left and right. Than to switch off all colors but the key (black). Then, by simultaneous scrolling through the docs, to discover whether there is a deviation which would make trouble in the printing. It would be nice to have an add-in-tool in Acrobat that shows those possible variations. Is it science fiction? 🙂
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mai 07, 2020
01:08 AM
Hi Uwe. Ja, das ist wahr. Sollte auch nur ein Denkanstoß in eine verwertbare Richtung sein. Das Programm meiner Wahl wäre aber auch eher Illustrator. Früher in der Agentur haben wir das manuell gelöst: abmessen, ausschneiden, anpassen, übertragen. 🙂 Gruß an alle Beteiligten (Viel Erfolg Martin)
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mai 05, 2020
10:38 PM
Hi Martin. Ich denke, du wirst nicht um ein wenig Mathe drum rum kommen: https://rechneronline.de/pi/kegelstumpf.php Du brauchst die Abwicklung eines Kegelstumpfes. Gruß Andreas
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avr. 30, 2020
12:42 AM
Hi! I have a problem with the guides. Or better: the edges of a picture. This picture (or graphic) is in a frame and I want to scale it manually. But the edges are white! One can´t see it on a brighter background. Can I change the color?
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mars 09, 2020
04:23 AM
Oh, it was nearly proper. I added a supplementary condition in the line: if(allGraphicsArray[t].parent.itemLayer.visible === true && allGraphicsArray[t].constructor.name === "PDF"){ ... } There is a psd-Image in one of the documents wich causes the error. Don´t know why. It´s not embeded. Because I´m only looking for pdfs, I sorted all others out now. Anway, thanks.
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mars 09, 2020
02:49 AM
Hi Jongware. If YOU are the one with this opinion, wow! No chance of finding a solution. 🙂 🙂 Not the worst of my problems. But I have to work with the open documents. It's part of my workflow. The following script is almost what I need. But at some point there was an error: "null is not an object": var myDoc = app.documents;
var docsLength = myDoc.length;
myArray= new Array();
mySortedDocs= new Array();
myPages = new Array();
mySortedIDs= new Array();
mySortedDocsName = new Array();
allGraphicsArray = new Array();
myGraphicsArray = new Array();
//////////////////////////////////////////////// OUTER LOOP ////////////////////////////////////////////////
for (i=0; i<docsLength; i++) {
mySortedDocs.push(myDoc[i]);
var pages = myDoc[i].pages;
//////////////////////////////////////////////// INNER LOOP ////////////////////////////////////////////////
for (n=0; n<pages.length;n++) {
if(pages.length > 0) {
myPages.push(mySortedDocs[i].pages[n]);
allGraphicsArray = mySortedDocs[i].pages[n].allGraphics;
var graphLength = mySortedDocs[i].pages[n].allGraphics.length;
//////////////////////////////////////////////// CORE LOOP ////////////////////////////////////////////////
for(t=0;t<graphLength;t++) {
if(allGraphicsArray[t].parent.itemLayer.visible === true){
//alert(mySortedDocs[i].name + " " + pages[n].name + " " + allGraphicsArray[t].itemLink.name);
var objName = allGraphicsArray[t].itemLink.name;
if(objName === "SF_Icon_72h_2020.ai"){
myGraphicsArray.push(allGraphicsArray[t]);
}//IF-END
}
}// FOR-END
////////////////////////////////////////////////////////////////////////////////////////////////
}// IF-END
} // FOR-END
////////////////////////////////////////////////////////////////////////////////////////////////
} // FOR-END
////////////////////////////////////////////////////////////////////////////////////////////////
alert(myGraphicsArray.length);
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mars 05, 2020
06:17 AM
It´s a good hint. Thanks But not the answer. 🙂 Do you know why in a sorted array the first object isn´t the one with the name 01_... ? 😞
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mars 05, 2020
05:46 AM
I do not have the anwer yet, but a solution to sort the opened documents ascending: var myDoc = app.documents;
var docsLength = myDoc.length;
myArray= new Array();
mySortedDocs= new Array();
mySortedIDs= new Array();
for (i=0; i<docsLength; i++) {
var myDoc = app.documents;
var docsLength = myDoc.length;
myArray= new Array();
mySortedDocs= new Array();
mySortedIDs= new Array();
for (i=0; i<docsLength; i++) {
mySortedDocs.push(myDoc[i]);
//~ mySortedIDs.push(myDoc[i].index);
}
mySortedDocs.sort(function (a) {return (a.name)});
//~ mySortedIDs.sort();
for (i=0; i<docsLength; i++) {
myArray.push(mySortedDocs[i].name + ": has the Index " + mySortedDocs[i].index + "\r");//
}
alert(myArray.join("\r")); But why does the list start with second document, with the index 1? The name of all the document starts witz a number (01_, 02_, 03_). Newerthenless it starts with 02_.... .indd! The document 01_.... .indd ist the last one in the list.
