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Folder.commonFiles.path

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When I have the following line in a FrameMaker Script:

Alert(Folder.commonFiles.path)

I get the following:

I would have expected:

c:/Program Files(x86)/Common Files

Scripting

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Klaus GöbelCorrect answer

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To summarize:

var oFile = Folder.commonFiles.path;
$.writeln(oFile);
var oFile = File.decode(Folder.commonFiles.path);
$.writeln(oFile);
var oFile = File.decode(Folder.commonFiles);
$.writeln(oFile);
var oFile = File.decode(Folder.commonFiles.fsName);
$.writeln(oFile);

leads to

/c/Program%20Files%20(x86)

/c/Program Files (x86)

/c/Program Files (x86)/Common Files

C:\Program Files (x86)\Common Files

So you can pick your solution, that fits for you

Klaus GöbelCorrect answer

Legend

To summarize:

var oFile = Folder.commonFiles.path;
$.writeln(oFile);
var oFile = File.decode(Folder.commonFiles.path);
$.writeln(oFile);
var oFile = File.decode(Folder.commonFiles);
$.writeln(oFile);
var oFile = File.decode(Folder.commonFiles.fsName);
$.writeln(oFile);

leads to

/c/Program%20Files%20(x86)

/c/Program Files (x86)

/c/Program Files (x86)/Common Files

C:\Program Files (x86)\Common Files

So you can pick your solution, that fits for you

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Legend

Klaus, there is no need to use File.decode() on line 7, fsName already does that...

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Legend

Hi Ian,

I know. That is only to show all different ways, results and syntaxes.

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Community Expert

Community Expert

Or leave off the .path property. The commonFiles property is already a "folder". When you ask for .path, it gives you the next folder up the tree.

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www.frameexpert.com

Legend

But that would just return the Object type of 'Folder'...

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Community Expert

Community Expert

I am not exactly sure what the original poster is looking for. I thought he was wondering why "Common Files" got dropped, but maybe I misunderstood.

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www.frameexpert.com

Legend

You can get the expected result using fsName as follows:

Alert(Folder.commonFiles.fsName);

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