"Visible If" not working

Question

Hi! People,There's a boolean input node having indentifer name as "bevel_type"There's a second input value node. I want input value node to be visible when "bevel_type" is true.I'm finding such a simple stuff difficult.I used this as guide:Visible if: control visibility of inputs, outputs and parameters | Substance 3D Designer (adobe.com) The expression I entered in the "Visible If" of input value node is: input["bevel_type"] == Trueinput.bevel_type == True A) There's no way to add line_break/ENTER/Return in "Visible If" field as shown in the documentation link above.B) It's just giving me yellow exclamation.

davescm · Accepted Answer

Here's the screenshot:I want to control the visibility of two inputs (Bevel In and Bevel Out) using the bevel_type input (boolean type).Thanks for the screenshot, now I see the difference between what we were doing.As far as I am aware, Visible If has to reference an input parameter (in the input parameters section) rather than an input value node. Dave

davescm · Answer

HiIf the identifier for your Boolean Input parameter is bevel_type You just need input.bevel_type == true Note the spaces before and after == and also lowercase true This looks like a Substance Designer question so I will move the thread to that forum Dave

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