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mars 05, 2020
04:16 AM
var myDoc = app.documents; app.activeDocument = myDoc[1]; Okay, I found that the object with key 1 is not necessarily the second document. Hmmm....
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mars 05, 2020
04:06 AM
Hi! e.g. I have a book with 15 Documents. I mark the docs in the book-palette and open them with a double click. When they are all opened I want to ask how many pages each of them has. The script works, that´s not the problem. My question is: In what order do the documents open? In the list that I have issued, they are mixed up. Why?
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mars 05, 2020
12:42 AM
So simple! (if one knows the answer) But illogical for me, because join means to attach, to bind, to connect. Not to devide, to separate. 😞 Thank you Uwe
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mars 04, 2020
07:54 AM
Hello! How one can separate the contents with split() or something else? In the following case it doesn´t work. Okay, I think it´s becausse it is a multidimensional array. Isn´t it? var string1 = "first string"; var string2 = "second string"; var string3 = "third string"; var string4 = "fourth string"; var string5 = "fifth string"; var x = new Array(); x = [string1, string2, string3, string4, string5]; alert(x.split()); What I want to have is an alert-output like: first string second string third string fourth string fifth string
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févr. 26, 2020
12:00 AM
Thanx Bob, thankx Brian. My problem was the absolute Position on both sides of a double sided document. But I found the solution, it's the red line: var myDoc = app.activeDocument; var theSelection = myDoc.selection; var numSelection = theSelection.length; app.doScript(auswahlCheck, ScriptLanguage.JAVASCRIPT, undefined, UndoModes.ENTIRE_SCRIPT, "Process Table"); function auswahlCheck(){ objArray = []; for (i=0; i<numSelection; i++){objArray.push(theSelection[i]);} objArray.sort(function (a, b) {return Number(a.geometricBounds[0]) - Number(b.geometricBounds[0]);}); for (i=0; i<numSelection; i++) { var myObj = objArray[i]; var myPage = theSelection[i].parentPage; var hoehe = myObj.geometricBounds[2]-myObj.geometricBounds[0]; var breite = myObj.geometricBounds[3]-myObj.geometricBounds[1]; if (i==0) {var y1 = myPage.bounds[0]+myPage.marginPreferences.top;} else if (i>0) { var vorherigesObj = objArray[i-1]; var y1 = vorherigesObj.geometricBounds[2]+1.764 ; } var x1 = myPage.bounds[1]+myPage.marginPreferences.left; var y2 = y1+ hoehe; if (i==2) {var y2 = myPage.bounds[2]-myPage.marginPreferences.bottom} var x2 = myPage.bounds[3]-myPage.marginPreferences.right; myObj.geometricBounds= [y1,x1,y2,x2]; } }
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févr. 25, 2020
01:15 AM
Hi! it's actually an easy task, obviously not for me...
I have a spread with facing pages. There are top-pargins, bottom-margins, left and right-margins. But the left and right ones should be inner- and outer-margins. Whenever I want to adjust the size and position of an object to the margins, the wide becomes 0. The reason is, that: myPage.marginPreferences.top; is not (e.g.) 200 mm but 10 mm (from the right side of the page). So you have 10 for the geometricBounds[1] (its the relative coordinate for x1) and 10 for geometricBounds[3] (the relative coordinate for x2). But I need the absolute values from the left edge (0mm) for both the left side page and the right side page. Is that doable?
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janv. 13, 2020
07:26 AM
1 Vote positif
Hi Barb. Unfortunately I have an iMac. But thanks
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janv. 09, 2020
06:35 AM
Yes, I fear it will remain with the traditional solution 😞
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janv. 09, 2020
06:24 AM
Hello Jeffrey. A saved query is not a solution for me. There are e.g. three forms of one type with different contents. I would like to have two of them with and one without effect. There is no automatic search and replace function for this.
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janv. 09, 2020
06:02 AM
Hi! Does anybody know, if one can use shortcuts for the options of searching/replaceing (find next, change, change all, change/find)? I´m going to change a pretty lot of objects in a large document (delete the shadow-effect) and the only way to decide wich one have to be changed is a visual controll, one by one. It would be helpful to use both hands :). Thanks in advance
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nov. 16, 2019
10:05 AM
Good idea. 🙂
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nov. 14, 2019
07:54 AM
1 Vote positif
Hi Jongware I didn´t say Mark´s script doesn´t help. 🙂 I've meant, I would prefer not to need to use a script, but work with the tool "index", that should have that function.
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nov. 13, 2019
11:51 PM
Hi Uwe. Nee, eigentlich nicht. Das war ein Versehen. Sollte schon alle fortlaufenden Seitenzahlen mit einem Bindestrich versehen. Die Sache ist, ich habe keinen Bock mehr, ehrlich gesagt, Defizite in der InDesign-Programmierung mit einem Script zu lösen. Das wäre im Grunde genommen ein elementarer Bestandteil des Index. Zumindest optional einstellbar. Werde aber dann wohl nicht um einen Script herum kommen. Danke Dir.
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