>ANY OTHER SUGGESTIONS Control your caps. Peter ... View more

>CS3 cannot find them with grep Try this: search for [\x{0401}-\x{0491}] and set Rusian in the Change Format pane. That should doe what you want. Peter ... View more

>The real question is: is there some preference somewhere that makes I don't think so, certainly have never come across it. Peter ... View more

That's right: >text.applyParagraphStyle(someStyle, false); applies the paragraph style and doesn't remove overrides. Use "true" to delete the overrides, in which case you get the same results as >text.appliedParagraphStyle = someStyle Peter ... View more

Thanks Gerald. Peter ... View more

The code you showed cannot work. First you need to create a preset as follows: if (app.documentPresets.item ("Amit") == null) { with(app.documentPresets.add()) { name = "Amit"; pageHeight = "30p0"; // rest of the preset definitions } } Then, when you want to create a new document with those presets, you do this: app.documents.add ({DocumentPreset: "Amit"}) Peter ... View more

Darwin, True -- I forgot about deeply embedded items. Peter ... View more

>I stand by my observation that the object model in ESTK is inadequate for learning JS for InDesign. Everybody, including Adobe's engineers, would agree with that. They would also say that the object model in the ESTK is a reference, not a learning tool. For learning about the object model you need other resources. There are several scripting guides around -- see Adobe's web site. Peter ... View more

Make sure that in the top left of your edit window it says "Adobe InDesign CS3". You probably see "ExtendScript Toolkit 2" there now. To avoid this in future, make a habit of including this line at the beginning of every script: #target indesign As to your two questions, (1) there isn't any; (2) depends on what you want. Press Shift+Cmd/Ctrl+D to display it on screen, or use >app.activeDocument.links.everyItem().name.join('\r') to print all link names in ESTK's console. Peter ... View more

Just add this line after the four that you have: app.activeDocument.layers.item('Layer 1').remove(); Peter ... View more

To tell you the truth, I haven't a clue what an assignment is. But anyway, if you check the scripting reference -- which you will do if you're new at scripting InDesign -- you'll see that there is a collection called "assignments". The first assignment in that collection is addressed as "assignments[0]", the second as "assignment[1]", etc. So what you actually need is >if (app.activeDocument.assignments[0].userName == "johnny") to check the username of the first assignment. Peter ... View more

#target indesign app.activeDocument.layers.add ({name: 'border', layerColor: UIColors.blue}); app.activeDocument.layers.add ({name: 'copy', layerColor: UIColors.green}); app.activeDocument.layers.add ({name: 'graphics', layerColor: UIColors.red}); app.activeDocument.layers.add ({name: 'background', layerColor: UIColors.lightBlue}); Peter ... View more

"To" refers to where the group is supposed to be duplicated. This is a page, spread, or layer. "By" is an array stating the offset of the duplicated group. If you leave it out, the group will be duplicated at the same position. Example: >myGroup(1).Duplicate (MyDestinationPage, [30,30]) Peter ... View more

For the current document you need >if (app.activeDocument.assignment.userName == "johnny") ... View more

If userName is a property you wouldn't expect the parentheses. ... View more

Well, you don't really have to label anything beforehand. What you need to do is this: find all job numbers, then for each jobnumber, get the page it's on and export it. The script below does that (assuming that text frames in the bleed area behave the same as any other text frame). It doesn't do any error-checking, it's just something to start off with. Peter destination_folder = '/d/'; doc = app.activeDocument; doc.sections.everyItem().includeSectionPrefix = false; app.findTextPreferences = null; app.findTextPreferences.findWhat = 'pnxx-^9^9^9^9'; found = doc.findText(); for (i = 0; i < found.length; i++ ) { f = File (destination_folder + found.contents + '.pdf'); app.pdfExportPreferences.pageRange = found.parentTextFrames[0].parent.name; doc.exportFile (ExportFormat.pdfType, f, false); } ... View more

Stefano, You'll need to do the flowing yourself. I use the function below for that. It keeps adding pages and text frames, linking each new text frame to the previous thread, as long as the last added text frame overflows. It may not work for you as it is, but it gets you going. Peter flow (app.activeDocument) function flow (doc) { var m = doc.pages[0].marginPreferences; var gbounds = [m.top, m.left, doc.documentPreferences.pageHeight - m.bottom, doc.documentPreferences.pageWidth - m.right]; doc.viewPreferences.rulerOrigin = RulerOrigin.pageOrigin; while (doc.pages[-1].textFrames[0].overflows) { var tf = doc.pages.add().textFrames.add ({geometricBounds: gbounds}); tf.previousTextFrame = doc.pages[-2].textFrames[0]; } } ... View more

What about >myLink.parent.parent.parent.name Peter ... View more

Fred, When you've got a handle on something inside an inline it's not so hard to figure out whether or not you're in an inline; that was covered earlier in this thread. Figuring out whether an object that declares itself to be a character is really that (i.e. its contents is a single letter) or an inline takes some less elegant methods. I know of two. (1) Check the character's unicode value: if it's an inline, unicode value FFFC is returned. Any other unicode values mean it's a real character (or likely, anyway; it could also be a special character I guess). (2) A character with geometricBounds must be an inline; a real character has no geometricBounds, so testing for that will produce an error. The latter test would be something like this: try { app.selection[0].textFrames[0].geometricBounds alert ("It's an inline.") } catch(_) { alert ("It's a character") } with a character (either a plain one or an inline) selected. Peter ... View more

Thanks, X and Harbs, for the explanation. ... View more

Maybe. But could you remind us what exactly you're trying to accomplish? ... View more

No, but >myFindsB[0].parent.characters[myIndex].index should. ... View more

Not at all. It returns the index of the first character of myFindsB[0], measered from the beginning of the story in which it occurs. ... View more

>What do I have to do to have it return true? What the comparison tells you if you get true is that myFindsB[0] is the first word in its story. What you have to do then I don't know. Peter ... View more

xbytor, > There is one very good reason (for me, at least) to not use x.constructor.name So there are circumstances in which constructor.name doesn't work. But there are also circumstances where instanceof doesn't work, though i can't remember now which they were. It'd be nice if there is one that always works! Peter ... View more

>myFindsB[0].characters[0].index is the index the first character of myFindsB relative to the beginning of the story. >myFindsB[0].parent.characters[myIndex] is the index of the first character of the story, because myFindsB[0].parent is a story. Peter ... View more

We're writing at cross-purposes too! ... View more

>How do you get the last character in myFinds relative to the story? myFindsB[0].characters[-1].index Peter ... View more

Fred, If you try >if(myFindsB[0].parent.characters[myIndex+1].parentTextFrames[0].parent instanceof Character) when myIndex is the last position in a story, then you would get an error. >does there have to be a == true after instanceof Character No, == isn't used with instanceof. Peter ... View more

We were writing at cross-purposes... ... View more